mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
196 lines
29 KiB
JSON
196 lines
29 KiB
JSON
{
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"questionId": "2677",
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"questionFrontendId": "2641",
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"categoryTitle": "Algorithms",
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"boundTopicId": 2225771,
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"title": "Cousins in Binary Tree II",
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"titleSlug": "cousins-in-binary-tree-ii",
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"content": "<p>Given the <code>root</code> of a binary tree, replace the value of each node in the tree with the <strong>sum of all its cousins' values</strong>.</p>\n\n<p>Two nodes of a binary tree are <strong>cousins</strong> if they have the same depth with different parents.</p>\n\n<p>Return <em>the </em><code>root</code><em> of the modified tree</em>.</p>\n\n<p><strong>Note</strong> that the depth of a node is the number of edges in the path from the root node to it.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2023/01/11/example11.png\" style=\"width: 571px; height: 151px;\" />\n<pre>\n<strong>Input:</strong> root = [5,4,9,1,10,null,7]\n<strong>Output:</strong> [0,0,0,7,7,null,11]\n<strong>Explanation:</strong> The diagram above shows the initial binary tree and the binary tree after changing the value of each node.\n- Node with value 5 does not have any cousins so its sum is 0.\n- Node with value 4 does not have any cousins so its sum is 0.\n- Node with value 9 does not have any cousins so its sum is 0.\n- Node with value 1 has a cousin with value 7 so its sum is 7.\n- Node with value 10 has a cousin with value 7 so its sum is 7.\n- Node with value 7 has cousins with values 1 and 10 so its sum is 11.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2023/01/11/diagram33.png\" style=\"width: 481px; height: 91px;\" />\n<pre>\n<strong>Input:</strong> root = [3,1,2]\n<strong>Output:</strong> [0,0,0]\n<strong>Explanation:</strong> The diagram above shows the initial binary tree and the binary tree after changing the value of each node.\n- Node with value 3 does not have any cousins so its sum is 0.\n- Node with value 1 does not have any cousins so its sum is 0.\n- Node with value 2 does not have any cousins so its sum is 0.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the tree is in the range <code>[1, 10<sup>5</sup>]</code>.</li>\n\t<li><code>1 <= Node.val <= 10<sup>4</sup></code></li>\n</ul>\n",
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"translatedTitle": "二叉树的堂兄弟节点 II",
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"translatedContent": "<p>给你一棵二叉树的根 <code>root</code> ，请你将每个节点的值替换成该节点的所有 <strong>堂兄弟节点值的和 </strong>。</p>\n\n<p>如果两个节点在树中有相同的深度且它们的父节点不同，那么它们互为 <strong>堂兄弟</strong> 。</p>\n\n<p>请你返回修改值之后，树的根<em> </em><code>root</code><em> </em>。</p>\n\n<p><strong>注意</strong>，一个节点的深度指的是从树根节点到这个节点经过的边数。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2023/01/11/example11.png\" style=\"width: 571px; height: 151px;\" /></p>\n\n<pre>\n<b>输入：</b>root = [5,4,9,1,10,null,7]\n<b>输出：</b>[0,0,0,7,7,null,11]\n<b>解释：</b>上图展示了初始的二叉树和修改每个节点的值之后的二叉树。\n- 值为 5 的节点没有堂兄弟，所以值修改为 0 。\n- 值为 4 的节点没有堂兄弟，所以值修改为 0 。\n- 值为 9 的节点没有堂兄弟，所以值修改为 0 。\n- 值为 1 的节点有一个堂兄弟，值为 7 ，所以值修改为 7 。\n- 值为 10 的节点有一个堂兄弟，值为 7 ，所以值修改为 7 。\n- 值为 7 的节点有两个堂兄弟，值分别为 1 和 10 ，所以值修改为 11 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2023/01/11/diagram33.png\" style=\"width: 481px; height: 91px;\" /></p>\n\n<pre>\n<b>输入：</b>root = [3,1,2]\n<b>输出：</b>[0,0,0]\n<b>解释：</b>上图展示了初始的二叉树和修改每个节点的值之后的二叉树。\n- 值为 3 的节点没有堂兄弟，所以值修改为 0 。\n- 值为 1 的节点没有堂兄弟，所以值修改为 0 。\n- 值为 2 的节点没有堂兄弟，所以值修改为 0 。\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>树中节点数目的范围是 <code>[1, 10<sup>5</sup>]</code> 。</li>\n\t<li><code>1 <= Node.val <= 10<sup>4</sup></code></li>\n</ul>\n",
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"Use DFS two times.",
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"For the first time, find the sum of values of all the levels of the binary tree.",
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"For the second time, update the value of the node with the sum of the values of the current level - sibling node’s values."
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