mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
164 lines
21 KiB
JSON
164 lines
21 KiB
JSON
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"categoryTitle": "Algorithms",
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"title": "Maximize Consecutive Elements in an Array After Modification",
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"content": "<p>You are given a <strong>0-indexed</strong> array <code>nums</code> consisting of <strong>positive</strong> integers.</p>\n\n<p>Initially, you can increase the value of <strong>any</strong> element in the array by <strong>at most</strong> <code>1</code>.</p>\n\n<p>After that, you need to select <strong>one or more</strong> elements from the final array such that those elements are <strong>consecutive</strong> when sorted in increasing order. For example, the elements <code>[3, 4, 5]</code> are consecutive while <code>[3, 4, 6]</code> and <code>[1, 1, 2, 3]</code> are not.<!-- notionvc: 312f8c5d-40d0-4cd1-96cc-9e96a846735b --></p>\n\n<p>Return <em>the <strong>maximum</strong> number of elements that you can select</em>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [2,1,5,1,1]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> We can increase the elements at indices 0 and 3. The resulting array is nums = [3,1,5,2,1].\nWe select the elements [<u><strong>3</strong></u>,<u><strong>1</strong></u>,5,<u><strong>2</strong></u>,1] and we sort them to obtain [1,2,3], which are consecutive.\nIt can be shown that we cannot select more than 3 consecutive elements.</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,4,7,10]\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> The maximum consecutive elements that we can select is 1.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= nums[i] <= 10<sup>6</sup></code></li>\n</ul>\n",
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"translatedTitle": "修改数组后最大化数组中的连续元素数目",
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"translatedContent": "<p>给你一个下标从 <strong>0</strong> 开始只包含 <strong>正</strong> 整数的数组 <code>nums</code> 。</p>\n\n<p>一开始,你可以将数组中 <strong>任意数量</strong> 元素增加 <strong>至多</strong> <code>1</code> 。</p>\n\n<p>修改后,你可以从最终数组中选择 <strong>一个或者更多</strong> 元素,并确保这些元素升序排序后是 <strong>连续</strong> 的。比方说,<code>[3, 4, 5]</code> 是连续的,但是 <code>[3, 4, 6]</code> 和 <code>[1, 1, 2, 3]</code> 不是连续的。<!-- notionvc: 312f8c5d-40d0-4cd1-96cc-9e96a846735b --></p>\n\n<p>请你返回 <strong>最多</strong> 可以选出的元素数目。</p>\n\n<p> </p>\n\n<p><strong class=\"example\">示例 1:</strong></p>\n\n<pre>\n<b>输入:</b>nums = [2,1,5,1,1]\n<b>输出:</b>3\n<b>解释:</b>我们将下标 0 和 3 处的元素增加 1 ,得到结果数组 nums = [3,1,5,2,1] 。\n我们选择元素 [<em><strong>3</strong></em>,<em><strong>1</strong></em>,5,<em><strong>2</strong></em>,1] 并将它们排序得到 [1,2,3] ,是连续元素。\n最多可以得到 3 个连续元素。</pre>\n\n<p><strong class=\"example\">示例 2:</strong></p>\n\n<pre>\n<b>输入:</b>nums = [1,4,7,10]\n<b>输出:</b>1\n<b>解释:</b>我们可以选择的最多元素数目是 1 。\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= nums[i] <= 10<sup>6</sup></code></li>\n</ul>\n",
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"Sort the array and try using dynamic programming.",
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"Let <code>dp[i]</code> be the length of the longest consecutive elements ending at element at index <code>i</code> in the sorted array."
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