{ "data": { "question": { "questionId": "1487", "questionFrontendId": "1386", "categoryTitle": "Algorithms", "boundTopicId": 157862, "title": "Cinema Seat Allocation", "titleSlug": "cinema-seat-allocation", "content": "

\"\"

\n\n

A cinema has n rows of seats, numbered from 1 to n and there are ten seats in each row, labelled from 1 to 10 as shown in the figure above.

\n\n

Given the array reservedSeats containing the numbers of seats already reserved, for example, reservedSeats[i] = [3,8] means the seat located in row 3 and labelled with 8 is already reserved.

\n\n

Return the maximum number of four-person groups you can assign on the cinema seats. A four-person group occupies four adjacent seats in one single row. Seats across an aisle (such as [3,3] and [3,4]) are not considered to be adjacent, but there is an exceptional case on which an aisle split a four-person group, in that case, the aisle split a four-person group in the middle, which means to have two people on each side.

\n\n

 

\n

Example 1:

\n\n

\"\"

\n\n
\nInput: n = 3, reservedSeats = [[1,2],[1,3],[1,8],[2,6],[3,1],[3,10]]\nOutput: 4\nExplanation: The figure above shows the optimal allocation for four groups, where seats mark with blue are already reserved and contiguous seats mark with orange are for one group.\n
\n\n

Example 2:

\n\n
\nInput: n = 2, reservedSeats = [[2,1],[1,8],[2,6]]\nOutput: 2\n
\n\n

Example 3:

\n\n
\nInput: n = 4, reservedSeats = [[4,3],[1,4],[4,6],[1,7]]\nOutput: 4\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "安排电影院座位", "translatedContent": "

\"\"

\n\n

如上图所示,电影院的观影厅中有 n 行座位,行编号从 1 到 n ,且每一行内总共有 10 个座位,列编号从 1 到 10 。

\n\n

给你数组 reservedSeats ,包含所有已经被预约了的座位。比如说,researvedSeats[i]=[3,8] ,它表示第 3 行第 8 个座位被预约了。

\n\n

请你返回 最多能安排多少个 4 人家庭 。4 人家庭要占据 同一行内连续 的 4 个座位。隔着过道的座位(比方说 [3,3] 和 [3,4])不是连续的座位,但是如果你可以将 4 人家庭拆成过道两边各坐 2 人,这样子是允许的。

\n\n

 

\n\n

示例 1:

\n\n

\"\"

\n\n
输入:n = 3, reservedSeats = [[1,2],[1,3],[1,8],[2,6],[3,1],[3,10]]\n输出:4\n解释:上图所示是最优的安排方案,总共可以安排 4 个家庭。蓝色的叉表示被预约的座位,橙色的连续座位表示一个 4 人家庭。\n
\n\n

示例 2:

\n\n
输入:n = 2, reservedSeats = [[2,1],[1,8],[2,6]]\n输出:2\n
\n\n

示例 3:

\n\n
输入:n = 4, reservedSeats = [[4,3],[1,4],[4,6],[1,7]]\n输出:4\n
\n\n

 

\n\n

提示:

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(listof (listof exact-integer?)) exact-integer?)\n )", "__typename": "CodeSnippetNode" }, { "lang": "Erlang", "langSlug": "erlang", "code": "-spec max_number_of_families(N :: integer(), ReservedSeats :: [[integer()]]) -> integer().\nmax_number_of_families(N, ReservedSeats) ->\n .", "__typename": "CodeSnippetNode" }, { "lang": "Elixir", "langSlug": "elixir", "code": "defmodule Solution do\n @spec max_number_of_families(n :: integer, reserved_seats :: [[integer]]) :: integer\n def max_number_of_families(n, reserved_seats) do\n \n end\nend", "__typename": "CodeSnippetNode" } ], "stats": "{\"totalAccepted\": \"10.7K\", \"totalSubmission\": \"29.8K\", \"totalAcceptedRaw\": 10689, \"totalSubmissionRaw\": 29781, \"acRate\": \"35.9%\"}", "hints": [ "Note you can allocate at most two families in one row.", "Greedily check if you can allocate seats for two families, one family or none.", "Process only rows that appear in the input, for other rows you can always allocate seats for two families." ], "solution": null, "status": null, "sampleTestCase": "3\n[[1,2],[1,3],[1,8],[2,6],[3,1],[3,10]]", "metaData": "{\n \"name\": \"maxNumberOfFamilies\",\n \"params\": [\n {\n \"name\": \"n\",\n \"type\": \"integer\"\n },\n {\n \"type\": \"integer[][]\",\n \"name\": \"reservedSeats\"\n }\n ],\n \"return\": {\n \"type\": \"integer\"\n }\n}", "judgerAvailable": true, "judgeType": "large", "mysqlSchemas": [], "enableRunCode": true, "envInfo": "{\"cpp\":[\"C++\",\"

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