leetcode-problemset/leetcode-cn/originData/cinema-seat-allocation.json

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        "question": {
            "questionId": "1487",
            "questionFrontendId": "1386",
            "categoryTitle": "Algorithms",
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            "title": "Cinema Seat Allocation",
            "titleSlug": "cinema-seat-allocation",
            "content": "<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/02/14/cinema_seats_1.png\" style=\"width: 400px; height: 149px;\" /></p>\n\n<p>A cinema&nbsp;has <code>n</code>&nbsp;rows of seats, numbered from 1 to <code>n</code>&nbsp;and there are ten&nbsp;seats in each row, labelled from 1&nbsp;to 10&nbsp;as shown in the figure above.</p>\n\n<p>Given the array <code>reservedSeats</code> containing the numbers of seats already reserved, for example, <code>reservedSeats[i] = [3,8]</code>&nbsp;means the seat located in row <strong>3</strong> and labelled with <b>8</b>&nbsp;is already reserved.</p>\n\n<p><em>Return the maximum number of four-person groups&nbsp;you can assign on the cinema&nbsp;seats.</em> A four-person group&nbsp;occupies four&nbsp;adjacent seats <strong>in one single row</strong>. Seats across an aisle (such as [3,3]&nbsp;and [3,4]) are not considered to be adjacent, but there is an exceptional case&nbsp;on which an aisle split&nbsp;a four-person group, in that case, the aisle split&nbsp;a four-person group in the middle,&nbsp;which means to have two people on each side.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/02/14/cinema_seats_3.png\" style=\"width: 400px; height: 96px;\" /></p>\n\n<pre>\n<strong>Input:</strong> n = 3, reservedSeats = [[1,2],[1,3],[1,8],[2,6],[3,1],[3,10]]\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> The figure above shows the optimal allocation for four groups, where seats mark with blue are already reserved and contiguous seats mark with orange are for one group.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 2, reservedSeats = [[2,1],[1,8],[2,6]]\n<strong>Output:</strong> 2\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 4, reservedSeats = [[4,3],[1,4],[4,6],[1,7]]\n<strong>Output:</strong> 4\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 10^9</code></li>\n\t<li><code>1 &lt;=&nbsp;reservedSeats.length &lt;= min(10*n, 10^4)</code></li>\n\t<li><code>reservedSeats[i].length == 2</code></li>\n\t<li><code>1&nbsp;&lt;=&nbsp;reservedSeats[i][0] &lt;= n</code></li>\n\t<li><code>1 &lt;=&nbsp;reservedSeats[i][1] &lt;= 10</code></li>\n\t<li>All <code>reservedSeats[i]</code> are distinct.</li>\n</ul>\n",
            "translatedTitle": "安排电影院座位",
            "translatedContent": "<p><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2020/03/21/cinema_seats_1.png\" style=\"height: 149px; width: 400px;\"></p>\n\n<p>如上图所示，电影院的观影厅中有 <code>n</code>&nbsp;行座位，行编号从 1&nbsp;到 <code>n</code>&nbsp;，且每一行内总共有 10 个座位，列编号从 1 到 10 。</p>\n\n<p>给你数组&nbsp;<code>reservedSeats</code>&nbsp;，包含所有已经被预约了的座位。比如说，<code>researvedSeats[i]=[3,8]</code>&nbsp;，它表示第&nbsp;<strong>3</strong>&nbsp;行第&nbsp;<strong>8</strong>&nbsp;个座位被预约了。</p>\n\n<p>请你返回&nbsp;<strong>最多能安排多少个 4 人家庭</strong>&nbsp;。4 人家庭要占据&nbsp;<strong>同一行内连续&nbsp;</strong>的 4 个座位。隔着过道的座位（比方说 [3,3] 和 [3,4]）不是连续的座位，但是如果你可以将 4 人家庭拆成过道两边各坐 2 人，这样子是允许的。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2020/03/21/cinema_seats_3.png\" style=\"height: 96px; width: 400px;\"></p>\n\n<pre><strong>输入：</strong>n = 3, reservedSeats = [[1,2],[1,3],[1,8],[2,6],[3,1],[3,10]]\n<strong>输出：</strong>4\n<strong>解释：</strong>上图所示是最优的安排方案，总共可以安排 4 个家庭。蓝色的叉表示被预约的座位，橙色的连续座位表示一个 4 人家庭。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><strong>输入：</strong>n = 2, reservedSeats = [[2,1],[1,8],[2,6]]\n<strong>输出：</strong>2\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre><strong>输入：</strong>n = 4, reservedSeats = [[4,3],[1,4],[4,6],[1,7]]\n<strong>输出：</strong>4\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 10^9</code></li>\n\t<li><code>1 &lt;=&nbsp;reservedSeats.length &lt;= min(10*n, 10^4)</code></li>\n\t<li><code>reservedSeats[i].length == 2</code></li>\n\t<li><code>1&nbsp;&lt;=&nbsp;reservedSeats[i][0] &lt;= n</code></li>\n\t<li><code>1 &lt;=&nbsp;reservedSeats[i][1] &lt;= 10</code></li>\n\t<li>所有&nbsp;<code>reservedSeats[i]</code> 都是互不相同的。</li>\n</ul>\n",
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                "Note you can allocate at most two families in one row.",
                "Greedily check if you can allocate seats for two families, one family or none.",
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