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leetcode-problemset/leetcode-cn/problem (Chinese)/查找库存不平衡的店铺 [find-stores-with-inventory-imbalance].html
2025-08-10 21:35:14 +08:00

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<p>表:<code>stores</code></p>
<pre>
+-------------+---------+
| Column Name | Type |
+-------------+---------+
| store_id | int |
| store_name | varchar |
| location | varchar |
+-------------+---------+
store_id 是这张表的唯一主键。
每一行包含有关商店及其位置的信息。
</pre>
<p>表:<code>inventory</code></p>
<pre>
+-------------+---------+
| Column Name | Type |
+-------------+---------+
| inventory_id| int |
| store_id | int |
| product_name| varchar |
| quantity | int |
| price | decimal |
+-------------+---------+
inventory_id 是这张表的唯一主键。
每一行代表特定商店中某一特定产品的库存情况。
</pre>
<p>编写一个解决方案来查找库存不平衡的商店 - 即最贵商品的库存比最便宜商品少的商店。</p>
<ul>
<li>对于每个商店,识别 <strong>最贵的商品</strong>(最高价格)及其数量,如果有多个最贵的商品则选取数量最多的一个。</li>
<li>对于每个商店,识别 <strong>最便宜的商品</strong>(最低价格)及其数量,如果有多个最便宜的物品则选取数量最多的一个。</li>
<li>如果最贵商品的数量 <strong>少于</strong> 最便宜商品的数量,则商店存在库存不平衡。</li>
<li>按(最便宜商品的数量/最贵商品的数量)计算 <strong>不平衡比</strong></li>
<li>不平衡比&nbsp;<strong>舍入到 2 位</strong>&nbsp;小数</li>
<li>结果只包含&nbsp;<strong>至少有</strong><strong> </strong><code>3</code>&nbsp;<strong>个不同商品</strong> 的店铺</li>
</ul>
<p>返回结果表以不平衡比率降序排列,然后按商店名称升序排列。</p>
<p>结果格式如下所示。</p>
<p>&nbsp;</p>
<p><strong class="example">示例:</strong></p>
<div class="example-block">
<p><strong>输入:</strong></p>
<p>stores 表:</p>
<pre class="example-io">
+----------+----------------+-------------+
| store_id | store_name | location |
+----------+----------------+-------------+
| 1 | Downtown Tech | New York |
| 2 | Suburb Mall | Chicago |
| 3 | City Center | Los Angeles |
| 4 | Corner Shop | Miami |
| 5 | Plaza Store | Seattle |
+----------+----------------+-------------+
</pre>
<p>inventory 表:</p>
<pre class="example-io">
+--------------+----------+--------------+----------+--------+
| inventory_id | store_id | product_name | quantity | price |
+--------------+----------+--------------+----------+--------+
| 1 | 1 | Laptop | 5 | 999.99 |
| 2 | 1 | Mouse | 50 | 19.99 |
| 3 | 1 | Keyboard | 25 | 79.99 |
| 4 | 1 | Monitor | 15 | 299.99 |
| 5 | 2 | Phone | 3 | 699.99 |
| 6 | 2 | Charger | 100 | 25.99 |
| 7 | 2 | Case | 75 | 15.99 |
| 8 | 2 | Headphones | 20 | 149.99 |
| 9 | 3 | Tablet | 2 | 499.99 |
| 10 | 3 | Stylus | 80 | 29.99 |
| 11 | 3 | Cover | 60 | 39.99 |
| 12 | 4 | Watch | 10 | 299.99 |
| 13 | 4 | Band | 25 | 49.99 |
| 14 | 5 | Camera | 8 | 599.99 |
| 15 | 5 | Lens | 12 | 199.99 |
+--------------+----------+--------------+----------+--------+
</pre>
<p><strong>输出:</strong></p>
<pre class="example-io">
+----------+----------------+-------------+------------------+--------------------+------------------+
| store_id | store_name | location | most_exp_product | cheapest_product | imbalance_ratio |
+----------+----------------+-------------+------------------+--------------------+------------------+
| 3 | City Center | Los Angeles | Tablet | Stylus | 40.00 |
| 1 | Downtown Tech | New York | Laptop | Mouse | 10.00 |
| 2 | Suburb Mall | Chicago | Phone | Case | 25.00 |
+----------+----------------+-------------+------------------+--------------------+------------------+
</pre>
<p><strong>解释:</strong></p>
<ul>
<li><strong>Downtown Tech (store_id = 1)</strong>
<ul>
<li>最贵的商品:笔记本($999.99)数量为 5</li>
<li>最便宜的商品:鼠标($19.99)数量为 50</li>
<li>库存不平衡5 &lt; 50贵的商品的库存更少</li>
<li>不平衡比50 / 5 = 10.00</li>
<li>有 4&nbsp;件商品(≥ 3所以满足要求</li>
</ul>
</li>
<li><strong>Suburb Mall (store_id = 2)</strong>
<ul>
<li>最贵的商品:手机($699.99)数量为 3</li>
<li>最便宜的商品:保护壳($15.99数量为75</li>
<li>库存不平衡3 &lt; 75贵的商品的库存更少</li>
<li>不平衡比75 / 3 = 25.00</li>
<li>有 4&nbsp;件商品(≥ 3所以满足要求</li>
</ul>
</li>
<li><strong>City Center (store_id = 3)</strong>
<ul>
<li>最贵的商品:平板电脑($499.99)数量为 2</li>
<li>最便宜的商品:触控笔($29.99)数量为 80</li>
<li>不平衡比2 &lt; 80贵的商品的库存更少</li>
<li>不平衡比80 / 2 = 40.00</li>
<li>有 3 件商品(≥ 3所以满足要求</li>
</ul>
</li>
<li><strong>未包含的商店:</strong>
<ul>
<li>Corner Shopstore_id = 4只有两件商品手表手环- 不满足最少 3 件商品的要求</li>
<li>Plaza Storestore_id = 5只有两件商品相机镜头- 不满足最少 3 件商品的要求</li>
</ul>
</li>
</ul>
<p>结果表按不平衡比降序排序,然后以商店名升序排序。</p>
</div>