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leetcode-problemset/leetcode-cn/originData/divisible-and-non-divisible-sums-difference.json
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"categoryTitle": "Algorithms",
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"title": "Divisible and Non-divisible Sums Difference",
"titleSlug": "divisible-and-non-divisible-sums-difference",
"content": "<p>You are given positive integers <code>n</code> and <code>m</code>.</p>\n\n<p>Define two integers, <code>num1</code> and <code>num2</code>, as follows:</p>\n\n<ul>\n\t<li><code>num1</code>: The sum of all integers in the range <code>[1, n]</code> that are <strong>not divisible</strong> by <code>m</code>.</li>\n\t<li><code>num2</code>: The sum of all integers in the range <code>[1, n]</code> that are <strong>divisible</strong> by <code>m</code>.</li>\n</ul>\n\n<p>Return <em>the integer</em> <code>num1 - num2</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 10, m = 3\n<strong>Output:</strong> 19\n<strong>Explanation:</strong> In the given example:\n- Integers in the range [1, 10] that are not divisible by 3 are [1,2,4,5,7,8,10], num1 is the sum of those integers = 37.\n- Integers in the range [1, 10] that are divisible by 3 are [3,6,9], num2 is the sum of those integers = 18.\nWe return 37 - 18 = 19 as the answer.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 5, m = 6\n<strong>Output:</strong> 15\n<strong>Explanation:</strong> In the given example:\n- Integers in the range [1, 5] that are not divisible by 6 are [1,2,3,4,5], num1 is the sum of those integers = 15.\n- Integers in the range [1, 5] that are divisible by 6 are [], num2 is the sum of those integers = 0.\nWe return 15 - 0 = 15 as the answer.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 5, m = 1\n<strong>Output:</strong> -15\n<strong>Explanation:</strong> In the given example:\n- Integers in the range [1, 5] that are not divisible by 1 are [], num1 is the sum of those integers = 0.\n- Integers in the range [1, 5] that are divisible by 1 are [1,2,3,4,5], num2 is the sum of those integers = 15.\nWe return 0 - 15 = -15 as the answer.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n, m &lt;= 1000</code></li>\n</ul>\n",
"translatedTitle": "分类求和并作差",
"translatedContent": "<p>给你两个正整数 <code>n</code> 和 <code>m</code> 。</p>\n\n<p>现定义两个整数 <code>num1</code> 和 <code>num2</code> ,如下所示:</p>\n\n<ul>\n\t<li><code>num1</code>:范围 <code>[1, n]</code> 内所有 <strong>无法被 </strong><code>m</code><strong> 整除</strong> 的整数之和。</li>\n\t<li><code>num2</code>:范围 <code>[1, n]</code> 内所有 <strong>能够被 </strong><code>m</code><strong> 整除</strong> 的整数之和。</li>\n</ul>\n\n<p>返回整数 <code>num1 - num2</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>n = 10, m = 3\n<strong>输出:</strong>19\n<strong>解释:</strong>在这个示例中:\n- 范围 [1, 10] 内无法被 3 整除的整数为 [1,2,4,5,7,8,10] num1 = 这些整数之和 = 37 。\n- 范围 [1, 10] 内能够被 3 整除的整数为 [3,6,9] num2 = 这些整数之和 = 18 。\n返回 37 - 18 = 19 作为答案。\n</pre>\n\n<p><strong class=\"example\">示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>n = 5, m = 6\n<strong>输出:</strong>15\n<strong>解释:</strong>在这个示例中:\n- 范围 [1, 5] 内无法被 6 整除的整数为 [1,2,3,4,5] num1 = 这些整数之和 = 15 。\n- 范围 [1, 5] 内能够被 6 整除的整数为 [] num2 = 这些整数之和 = 0 。\n返回 15 - 0 = 15 作为答案。\n</pre>\n\n<p><strong class=\"example\">示例 3</strong></p>\n\n<pre>\n<strong>输入:</strong>n = 5, m = 1\n<strong>输出:</strong>-15\n<strong>解释:</strong>在这个示例中:\n- 范围 [1, 5] 内无法被 1 整除的整数为 [] num1 = 这些整数之和 = 0 。 \n- 范围 [1, 5] 内能够被 1 整除的整数为 [1,2,3,4,5] num2 = 这些整数之和 = 15 。\n返回 0 - 15 = -15 作为答案。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n, m &lt;= 1000</code></li>\n</ul>\n",
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