{ "data": { "question": { "questionId": "748", "questionFrontendId": "747", "categoryTitle": "Algorithms", "boundTopicId": 1480, "title": "Largest Number At Least Twice of Others", "titleSlug": "largest-number-at-least-twice-of-others", "content": "
You are given an integer array nums
where the largest integer is unique.
Determine whether the largest element in the array is at least twice as much as every other number in the array. If it is, return the index of the largest element, or return -1
otherwise.
\n
Example 1:
\n\n\nInput: nums = [3,6,1,0]\nOutput: 1\nExplanation: 6 is the largest integer.\nFor every other number in the array x, 6 is at least twice as big as x.\nThe index of value 6 is 1, so we return 1.\n\n\n
Example 2:
\n\n\nInput: nums = [1,2,3,4]\nOutput: -1\nExplanation: 4 is less than twice the value of 3, so we return -1.\n\n\n
\n
Constraints:
\n\n2 <= nums.length <= 50
0 <= nums[i] <= 100
nums
is unique.给你一个整数数组 nums
,其中总是存在 唯一的 一个最大整数 。
请你找出数组中的最大元素并检查它是否 至少是数组中每个其他数字的两倍 。如果是,则返回 最大元素的下标 ,否则返回 -1
。
\n\n
示例 1:
\n\n\n输入:nums = [3,6,1,0]\n输出:1\n解释:6 是最大的整数,对于数组中的其他整数,6 至少是数组中其他元素的两倍。6 的下标是 1 ,所以返回 1 。\n\n\n
示例 2:
\n\n\n输入:nums = [1,2,3,4]\n输出:-1\n解释:4 没有超过 3 的两倍大,所以返回 -1 。\n\n\n
\n\n
提示:
\n\n2 <= nums.length <= 50
0 <= nums[i] <= 100
nums
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