leetcode-problemset/leetcode-cn/originData/largest-number-at-least-twice-of-others.json

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            "categoryTitle": "Algorithms",
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            "title": "Largest Number At Least Twice of Others",
            "titleSlug": "largest-number-at-least-twice-of-others",
            "content": "<p>You are given an integer array <code>nums</code> where the largest integer is <strong>unique</strong>.</p>\n\n<p>Determine whether the largest element in the array is <strong>at least twice</strong> as much as every other number in the array. If it is, return <em>the <strong>index</strong> of the largest element, or return </em><code>-1</code><em> otherwise</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [3,6,1,0]\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> 6 is the largest integer.\nFor every other number in the array x, 6 is at least twice as big as x.\nThe index of value 6 is 1, so we return 1.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3,4]\n<strong>Output:</strong> -1\n<strong>Explanation:</strong> 4 is less than twice the value of 3, so we return -1.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= nums.length &lt;= 50</code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 100</code></li>\n\t<li>The largest element in <code>nums</code> is unique.</li>\n</ul>\n",
            "translatedTitle": "至少是其他数字两倍的最大数",
            "translatedContent": "<p>给你一个整数数组 <code>nums</code> ，其中总是存在 <strong>唯一的</strong> 一个最大整数 。</p>\n\n<p>请你找出数组中的最大元素并检查它是否 <strong>至少是数组中每个其他数字的两倍</strong> 。如果是，则返回 <strong>最大元素的下标</strong> ，否则返回 <code>-1</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [3,6,1,0]\n<strong>输出：</strong>1\n<strong>解释：</strong>6 是最大的整数，对于数组中的其他整数，6 至少是数组中其他元素的两倍。6 的下标是 1 ，所以返回 1 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,2,3,4]\n<strong>输出：</strong>-1\n<strong>解释：</strong>4 没有超过 3 的两倍大，所以返回 -1 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= nums.length &lt;= 50</code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 100</code></li>\n\t<li><code>nums</code> 中的最大元素是唯一的</li>\n</ul>\n",
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                "Scan through the array to find the unique largest element `m`, keeping track of it's index `maxIndex`.\r\n\r\nScan through the array again.  If we find some `x != m` with `m < 2*x`, we should return `-1`.\r\n\r\nOtherwise, we should return `maxIndex`."
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