{ "data": { "question": { "questionId": "3207", "questionFrontendId": "2937", "categoryTitle": "Algorithms", "boundTopicId": 2531443, "title": "Make Three Strings Equal", "titleSlug": "make-three-strings-equal", "content": "
You are given three strings s1
, s2
, and s3
. You have to perform the following operation on these three strings as many times as you want.
In one operation you can choose one of these three strings such that its length is at least 2
and delete the rightmost character of it.
Return the minimum number of operations you need to perform to make the three strings equal if there is a way to make them equal, otherwise, return -1
.
\n
Example 1:
\n\n\nInput: s1 = "abc", s2 = "abb", s3 = "ab"\nOutput: 2\nExplanation: Performing operations on s1 and s2 once will lead to three equal strings.\nIt can be shown that there is no way to make them equal with less than two operations.\n\n
Example 2:
\n\n\nInput: s1 = "dac", s2 = "bac", s3 = "cac"\nOutput: -1\nExplanation: Because the leftmost letters of s1 and s2 are not equal, they could not be equal after any number of operations. So the answer is -1.\n\n\n
\n
Constraints:
\n\n1 <= s1.length, s2.length, s3.length <= 100
s1
, s2
and s3
consist only of lowercase English letters.给你三个字符串 s1
、s2
和 s3
。 你可以根据需要对这三个字符串执行以下操作 任意次数 。
在每次操作中,你可以选择其中一个长度至少为 2
的字符串 并删除其 最右位置上 的字符。
如果存在某种方法能够使这三个字符串相等,请返回使它们相等所需的 最小 操作次数;否则,返回 -1
。
\n\n
示例 1:
\n\n\n输入:s1 = \"abc\",s2 = \"abb\",s3 = \"ab\"\n输出:2\n解释:对 s1 和 s2 进行一次操作后,可以得到三个相等的字符串。\n可以证明,不可能用少于两次操作使它们相等。\n\n
示例 2:
\n\n\n输入:s1 = \"dac\",s2 = \"bac\",s3 = \"cac\"\n输出:-1\n解释:因为 s1 和 s2 的最左位置上的字母不相等,所以无论进行多少次操作,它们都不可能相等。因此答案是 -1 。\n\n
\n\n
提示:
\n\n1 <= s1.length, s2.length, s3.length <= 100
s1
、s2
和 s3
仅由小写英文字母组成。3
strings."
],
"solution": null,
"status": null,
"sampleTestCase": "\"abc\"\n\"abb\"\n\"ab\"",
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