leetcode-problemset/leetcode-cn/originData/minimum-total-space-wasted-with-k-resizing-operations.json

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            "categoryTitle": "Algorithms",
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            "title": "Minimum Total Space Wasted With K Resizing Operations",
            "titleSlug": "minimum-total-space-wasted-with-k-resizing-operations",
            "content": "<p>You are currently designing a dynamic array. You are given a <strong>0-indexed</strong> integer array <code>nums</code>, where <code>nums[i]</code> is the number of elements that will be in the array at time <code>i</code>. In addition, you are given an integer <code>k</code>, the <strong>maximum</strong> number of times you can <strong>resize</strong> the array (to<strong> any</strong> size).</p>\n\n<p>The size of the array at time <code>t</code>, <code>size<sub>t</sub></code>, must be at least <code>nums[t]</code> because there needs to be enough space in the array to hold all the elements. The <strong>space wasted</strong> at&nbsp;time <code>t</code> is defined as <code>size<sub>t</sub> - nums[t]</code>, and the <strong>total</strong> space wasted is the <strong>sum</strong> of the space wasted across every time <code>t</code> where <code>0 &lt;= t &lt; nums.length</code>.</p>\n\n<p>Return <em>the <strong>minimum</strong> <strong>total space wasted</strong> if you can resize the array at most</em> <code>k</code> <em>times</em>.</p>\n\n<p><strong>Note:</strong> The array can have <strong>any size</strong> at the start and does<strong> not </strong>count towards the number of resizing operations.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [10,20], k = 0\n<strong>Output:</strong> 10\n<strong>Explanation:</strong> size = [20,20].\nWe can set the initial size to be 20.\nThe total wasted space is (20 - 10) + (20 - 20) = 10.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [10,20,30], k = 1\n<strong>Output:</strong> 10\n<strong>Explanation:</strong> size = [20,20,30].\nWe can set the initial size to be 20 and resize to 30 at time 2. \nThe total wasted space is (20 - 10) + (20 - 20) + (30 - 30) = 10.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [10,20,15,30,20], k = 2\n<strong>Output:</strong> 15\n<strong>Explanation:</strong> size = [10,20,20,30,30].\nWe can set the initial size to 10, resize to 20 at time 1, and resize to 30 at time 3.\nThe total wasted space is (10 - 10) + (20 - 20) + (20 - 15) + (30 - 30) + (30 - 20) = 15.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 200</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>6</sup></code></li>\n\t<li><code>0 &lt;= k &lt;= nums.length - 1</code></li>\n</ul>\n",
            "translatedTitle": "K 次调整数组大小浪费的最小总空间",
            "translatedContent": "<p>你正在设计一个动态数组。给你一个下标从 <strong>0</strong>&nbsp;开始的整数数组&nbsp;<code>nums</code>&nbsp;，其中&nbsp;<code>nums[i]</code>&nbsp;是&nbsp;<code>i</code>&nbsp;时刻数组中的元素数目。除此以外，你还有一个整数 <code>k</code>&nbsp;，表示你可以 <strong>调整</strong>&nbsp;数组大小的 <strong>最多</strong>&nbsp;次数（每次都可以调整成 <strong>任意</strong>&nbsp;大小）。</p>\n\n<p><code>t</code>&nbsp;时刻数组的大小&nbsp;<code>size<sub>t</sub></code>&nbsp;必须大于等于&nbsp;<code>nums[t]</code>&nbsp;，因为数组需要有足够的空间容纳所有元素。<code>t</code>&nbsp;时刻 <strong>浪费的空间</strong>&nbsp;为&nbsp;<code>size<sub>t</sub> - nums[t]</code>&nbsp;，<strong>总</strong>&nbsp;浪费空间为满足&nbsp;<code>0 &lt;= t &lt; nums.length</code>&nbsp;的每一个时刻&nbsp;<code>t</code>&nbsp;浪费的空间&nbsp;<strong>之和</strong>&nbsp;。</p>\n\n<p>在调整数组大小不超过 <code>k</code>&nbsp;次的前提下，请你返回 <strong>最小总浪费空间</strong>&nbsp;。</p>\n\n<p><strong>注意：</strong>数组最开始时可以为&nbsp;<strong>任意大小</strong>&nbsp;，且&nbsp;<strong>不计入</strong>&nbsp;调整大小的操作次数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><b>输入：</b>nums = [10,20], k = 0\n<b>输出：</b>10\n<b>解释：</b>size = [20,20].\n我们可以让数组初始大小为 20 。\n总浪费空间为 (20 - 10) + (20 - 20) = 10 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><b>输入：</b>nums = [10,20,30], k = 1\n<b>输出：</b>10\n<b>解释：</b>size = [20,20,30].\n我们可以让数组初始大小为 20 ，然后时刻 2 调整大小为 30 。\n总浪费空间为 (20 - 10) + (20 - 20) + (30 - 30) = 10 。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><b>输入：</b>nums = [10,20,15,30,20], k = 2\n<b>输出：</b>15\n<b>解释：</b>size = [10,20,20,30,30].\n我们可以让数组初始大小为 10 ，时刻 1 调整大小为 20 ，时刻 3 调整大小为 30 。\n总浪费空间为 (10 - 10) + (20 - 20) + (20 - 15) + (30 - 30) + (30 - 20) = 15 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 200</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>6</sup></code></li>\n\t<li><code>0 &lt;= k &lt;= nums.length - 1</code></li>\n</ul>\n",
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