{ "data": { "question": { "questionId": "2677", "questionFrontendId": "2641", "categoryTitle": "Algorithms", "boundTopicId": 2225771, "title": "Cousins in Binary Tree II", "titleSlug": "cousins-in-binary-tree-ii", "content": "

Given the root of a binary tree, replace the value of each node in the tree with the sum of all its cousins' values.

\n\n

Two nodes of a binary tree are cousins if they have the same depth with different parents.

\n\n

Return the root of the modified tree.

\n\n

Note that the depth of a node is the number of edges in the path from the root node to it.

\n\n

 

\n

Example 1:

\n\"\"\n
\nInput: root = [5,4,9,1,10,null,7]\nOutput: [0,0,0,7,7,null,11]\nExplanation: The diagram above shows the initial binary tree and the binary tree after changing the value of each node.\n- Node with value 5 does not have any cousins so its sum is 0.\n- Node with value 4 does not have any cousins so its sum is 0.\n- Node with value 9 does not have any cousins so its sum is 0.\n- Node with value 1 has a cousin with value 7 so its sum is 7.\n- Node with value 10 has a cousin with value 7 so its sum is 7.\n- Node with value 7 has cousins with values 1 and 10 so its sum is 11.\n
\n\n

Example 2:

\n\"\"\n
\nInput: root = [3,1,2]\nOutput: [0,0,0]\nExplanation: The diagram above shows the initial binary tree and the binary tree after changing the value of each node.\n- Node with value 3 does not have any cousins so its sum is 0.\n- Node with value 1 does not have any cousins so its sum is 0.\n- Node with value 2 does not have any cousins so its sum is 0.\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "二叉树的堂兄弟节点 II", "translatedContent": "

给你一棵二叉树的根 root ，请你将每个节点的值替换成该节点的所有 堂兄弟节点值的和 。

\n\n

如果两个节点在树中有相同的深度且它们的父节点不同，那么它们互为 堂兄弟 。

\n\n

请你返回修改值之后，树的根 root 。

\n\n

注意，一个节点的深度指的是从树根节点到这个节点经过的边数。

\n\n

 

\n\n

示例 1：

\n\n

\"\"

\n\n
\n输入：root = [5,4,9,1,10,null,7]\n输出：[0,0,0,7,7,null,11]\n解释：上图展示了初始的二叉树和修改每个节点的值之后的二叉树。\n- 值为 5 的节点没有堂兄弟，所以值修改为 0 。\n- 值为 4 的节点没有堂兄弟，所以值修改为 0 。\n- 值为 9 的节点没有堂兄弟，所以值修改为 0 。\n- 值为 1 的节点有一个堂兄弟，值为 7 ，所以值修改为 7 。\n- 值为 10 的节点有一个堂兄弟，值为 7 ，所以值修改为 7 。\n- 值为 7 的节点有两个堂兄弟，值分别为 1 和 10 ，所以值修改为 11 。\n
\n\n

示例 2：

\n\n

\"\"

\n\n
\n输入：root = [3,1,2]\n输出：[0,0,0]\n解释：上图展示了初始的二叉树和修改每个节点的值之后的二叉树。\n- 值为 3 的节点没有堂兄弟，所以值修改为 0 。\n- 值为 1 的节点没有堂兄弟，所以值修改为 0 。\n- 值为 2 的节点没有堂兄弟，所以值修改为 0 。\n
\n\n

 

\n\n

提示：

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0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root\n * @return {TreeNode}\n */\nvar replaceValueInTree = function(root) {\n\n};", "__typename": "CodeSnippetNode" }, { "lang": "TypeScript", "langSlug": "typescript", "code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * val: number\n * left: TreeNode | null\n * right: TreeNode | null\n * constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n * }\n */\n\nfunction replaceValueInTree(root: TreeNode | null): TreeNode | null {\n \n};", "__typename": "CodeSnippetNode" }, { "lang": "PHP", "langSlug": "php", "code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($val = 0, $left = null, $right = null) {\n * $this->val = $val;\n * $this->left = $left;\n * $this->right = $right;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param TreeNode $root\n * @return TreeNode\n */\n function replaceValueInTree($root) {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Swift", "langSlug": "swift", "code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func replaceValueInTree(_ root: TreeNode?) -> TreeNode? {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Kotlin", "langSlug": "kotlin", "code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun replaceValueInTree(root: TreeNode?): TreeNode? {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Dart", "langSlug": "dart", "code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * int val;\n * TreeNode? left;\n * TreeNode? right;\n * TreeNode([this.val = 0, this.left, this.right]);\n * }\n */\nclass Solution {\n TreeNode? replaceValueInTree(TreeNode? root) {\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Go", "langSlug": "golang", "code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc replaceValueInTree(root *TreeNode) *TreeNode {\n\n}", "__typename": "CodeSnippetNode" }, { "lang": "Ruby", "langSlug": "ruby", "code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {TreeNode} root\n# @return {TreeNode}\ndef replace_value_in_tree(root)\n\nend", "__typename": "CodeSnippetNode" }, { "lang": "Scala", "langSlug": "scala", "code": "/**\n * Definition for a binary tree node.\n * class TreeNode(_value: Int = 0, _left: TreeNode = null, _right: TreeNode = null) {\n * var value: Int = _value\n * var left: TreeNode = _left\n * var right: TreeNode = _right\n * }\n */\nobject Solution {\n def replaceValueInTree(root: TreeNode): TreeNode = {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Rust", "langSlug": "rust", "code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option>>,\n// pub right: Option>>,\n// }\n//\n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n pub fn replace_value_in_tree(root: Option>>) -> Option>> {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Racket", "langSlug": "racket", "code": "; Definition for a binary tree node.\n#|\n\n; val : integer?\n; left : (or/c tree-node? #f)\n; right : (or/c tree-node? #f)\n(struct tree-node\n (val left right) #:mutable #:transparent)\n\n; constructor\n(define (make-tree-node [val 0])\n (tree-node val #f #f))\n\n|#\n\n(define/contract (replace-value-in-tree root)\n (-> (or/c tree-node? #f) (or/c tree-node? #f))\n )", "__typename": "CodeSnippetNode" }, { "lang": "Erlang", "langSlug": "erlang", "code": "%% Definition for a binary tree node.\n%%\n%% -record(tree_node, {val = 0 :: integer(),\n%% left = null :: 'null' | #tree_node{},\n%% right = null :: 'null' | #tree_node{}}).\n\n-spec replace_value_in_tree(Root :: #tree_node{} | null) -> #tree_node{} | null.\nreplace_value_in_tree(Root) ->\n .", "__typename": "CodeSnippetNode" }, { "lang": "Elixir", "langSlug": "elixir", "code": "# Definition for a binary tree node.\n#\n# defmodule TreeNode do\n# @type t :: %__MODULE__{\n# val: integer,\n# left: TreeNode.t() | nil,\n# right: TreeNode.t() | nil\n# }\n# defstruct val: 0, left: nil, right: nil\n# end\n\ndefmodule Solution do\n @spec replace_value_in_tree(root :: TreeNode.t | nil) :: TreeNode.t | nil\n def replace_value_in_tree(root) do\n \n end\nend", "__typename": "CodeSnippetNode" } ], "stats": "{\"totalAccepted\": \"4.4K\", \"totalSubmission\": \"6.2K\", \"totalAcceptedRaw\": 4425, \"totalSubmissionRaw\": 6172, \"acRate\": \"71.7%\"}", "hints": [ "Use DFS two times.", "For the first time, find the sum of values of all the levels of the binary tree.", "For the second time, update the value of the node with the sum of the values of the current level - sibling node’s values." ], "solution": null, "status": null, "sampleTestCase": "[5,4,9,1,10,null,7]", "metaData": "{\n \"name\": \"replaceValueInTree\",\n \"params\": [\n {\n \"name\": \"root\",\n \"type\": \"TreeNode\"\n }\n ],\n \"return\": {\n \"type\": \"TreeNode\"\n }\n}", "judgerAvailable": true, "judgeType": "large", "mysqlSchemas": [], "enableRunCode": true, "envInfo": "{\"cpp\":[\"C++\",\"

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