You are given a 0-indexed array nums consisting of positive integers.
Initially, you can increase the value of any element in the array by at most 1.
After that, you need to select one or more elements from the final array such that those elements are consecutive when sorted in increasing order. For example, the elements [3, 4, 5] are consecutive while [3, 4, 6] and [1, 1, 2, 3] are not.
Return the maximum number of elements that you can select.
\n\n\n
Example 1:
\n\n\nInput: nums = [2,1,5,1,1]\nOutput: 3\nExplanation: We can increase the elements at indices 0 and 3. The resulting array is nums = [3,1,5,2,1].\nWe select the elements [3,1,5,2,1] and we sort them to obtain [1,2,3], which are consecutive.\nIt can be shown that we cannot select more than 3 consecutive elements.\n\n
Example 2:
\n\n\nInput: nums = [1,4,7,10]\nOutput: 1\nExplanation: The maximum consecutive elements that we can select is 1.\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 1051 <= nums[i] <= 106给你一个下标从 0 开始只包含 正 整数的数组 nums 。
一开始，你可以将数组中 任意数量 元素增加 至多 1 。
修改后，你可以从最终数组中选择 一个或者更多 元素，并确保这些元素升序排序后是 连续 的。比方说，[3, 4, 5] 是连续的，但是 [3, 4, 6] 和 [1, 1, 2, 3] 不是连续的。
请你返回 最多 可以选出的元素数目。
\n\n\n\n
示例 1：
\n\n\n输入：nums = [2,1,5,1,1]\n输出：3\n解释：我们将下标 0 和 3 处的元素增加 1 ，得到结果数组 nums = [3,1,5,2,1] 。\n我们选择元素 [3,1,5,2,1] 并将它们排序得到 [1,2,3] ，是连续元素。\n最多可以得到 3 个连续元素。\n\n
示例 2：
\n\n\n输入：nums = [1,4,7,10]\n输出：1\n解释：我们可以选择的最多元素数目是 1 。\n\n\n
\n\n
提示：
\n\n1 <= nums.length <= 1051 <= nums[i] <= 106dp[i] be the length of the longest consecutive elements ending at element at index i in the sorted array."
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