mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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189 lines
29 KiB
JSON
189 lines
29 KiB
JSON
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"questionId": "2493",
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"questionFrontendId": "2415",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1827109,
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"title": "Reverse Odd Levels of Binary Tree",
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"titleSlug": "reverse-odd-levels-of-binary-tree",
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"content": "<p>Given the <code>root</code> of a <strong>perfect</strong> binary tree, reverse the node values at each <strong>odd</strong> level of the tree.</p>\n\n<ul>\n\t<li>For example, suppose the node values at level 3 are <code>[2,1,3,4,7,11,29,18]</code>, then it should become <code>[18,29,11,7,4,3,1,2]</code>.</li>\n</ul>\n\n<p>Return <em>the root of the reversed tree</em>.</p>\n\n<p>A binary tree is <strong>perfect</strong> if all parent nodes have two children and all leaves are on the same level.</p>\n\n<p>The <strong>level</strong> of a node is the number of edges along the path between it and the root node.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/07/28/first_case1.png\" style=\"width: 626px; height: 191px;\" />\n<pre>\n<strong>Input:</strong> root = [2,3,5,8,13,21,34]\n<strong>Output:</strong> [2,5,3,8,13,21,34]\n<strong>Explanation:</strong> \nThe tree has only one odd level.\nThe nodes at level 1 are 3, 5 respectively, which are reversed and become 5, 3.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/07/28/second_case3.png\" style=\"width: 591px; height: 111px;\" />\n<pre>\n<strong>Input:</strong> root = [7,13,11]\n<strong>Output:</strong> [7,11,13]\n<strong>Explanation:</strong> \nThe nodes at level 1 are 13, 11, which are reversed and become 11, 13.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> root = [0,1,2,0,0,0,0,1,1,1,1,2,2,2,2]\n<strong>Output:</strong> [0,2,1,0,0,0,0,2,2,2,2,1,1,1,1]\n<strong>Explanation:</strong> \nThe odd levels have non-zero values.\nThe nodes at level 1 were 1, 2, and are 2, 1 after the reversal.\nThe nodes at level 3 were 1, 1, 1, 1, 2, 2, 2, 2, and are 2, 2, 2, 2, 1, 1, 1, 1 after the reversal.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the tree is in the range <code>[1, 2<sup>14</sup>]</code>.</li>\n\t<li><code>0 <= Node.val <= 10<sup>5</sup></code></li>\n\t<li><code>root</code> is a <strong>perfect</strong> binary tree.</li>\n</ul>\n",
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"translatedTitle": "反转二叉树的奇数层",
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"translatedContent": "<p>给你一棵 <strong>完美</strong> 二叉树的根节点 <code>root</code> ，请你反转这棵树中每个 <strong>奇数</strong> 层的节点值。</p>\n\n<ul>\n\t<li>例如，假设第 3 层的节点值是 <code>[2,1,3,4,7,11,29,18]</code> ，那么反转后它应该变成 <code>[18,29,11,7,4,3,1,2]</code> 。</li>\n</ul>\n\n<p>反转后，返回树的根节点。</p>\n\n<p><strong>完美</strong> 二叉树需满足：二叉树的所有父节点都有两个子节点，且所有叶子节点都在同一层。</p>\n\n<p>节点的 <strong>层数</strong> 等于该节点到根节点之间的边数。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/07/28/first_case1.png\" style=\"width: 626px; height: 191px;\" />\n<pre>\n<strong>输入：</strong>root = [2,3,5,8,13,21,34]\n<strong>输出：</strong>[2,5,3,8,13,21,34]\n<strong>解释：</strong>\n这棵树只有一个奇数层。\n在第 1 层的节点分别是 3、5 ，反转后为 5、3 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/07/28/second_case3.png\" style=\"width: 591px; height: 111px;\" />\n<pre>\n<strong>输入：</strong>root = [7,13,11]\n<strong>输出：</strong>[7,11,13]\n<strong>解释：</strong> \n在第 1 层的节点分别是 13、11 ，反转后为 11、13 。 \n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>root = [0,1,2,0,0,0,0,1,1,1,1,2,2,2,2]\n<strong>输出：</strong>[0,2,1,0,0,0,0,2,2,2,2,1,1,1,1]\n<strong>解释：</strong>奇数层由非零值组成。\n在第 1 层的节点分别是 1、2 ，反转后为 2、1 。\n在第 3 层的节点分别是 1、1、1、1、2、2、2、2 ，反转后为 2、2、2、2、1、1、1、1 。\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>树中的节点数目在范围 <code>[1, 2<sup>14</sup>]</code> 内</li>\n\t<li><code>0 <= Node.val <= 10<sup>5</sup></code></li>\n\t<li><code>root</code> 是一棵 <strong>完美</strong> 二叉树</li>\n</ul>\n",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($val = 0, $left = null, $right = null) {\n * $this->val = $val;\n * $this->left = $left;\n * $this->right = $right;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param TreeNode $root\n * @return TreeNode\n */\n function reverseOddLevels($root) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func reverseOddLevels(_ root: TreeNode?) -> TreeNode? {\n\n }\n}",
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"Try to solve recursively for each level independently.",
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"While performing a depth-first search, pass the left and right nodes (which should be paired) to the next level. If the current level is odd, then reverse their values, or else recursively move to the next level."
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