You are currently designing a dynamic array. You are given a 0-indexed integer array nums, where nums[i] is the number of elements that will be in the array at time i. In addition, you are given an integer k, the maximum number of times you can resize the array (to any size).
The size of the array at time t, sizet, must be at least nums[t] because there needs to be enough space in the array to hold all the elements. The space wasted at time t is defined as sizet - nums[t], and the total space wasted is the sum of the space wasted across every time t where 0 <= t < nums.length.
Return the minimum total space wasted if you can resize the array at most k times.
Note: The array can have any size at the start and does not count towards the number of resizing operations.
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Example 1:
\n\n\nInput: nums = [10,20], k = 0\nOutput: 10\nExplanation: size = [20,20].\nWe can set the initial size to be 20.\nThe total wasted space is (20 - 10) + (20 - 20) = 10.\n\n\n
Example 2:
\n\n\nInput: nums = [10,20,30], k = 1\nOutput: 10\nExplanation: size = [20,20,30].\nWe can set the initial size to be 20 and resize to 30 at time 2. \nThe total wasted space is (20 - 10) + (20 - 20) + (30 - 30) = 10.\n\n\n
Example 3:
\n\n\nInput: nums = [10,20,15,30,20], k = 2\nOutput: 15\nExplanation: size = [10,20,20,30,30].\nWe can set the initial size to 10, resize to 20 at time 1, and resize to 30 at time 3.\nThe total wasted space is (10 - 10) + (20 - 20) + (20 - 15) + (30 - 30) + (30 - 20) = 15.\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 2001 <= nums[i] <= 1060 <= k <= nums.length - 1你正在设计一个动态数组。给你一个下标从 0 开始的整数数组 nums ，其中 nums[i] 是 i 时刻数组中的元素数目。除此以外，你还有一个整数 k ，表示你可以 调整 数组大小的 最多 次数（每次都可以调整成 任意 大小）。
t 时刻数组的大小 sizet 必须大于等于 nums[t] ，因为数组需要有足够的空间容纳所有元素。t 时刻 浪费的空间 为 sizet - nums[t] ，总 浪费空间为满足 0 <= t < nums.length 的每一个时刻 t 浪费的空间 之和 。
在调整数组大小不超过 k 次的前提下，请你返回 最小总浪费空间 。
注意：数组最开始时可以为 任意大小 ，且 不计入 调整大小的操作次数。
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示例 1：
\n\n输入：nums = [10,20], k = 0\n输出：10\n解释：size = [20,20].\n我们可以让数组初始大小为 20 。\n总浪费空间为 (20 - 10) + (20 - 20) = 10 。\n\n\n
示例 2：
\n\n输入：nums = [10,20,30], k = 1\n输出：10\n解释：size = [20,20,30].\n我们可以让数组初始大小为 20 ，然后时刻 2 调整大小为 30 。\n总浪费空间为 (20 - 10) + (20 - 20) + (30 - 30) = 10 。\n\n\n
示例 3：
\n\n输入：nums = [10,20,15,30,20], k = 2\n输出：15\n解释：size = [10,20,20,30,30].\n我们可以让数组初始大小为 10 ，时刻 1 调整大小为 20 ，时刻 3 调整大小为 30 。\n总浪费空间为 (10 - 10) + (20 - 20) + (20 - 15) + (30 - 30) + (30 - 20) = 15 。\n\n\n
\n\n
提示：
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