leetcode-problemset/leetcode-cn/originData/promise-time-limit.json

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        "question": {
            "questionId": "2749",
            "questionFrontendId": "2637",
            "categoryTitle": "JavaScript",
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            "title": "Promise Time Limit",
            "titleSlug": "promise-time-limit",
            "content": "<p>Given an&nbsp;asyncronous function&nbsp;<code>fn</code>&nbsp;and a time <code>t</code>&nbsp;in milliseconds, return&nbsp;a new&nbsp;<strong>time limited</strong>&nbsp;version of the input function.</p>\n\n<p>A&nbsp;<strong>time limited</strong>&nbsp;function is a function that is identical to the original unless it takes longer than&nbsp;<code>t</code>&nbsp;milliseconds to fullfill. In that case, it will reject with&nbsp;<code>&quot;Time Limit Exceeded&quot;</code>.&nbsp; Note that it should reject with a string, not an&nbsp;<code>Error</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> \nfn = async (n) =&gt; { \n&nbsp; await new Promise(res =&gt; setTimeout(res, 100)); \n&nbsp; return n * n; \n}\ninputs = [5]\nt = 50\n<strong>Output:</strong> {&quot;rejected&quot;:&quot;Time Limit Exceeded&quot;,&quot;time&quot;:50}\n<strong>Explanation:</strong>\nThe provided function is set to resolve after 100ms. However, the time limit is set to 50ms. It rejects at t=50ms because the time limit was reached.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> \nfn = async (n) =&gt; { \n&nbsp; await new Promise(res =&gt; setTimeout(res, 100)); \n&nbsp; return n * n; \n}\ninputs = [5]\nt = 150\n<strong>Output:</strong> {&quot;resolved&quot;:25,&quot;time&quot;:100}\n<strong>Explanation:</strong>\nThe function resolved 5 * 5 = 25 at t=100ms. The time limit is never reached.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> \nfn = async (a, b) =&gt; { \n&nbsp; await new Promise(res =&gt; setTimeout(res, 120)); \n&nbsp; return a + b; \n}\ninputs = [5,10]\nt = 150\n<strong>Output:</strong> {&quot;resolved&quot;:15,&quot;time&quot;:120}\n<strong>Explanation:</strong>\nThe function resolved 5 + 10 = 15 at t=120ms. The time limit is never reached.\n</pre>\n\n<p><strong class=\"example\">Example 4:</strong></p>\n\n<pre>\n<strong>Input:</strong> \nfn = async () =&gt; { \n&nbsp; throw &quot;Error&quot;;\n}\ninputs = []\nt = 1000\n<strong>Output:</strong> {&quot;rejected&quot;:&quot;Error&quot;,&quot;time&quot;:0}\n<strong>Explanation:</strong>\nThe function immediately throws an error.</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= inputs.length &lt;= 10</code></li>\n\t<li><code>0 &lt;= t &lt;= 1000</code></li>\n\t<li><code>fn returns a promise</code></li>\n</ul>\n",
            "translatedTitle": "有时间限制的 Promise 对象",
            "translatedContent": "<p>请你编写一个函数，它接收一个异步函数 <code>fn</code>&nbsp;和一个以毫秒为单位的时间 <code>t</code>。它应根据限时函数返回一个有 <strong>限时</strong> 效果的函数。</p>\n\n<p>限时函数是与原函数相同的函数，除非它需要 <code>t</code> 毫秒以上的时间来完成。如果出现了这种情况，请你返回 <code>\"Time Limit Exceeded\"</code>&nbsp;拒绝这次函数的调用。注意，它应该返回一个字符串拒绝，而不是一个&nbsp;<code>Error</code>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><b>示例 1：</b></p>\n\n<pre>\n<b>输入：</b>\nfn = async (n) =&gt; { \n&nbsp; await new Promise(res =&gt; setTimeout(res, 100)); \n&nbsp; return n * n; \n}\ninputs = [5]\nt = 50\n<b>输出：</b>{\"rejected\":\"Time Limit Exceeded\",\"time\":50}\n<b>解释：\n</b>提供的函数设置在 100ms 后执行完成，但是设置的超时时间为 50ms，所以在 t=50ms 时拒绝因为达到了超时时间。\n</pre>\n\n<p><b>示例 2：</b></p>\n\n<pre>\n<b>输入：</b>\nfn = async (n) =&gt; { \n&nbsp; await new Promise(res =&gt; setTimeout(res, 100)); \n&nbsp; return n * n; \n}\ninputs = [5]\nt = 150\n<b>输出：</b>{\"resolved\":25,\"time\":100}\n<b>解释：</b>\n在 t=100ms 时执行 5*5=25 ，没有达到超时时间。\n</pre>\n\n<p><b>示例 3：</b></p>\n\n<pre>\n<b>输入：</b>\nfn = async (a, b) =&gt; { \n&nbsp; await new Promise(res =&gt; setTimeout(res, 120)); \n&nbsp; return a + b; \n}\ninputs = [5,10]\nt = 150\n<b>输出：</b>{\"resolved\":15,\"time\":120}\n<b>解释：\n</b>在 t=120ms 时执行 5+10=15，没有达到超时时间。\n</pre>\n\n<p><b>示例 4：</b></p>\n\n<pre>\n<b>输入：</b>\nfn = async () =&gt; { \n&nbsp; throw \"Error\";\n}\ninputs = []\nt = 1000\n<b>输出：</b>{\"rejected\":\"Error\",\"time\":0}\n<b>解释：</b>\n此函数始终丢出 Error</pre>\n\n<p>&nbsp;</p>\n\n<p><b>提示：</b></p>\n\n<ul>\n\t<li><code>0 &lt;= inputs.length &lt;= 10</code></li>\n\t<li><code>0 &lt;= t &lt;= 1000</code></li>\n\t<li><code>fn 返回一个 Promise 对象</code></li>\n</ul>\n",
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                    "code": "/**\n * @param {Function} fn\n * @param {number} t\n * @return {Function}\n */\nvar timeLimit = function(fn, t) {\n\treturn async function(...args) {\n        \n    }\n};\n\n/**\n * const limited = timeLimit((t) => new Promise(res => setTimeout(res, t)), 100);\n * limited(150).catch(console.log) // \"Time Limit Exceeded\" at t=100ms\n */",
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                    "code": "type Fn = (...params: any[]) => Promise<any>;\n\nfunction timeLimit(fn: Fn, t: number): Fn {\n\treturn async function(...args) {\n        \n    }\n};\n\n/**\n * const limited = timeLimit((t) => new Promise(res => setTimeout(res, t)), 100);\n * limited(150).catch(console.log) // \"Time Limit Exceeded\" at t=100ms\n */",
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                "You can return a copy of a function with: \r\n\r\nfunction outerFunction(fn) { \r\n  return function innerFunction(...params) {\r\n    return fn(...params);\r\n  };\r\n}",
                "Inside the inner function, you will need to return a new Promise.",
                "You can create a new promise like: new Promise((resolve, reject) => {}).",
                "You can execute code with a delay with \"setTimeout(fn, delay)\"",
                "To reject a promise after a delay, \"setTimeout(() => reject('err'), delay)\"",
                "You can resolve and reject when the passed promise resolves or rejects with: \"fn(...params).then(resolve).catch(reject)\""
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