leetcode-problemset/leetcode-cn/originData/process-restricted-friend-requests.json

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        "question": {
            "questionId": "2198",
            "questionFrontendId": "2076",
            "categoryTitle": "Algorithms",
            "boundTopicId": 1097255,
            "title": "Process Restricted Friend Requests",
            "titleSlug": "process-restricted-friend-requests",
            "content": "<p>You are given an integer <code>n</code> indicating the number of people in a network. Each person is labeled from <code>0</code> to <code>n - 1</code>.</p>\n\n<p>You are also given a <strong>0-indexed</strong> 2D integer array <code>restrictions</code>, where <code>restrictions[i] = [x<sub>i</sub>, y<sub>i</sub>]</code> means that person <code>x<sub>i</sub></code> and person <code>y<sub>i</sub></code> <strong>cannot </strong>become <strong>friends</strong>,<strong> </strong>either <strong>directly</strong> or <strong>indirectly</strong> through other people.</p>\n\n<p>Initially, no one is friends with each other. You are given a list of friend requests as a <strong>0-indexed</strong> 2D integer array <code>requests</code>, where <code>requests[j] = [u<sub>j</sub>, v<sub>j</sub>]</code> is a friend request between person <code>u<sub>j</sub></code> and person <code>v<sub>j</sub></code>.</p>\n\n<p>A friend request is <strong>successful </strong>if <code>u<sub>j</sub></code> and <code>v<sub>j</sub></code> can be <strong>friends</strong>. Each friend request is processed in the given order (i.e., <code>requests[j]</code> occurs before <code>requests[j + 1]</code>), and upon a successful request, <code>u<sub>j</sub></code> and <code>v<sub>j</sub></code> <strong>become direct friends</strong> for all future friend requests.</p>\n\n<p>Return <em>a <strong>boolean array</strong> </em><code>result</code>,<em> where each </em><code>result[j]</code><em> is </em><code>true</code><em> if the </em><code>j<sup>th</sup></code><em> friend request is <strong>successful</strong> or </em><code>false</code><em> if it is not</em>.</p>\n\n<p><strong>Note:</strong> If <code>u<sub>j</sub></code> and <code>v<sub>j</sub></code> are already direct friends, the request is still <strong>successful</strong>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 3, restrictions = [[0,1]], requests = [[0,2],[2,1]]\n<strong>Output:</strong> [true,false]\n<strong>Explanation:\n</strong>Request 0: Person 0 and person 2 can be friends, so they become direct friends. \nRequest 1: Person 2 and person 1 cannot be friends since person 0 and person 1 would be indirect friends (1--2--0).\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 3, restrictions = [[0,1]], requests = [[1,2],[0,2]]\n<strong>Output:</strong> [true,false]\n<strong>Explanation:\n</strong>Request 0: Person 1 and person 2 can be friends, so they become direct friends.\nRequest 1: Person 0 and person 2 cannot be friends since person 0 and person 1 would be indirect friends (0--2--1).\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 5, restrictions = [[0,1],[1,2],[2,3]], requests = [[0,4],[1,2],[3,1],[3,4]]\n<strong>Output:</strong> [true,false,true,false]\n<strong>Explanation:\n</strong>Request 0: Person 0 and person 4 can be friends, so they become direct friends.\nRequest 1: Person 1 and person 2 cannot be friends since they are directly restricted.\nRequest 2: Person 3 and person 1 can be friends, so they become direct friends.\nRequest 3: Person 3 and person 4 cannot be friends since person 0 and person 1 would be indirect friends (0--4--3--1).\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= n &lt;= 1000</code></li>\n\t<li><code>0 &lt;= restrictions.length &lt;= 1000</code></li>\n\t<li><code>restrictions[i].length == 2</code></li>\n\t<li><code>0 &lt;= x<sub>i</sub>, y<sub>i</sub> &lt;= n - 1</code></li>\n\t<li><code>x<sub>i</sub> != y<sub>i</sub></code></li>\n\t<li><code>1 &lt;= requests.length &lt;= 1000</code></li>\n\t<li><code>requests[j].length == 2</code></li>\n\t<li><code>0 &lt;= u<sub>j</sub>, v<sub>j</sub> &lt;= n - 1</code></li>\n\t<li><code>u<sub>j</sub> != v<sub>j</sub></code></li>\n</ul>\n",
            "translatedTitle": "处理含限制条件的好友请求",
            "translatedContent": "<p>给你一个整数 <code>n</code> ，表示网络上的用户数目。每个用户按从 <code>0</code> 到 <code>n - 1</code> 进行编号。</p>\n\n<p>给你一个下标从 <strong>0</strong> 开始的二维整数数组 <code>restrictions</code> ，其中 <code>restrictions[i] = [x<sub>i</sub>, y<sub>i</sub>]</code> 意味着用户 <code>x<sub>i</sub></code> 和用户 <code>y<sub>i</sub></code> <strong>不能</strong> 成为 <strong>朋友</strong> ，不管是 <strong>直接</strong> 还是通过其他用户 <strong>间接</strong> 。</p>\n\n<p>最初，用户里没有人是其他用户的朋友。给你一个下标从 <strong>0</strong> 开始的二维整数数组 <code>requests</code> 表示好友请求的列表，其中 <code>requests[j] = [u<sub>j</sub>, v<sub>j</sub>]</code> 是用户 <code>u<sub>j</sub></code> 和用户 <code>v<sub>j</sub></code> 之间的一条好友请求。</p>\n\n<p>如果 <code>u<sub>j</sub></code> 和 <code>v<sub>j</sub></code> 可以成为 <strong>朋友</strong> ，那么好友请求将会 <strong>成功</strong> 。每个好友请求都会按列表中给出的顺序进行处理（即，<code>requests[j]</code> 会在 <code>requests[j + 1]</code> 前）。一旦请求成功，那么对所有未来的好友请求而言， <code>u<sub>j</sub></code> 和 <code>v<sub>j</sub></code> 将会 <strong>成为直接朋友 。</strong></p>\n\n<p>返回一个 <strong>布尔数组</strong> <code>result</code> ，其中元素遵循此规则：如果第 <code>j</code> 个好友请求 <strong>成功</strong><em> </em>，那么 <code>result[j]</code><em> </em>就是<em> </em><code>true</code><em> </em>；否则，为<em> </em><code>false</code> 。</p>\n\n<p><strong>注意：</strong>如果 <code>u<sub>j</sub></code> 和 <code>v<sub>j</sub></code> 已经是直接朋友，那么他们之间的请求将仍然&nbsp;<strong>成功</strong> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 3, restrictions = [[0,1]], requests = [[0,2],[2,1]]\n<strong>输出：</strong>[true,false]\n<strong>解释：\n</strong>请求 0 ：用户 0 和 用户 2 可以成为朋友，所以他们成为直接朋友。 \n请求 1 ：用户 2 和 用户 1 不能成为朋友，因为这会使 用户 0 和 用户 1 成为间接朋友 (1--2--0) 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 3, restrictions = [[0,1]], requests = [[1,2],[0,2]]\n<strong>输出：</strong>[true,false]\n<strong>解释：</strong>\n请求 0 ：用户 1 和 用户 2 可以成为朋友，所以他们成为直接朋友。 \n请求 1 ：用户 0 和 用户 2 不能成为朋友，因为这会使 用户 0 和 用户 1 成为间接朋友 (0--2--1) 。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 5, restrictions = [[0,1],[1,2],[2,3]], requests = [[0,4],[1,2],[3,1],[3,4]]\n<strong>输出：</strong>[true,false,true,false]\n<strong>解释：\n</strong>请求 0 ：用户 0 和 用户 4 可以成为朋友，所以他们成为直接朋友。 \n请求 1 ：用户 1 和 用户 2 不能成为朋友，因为他们之间存在限制。\n请求 2 ：用户 3 和 用户 1 可以成为朋友，所以他们成为直接朋友。 \n请求 3 ：用户 3 和 用户 4 不能成为朋友，因为这会使 用户 0 和 用户 1 成为间接朋友 (0--4--3--1) 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= n &lt;= 1000</code></li>\n\t<li><code>0 &lt;= restrictions.length &lt;= 1000</code></li>\n\t<li><code>restrictions[i].length == 2</code></li>\n\t<li><code>0 &lt;= x<sub>i</sub>, y<sub>i</sub> &lt;= n - 1</code></li>\n\t<li><code>x<sub>i</sub> != y<sub>i</sub></code></li>\n\t<li><code>1 &lt;= requests.length &lt;= 1000</code></li>\n\t<li><code>requests[j].length == 2</code></li>\n\t<li><code>0 &lt;= u<sub>j</sub>, v<sub>j</sub> &lt;= n - 1</code></li>\n\t<li><code>u<sub>j</sub> != v<sub>j</sub></code></li>\n</ul>\n",
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                    "code": "class Solution(object):\n    def friendRequests(self, n, restrictions, requests):\n        \"\"\"\n        :type n: int\n        :type restrictions: List[List[int]]\n        :type requests: List[List[int]]\n        :rtype: List[bool]\n        \"\"\"",
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                    "code": "/**\n * @param {number} n\n * @param {number[][]} restrictions\n * @param {number[][]} requests\n * @return {boolean[]}\n */\nvar friendRequests = function(n, restrictions, requests) {\n\n};",
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                    "code": "class Solution {\n    func friendRequests(_ n: Int, _ restrictions: [[Int]], _ requests: [[Int]]) -> [Bool] {\n\n    }\n}",
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                    "code": "# @param {Integer} n\n# @param {Integer[][]} restrictions\n# @param {Integer[][]} requests\n# @return {Boolean[]}\ndef friend_requests(n, restrictions, requests)\n\nend",
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                    "code": "impl Solution {\n    pub fn friend_requests(n: i32, restrictions: Vec<Vec<i32>>, requests: Vec<Vec<i32>>) -> Vec<bool> {\n\n    }\n}",
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                "For each request, we could loop through all restrictions. Can you think of doing a check-in close to O(1)?",
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