leetcode-problemset/leetcode-cn/originData/find-the-substring-with-maximum-cost.json

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            "questionId": "2669",
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            "categoryTitle": "Algorithms",
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            "title": "Find the Substring With Maximum Cost",
            "titleSlug": "find-the-substring-with-maximum-cost",
            "content": "<p>You are given a string <code>s</code>, a string <code>chars</code> of <strong>distinct</strong> characters and an integer array <code>vals</code> of the same length as <code>chars</code>.</p>\n\n<p>The <strong>cost of the substring </strong>is the sum of the values of each character in the substring. The cost of an empty string is considered <code>0</code>.</p>\n\n<p>The <strong>value of the character </strong>is defined in the following way:</p>\n\n<ul>\n\t<li>If the character is not in the string <code>chars</code>, then its value is its corresponding position <strong>(1-indexed)</strong> in the alphabet.\n\n\t<ul>\n\t\t<li>For example, the value of <code>&#39;a&#39;</code> is <code>1</code>, the value of <code>&#39;b&#39;</code> is <code>2</code>, and so on. The value of <code>&#39;z&#39;</code> is <code>26</code>.</li>\n\t</ul>\n\t</li>\n\t<li>Otherwise, assuming <code>i</code> is the index where the character occurs in the string <code>chars</code>, then its value is <code>vals[i]</code>.</li>\n</ul>\n\n<p>Return <em>the maximum cost among all substrings of the string</em> <code>s</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;adaa&quot;, chars = &quot;d&quot;, vals = [-1000]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> The value of the characters &quot;a&quot; and &quot;d&quot; is 1 and -1000 respectively.\nThe substring with the maximum cost is &quot;aa&quot; and its cost is 1 + 1 = 2.\nIt can be proven that 2 is the maximum cost.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;abc&quot;, chars = &quot;abc&quot;, vals = [-1,-1,-1]\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> The value of the characters &quot;a&quot;, &quot;b&quot; and &quot;c&quot; is -1, -1, and -1 respectively.\nThe substring with the maximum cost is the empty substring &quot;&quot; and its cost is 0.\nIt can be proven that 0 is the maximum cost.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s</code> consist of lowercase English letters.</li>\n\t<li><code>1 &lt;= chars.length &lt;= 26</code></li>\n\t<li><code>chars</code> consist of <strong>distinct</strong> lowercase English letters.</li>\n\t<li><code>vals.length == chars.length</code></li>\n\t<li><code>-1000 &lt;= vals[i] &lt;= 1000</code></li>\n</ul>\n",
            "translatedTitle": "找到最大开销的子字符串",
            "translatedContent": "<p>给你一个字符串&nbsp;<code>s</code>&nbsp;，一个字符&nbsp;<strong>互不相同</strong>&nbsp;的字符串&nbsp;<code>chars</code>&nbsp;和一个长度与 <code>chars</code>&nbsp;相同的整数数组&nbsp;<code>vals</code>&nbsp;。</p>\n\n<p><strong>子字符串的开销</strong>&nbsp;是一个子字符串中所有字符对应价值之和。空字符串的开销是 <code>0</code>&nbsp;。</p>\n\n<p><strong>字符的价值</strong>&nbsp;定义如下：</p>\n\n<ul>\n\t<li>如果字符不在字符串&nbsp;<code>chars</code>&nbsp;中，那么它的价值是它在字母表中的位置（下标从 <strong>1</strong>&nbsp;开始）。\n\n\t<ul>\n\t\t<li>比方说，<code>'a'</code>&nbsp;的价值为&nbsp;<code>1</code>&nbsp;，<code>'b'</code>&nbsp;的价值为&nbsp;<code>2</code>&nbsp;，以此类推，<code>'z'</code>&nbsp;的价值为&nbsp;<code>26</code>&nbsp;。</li>\n\t</ul>\n\t</li>\n\t<li>否则，如果这个字符在 <code>chars</code>&nbsp;中的位置为 <code>i</code>&nbsp;，那么它的价值就是&nbsp;<code>vals[i]</code>&nbsp;。</li>\n</ul>\n\n<p>请你返回字符串 <code>s</code>&nbsp;的所有子字符串中的最大开销。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><b>输入：</b>s = \"adaa\", chars = \"d\", vals = [-1000]\n<b>输出：</b>2\n<b>解释：</b>字符 \"a\" 和 \"d\" 的价值分别为 1 和 -1000 。\n最大开销子字符串是 \"aa\" ，它的开销为 1 + 1 = 2 。\n2 是最大开销。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><b>输入：</b>s = \"abc\", chars = \"abc\", vals = [-1,-1,-1]\n<b>输出：</b>0\n<b>解释：</b>字符 \"a\" ，\"b\" 和 \"c\" 的价值分别为 -1 ，-1 和 -1 。\n最大开销子字符串是 \"\" ，它的开销为 0 。\n0 是最大开销。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s</code>&nbsp;只包含小写英文字母。</li>\n\t<li><code>1 &lt;= chars.length &lt;= 26</code></li>\n\t<li><code>chars</code>&nbsp;只包含小写英文字母，且 <strong>互不相同</strong>&nbsp;。</li>\n\t<li><code>vals.length == chars.length</code></li>\n\t<li><code>-1000 &lt;= vals[i] &lt;= 1000</code></li>\n</ul>\n",
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                "Create a new integer array where arr[i] denotes the value of character s[i].",
                "We can use Kadane’s maximum subarray sum algorithm to find the maximum cost."
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