{ "data": { "question": { "questionId": "2493", "questionFrontendId": "2415", "categoryTitle": "Algorithms", "boundTopicId": 1827109, "title": "Reverse Odd Levels of Binary Tree", "titleSlug": "reverse-odd-levels-of-binary-tree", "content": "

Given the root of a perfect binary tree, reverse the node values at each odd level of the tree.

\n\n\n\n

Return the root of the reversed tree.

\n\n

A binary tree is perfect if all parent nodes have two children and all leaves are on the same level.

\n\n

The level of a node is the number of edges along the path between it and the root node.

\n\n

 

\n

Example 1:

\n\"\"\n
\nInput: root = [2,3,5,8,13,21,34]\nOutput: [2,5,3,8,13,21,34]\nExplanation: \nThe tree has only one odd level.\nThe nodes at level 1 are 3, 5 respectively, which are reversed and become 5, 3.\n
\n\n

Example 2:

\n\"\"\n
\nInput: root = [7,13,11]\nOutput: [7,11,13]\nExplanation: \nThe nodes at level 1 are 13, 11, which are reversed and become 11, 13.\n
\n\n

Example 3:

\n\n
\nInput: root = [0,1,2,0,0,0,0,1,1,1,1,2,2,2,2]\nOutput: [0,2,1,0,0,0,0,2,2,2,2,1,1,1,1]\nExplanation: \nThe odd levels have non-zero values.\nThe nodes at level 1 were 1, 2, and are 2, 1 after the reversal.\nThe nodes at level 3 were 1, 1, 1, 1, 2, 2, 2, 2, and are 2, 2, 2, 2, 1, 1, 1, 1 after the reversal.\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "反转二叉树的奇数层", "translatedContent": "

给你一棵 完美 二叉树的根节点 root ，请你反转这棵树中每个 奇数 层的节点值。

\n\n\n\n

反转后，返回树的根节点。

\n\n

完美 二叉树需满足：二叉树的所有父节点都有两个子节点，且所有叶子节点都在同一层。

\n\n

节点的 层数 等于该节点到根节点之间的边数。

\n\n

 

\n\n

示例 1：

\n\"\"\n
\n输入：root = [2,3,5,8,13,21,34]\n输出：[2,5,3,8,13,21,34]\n解释：\n这棵树只有一个奇数层。\n在第 1 层的节点分别是 3、5 ，反转后为 5、3 。\n
\n\n

示例 2：

\n\"\"\n
\n输入：root = [7,13,11]\n输出：[7,11,13]\n解释： \n在第 1 层的节点分别是 13、11 ，反转后为 11、13 。 \n
\n\n

示例 3：

\n\n
\n输入：root = [0,1,2,0,0,0,0,1,1,1,1,2,2,2,2]\n输出：[0,2,1,0,0,0,0,2,2,2,2,1,1,1,1]\n解释：奇数层由非零值组成。\n在第 1 层的节点分别是 1、2 ，反转后为 2、1 。\n在第 3 层的节点分别是 1、1、1、1、2、2、2、2 ，反转后为 2、2、2、2、1、1、1、1 。\n
\n\n

 

\n\n

提示：

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0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root\n * @return {TreeNode}\n */\nvar reverseOddLevels = function(root) {\n\n};", "__typename": "CodeSnippetNode" }, { "lang": "TypeScript", "langSlug": "typescript", "code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * val: number\n * left: TreeNode | null\n * right: TreeNode | null\n * constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n * }\n */\n\nfunction reverseOddLevels(root: TreeNode | null): TreeNode | null {\n \n};", "__typename": "CodeSnippetNode" }, { "lang": "PHP", "langSlug": "php", "code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($val = 0, $left = null, $right = null) {\n * $this->val = $val;\n * $this->left = $left;\n * $this->right = $right;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param TreeNode $root\n * @return TreeNode\n */\n function reverseOddLevels($root) {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Swift", "langSlug": "swift", "code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func reverseOddLevels(_ root: TreeNode?) -> TreeNode? {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Kotlin", "langSlug": "kotlin", "code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun reverseOddLevels(root: TreeNode?): TreeNode? {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Dart", "langSlug": "dart", "code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * int val;\n * TreeNode? left;\n * TreeNode? right;\n * TreeNode([this.val = 0, this.left, this.right]);\n * }\n */\nclass Solution {\n TreeNode? reverseOddLevels(TreeNode? root) {\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Go", "langSlug": "golang", "code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc reverseOddLevels(root *TreeNode) *TreeNode {\n\n}", "__typename": "CodeSnippetNode" }, { "lang": "Ruby", "langSlug": "ruby", "code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {TreeNode} root\n# @return {TreeNode}\ndef reverse_odd_levels(root)\n\nend", "__typename": "CodeSnippetNode" }, { "lang": "Scala", "langSlug": "scala", "code": "/**\n * Definition for a binary tree node.\n * class TreeNode(_value: Int = 0, _left: TreeNode = null, _right: TreeNode = null) {\n * var value: Int = _value\n * var left: TreeNode = _left\n * var right: TreeNode = _right\n * }\n */\nobject Solution {\n def reverseOddLevels(root: TreeNode): TreeNode = {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Rust", "langSlug": "rust", "code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option>>,\n// pub right: Option>>,\n// }\n//\n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n pub fn reverse_odd_levels(root: Option>>) -> Option>> {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Racket", "langSlug": "racket", "code": "; Definition for a binary tree node.\n#|\n\n; val : integer?\n; left : (or/c tree-node? #f)\n; right : (or/c tree-node? #f)\n(struct tree-node\n (val left right) #:mutable #:transparent)\n\n; constructor\n(define (make-tree-node [val 0])\n (tree-node val #f #f))\n\n|#\n\n(define/contract (reverse-odd-levels root)\n (-> (or/c tree-node? #f) (or/c tree-node? #f))\n )", "__typename": "CodeSnippetNode" }, { "lang": "Erlang", "langSlug": "erlang", "code": "%% Definition for a binary tree node.\n%%\n%% -record(tree_node, {val = 0 :: integer(),\n%% left = null :: 'null' | #tree_node{},\n%% right = null :: 'null' | #tree_node{}}).\n\n-spec reverse_odd_levels(Root :: #tree_node{} | null) -> #tree_node{} | null.\nreverse_odd_levels(Root) ->\n .", "__typename": "CodeSnippetNode" }, { "lang": "Elixir", "langSlug": "elixir", "code": "# Definition for a binary tree node.\n#\n# defmodule TreeNode do\n# @type t :: %__MODULE__{\n# val: integer,\n# left: TreeNode.t() | nil,\n# right: TreeNode.t() | nil\n# }\n# defstruct val: 0, left: nil, right: nil\n# end\n\ndefmodule Solution do\n @spec reverse_odd_levels(root :: TreeNode.t | nil) :: TreeNode.t | nil\n def reverse_odd_levels(root) do\n \n end\nend", "__typename": "CodeSnippetNode" } ], "stats": "{\"totalAccepted\": \"11.3K\", \"totalSubmission\": \"16.1K\", \"totalAcceptedRaw\": 11341, \"totalSubmissionRaw\": 16073, \"acRate\": \"70.6%\"}", "hints": [ "Try to solve recursively for each level independently.", "While performing a depth-first search, pass the left and right nodes (which should be paired) to the next level. If the current level is odd, then reverse their values, or else recursively move to the next level." ], "solution": null, "status": null, "sampleTestCase": "[2,3,5,8,13,21,34]", "metaData": "{\n \"name\": \"reverseOddLevels\",\n \"params\": [\n {\n \"name\": \"root\",\n \"type\": \"TreeNode\"\n }\n ],\n \"return\": {\n \"type\": \"TreeNode\"\n }\n}", "judgerAvailable": true, "judgeType": "large", "mysqlSchemas": [], "enableRunCode": true, "envInfo": "{\"cpp\":[\"C++\",\"

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