leetcode-problemset/leetcode-cn/originData/make-three-strings-equal.json

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            "title": "Make Three Strings Equal",
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            "content": "<p>You are given three strings <code>s1</code>, <code>s2</code>, and <code>s3</code>. You have to perform the following operation on these three strings <strong>as many times</strong> as you want<!-- notionvc: b5178de7-3318-4129-b7d9-726b47e90621 -->.</p>\n\n<p>In one operation you can choose one of these three strings such that its length is at least <code>2</code><!-- notionvc: 3342ac46-33c8-4010-aacd-e58678ce31ef --> and delete the <strong>rightmost</strong> character of it.</p>\n\n<p>Return <em>the <strong>minimum</strong> number of operations you need to perform to make the three strings equal if there is a way to make them equal, otherwise, return </em><code>-1</code><em>.</em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s1 = &quot;abc&quot;, s2 = &quot;abb&quot;, s3 = &quot;ab&quot;\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> Performing operations on s1 and s2 once will lead to three equal strings.\nIt can be shown that there is no way to make them equal with less than two operations.</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s1 = &quot;dac&quot;, s2 = &quot;bac&quot;, s3 = &quot;cac&quot;\n<strong>Output:</strong> -1\n<strong>Explanation:</strong> Because the leftmost letters<!-- notionvc: 47239f7c-eec1-49f8-af79-c206ec88cb07 --> of s1 and s2 are not equal, they could not be equal after any number of operations. So the answer is -1.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s1.length, s2.length, s3.length &lt;= 100</code></li>\n\t<li><font face=\"monospace\"><code>s1</code>,</font> <code><font face=\"monospace\">s2</font></code><font face=\"monospace\"> and</font> <code><font face=\"monospace\">s3</font></code> consist only of lowercase English letters.</li>\n</ul>\n",
            "translatedTitle": "使三个字符串相等",
            "translatedContent": "<p>给你三个字符串 <code>s1</code>、<code>s2</code> 和 <code>s3</code>。 你可以根据需要对这三个字符串执行以下操作 <strong>任意次数</strong> <!-- notionvc: b5178de7-3318-4129-b7d9-726b47e90621 -->。</p>\n\n<p>在每次操作中，你可以选择其中一个长度至少为 <code>2</code> 的字符串 <!-- notionvc: 3342ac46-33c8-4010-aacd-e58678ce31ef --> 并删除其 <strong>最右位置上</strong> 的字符。</p>\n\n<p>如果存在某种方法能够使这三个字符串相等，请返回使它们相等所需的 <strong>最小</strong> 操作次数；否则，返回 <code>-1</code>。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>s1 = \"abc\"，s2 = \"abb\"，s3 = \"ab\"\n<strong>输出：</strong>2\n<strong>解释：</strong>对 s1 和 s2 进行一次操作后，可以得到三个相等的字符串。\n可以证明，不可能用少于两次操作使它们相等。</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>s1 = \"dac\"，s2 = \"bac\"，s3 = \"cac\"\n<strong>输出：</strong>-1\n<strong>解释：</strong>因为 s1 和 s2 的最左位置上的字母<!-- notionvc: 47239f7c-eec1-49f8-af79-c206ec88cb07 -->不相等，所以无论进行多少次操作，它们都不可能相等。因此答案是 -1 。</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s1.length, s2.length, s3.length &lt;= 100</code></li>\n\t<li><code>s1</code>、<code>s2</code> 和 <code>s3</code> 仅由小写英文字母组成。</li>\n</ul>\n",
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