You are given positive integers n and m.
Define two integers, num1 and num2, as follows:
num1: The sum of all integers in the range [1, n] that are not divisible by m.num2: The sum of all integers in the range [1, n] that are divisible by m.Return the integer num1 - num2.
\n
Example 1:
\n\n\nInput: n = 10, m = 3\nOutput: 19\nExplanation: In the given example:\n- Integers in the range [1, 10] that are not divisible by 3 are [1,2,4,5,7,8,10], num1 is the sum of those integers = 37.\n- Integers in the range [1, 10] that are divisible by 3 are [3,6,9], num2 is the sum of those integers = 18.\nWe return 37 - 18 = 19 as the answer.\n\n\n
Example 2:
\n\n\nInput: n = 5, m = 6\nOutput: 15\nExplanation: In the given example:\n- Integers in the range [1, 5] that are not divisible by 6 are [1,2,3,4,5], num1 is the sum of those integers = 15.\n- Integers in the range [1, 5] that are divisible by 6 are [], num2 is the sum of those integers = 0.\nWe return 15 - 0 = 15 as the answer.\n\n\n
Example 3:
\n\n\nInput: n = 5, m = 1\nOutput: -15\nExplanation: In the given example:\n- Integers in the range [1, 5] that are not divisible by 1 are [], num1 is the sum of those integers = 0.\n- Integers in the range [1, 5] that are divisible by 1 are [1,2,3,4,5], num2 is the sum of those integers = 15.\nWe return 0 - 15 = -15 as the answer.\n\n\n
\n
Constraints:
\n\n1 <= n, m <= 1000给你两个正整数 n 和 m 。
现定义两个整数 num1 和 num2 ，如下所示：
num1：范围 [1, n] 内所有 无法被 m 整除 的整数之和。num2：范围 [1, n] 内所有 能够被 m 整除 的整数之和。返回整数 num1 - num2 。
\n\n
示例 1：
\n\n\n输入：n = 10, m = 3\n输出：19\n解释：在这个示例中：\n- 范围 [1, 10] 内无法被 3 整除的整数为 [1,2,4,5,7,8,10] ，num1 = 这些整数之和 = 37 。\n- 范围 [1, 10] 内能够被 3 整除的整数为 [3,6,9] ，num2 = 这些整数之和 = 18 。\n返回 37 - 18 = 19 作为答案。\n\n\n
示例 2：
\n\n\n输入：n = 5, m = 6\n输出：15\n解释：在这个示例中：\n- 范围 [1, 5] 内无法被 6 整除的整数为 [1,2,3,4,5] ，num1 = 这些整数之和 = 15 。\n- 范围 [1, 5] 内能够被 6 整除的整数为 [] ，num2 = 这些整数之和 = 0 。\n返回 15 - 0 = 15 作为答案。\n\n\n
示例 3：
\n\n\n输入：n = 5, m = 1\n输出：-15\n解释：在这个示例中：\n- 范围 [1, 5] 内无法被 1 整除的整数为 [] ，num1 = 这些整数之和 = 0 。 \n- 范围 [1, 5] 内能够被 1 整除的整数为 [1,2,3,4,5] ，num2 = 这些整数之和 = 15 。\n返回 0 - 15 = -15 作为答案。\n\n\n
\n\n
提示：
\n\n1 <= n, m <= 1000[1, n] is n * (n + 1) / 2 ."
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