mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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66 lines
11 KiB
JSON
66 lines
11 KiB
JSON
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"question": {
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"questionId": "2749",
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"questionFrontendId": "2637",
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"categoryTitle": "JavaScript",
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"boundTopicId": 2222267,
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"title": "Promise Time Limit",
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"titleSlug": "promise-time-limit",
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"content": "<p>Given an asyncronous function <code>fn</code> and a time <code>t</code> in milliseconds, return a new <strong>time limited</strong> version of the input function.</p>\n\n<p>A <strong>time limited</strong> function is a function that is identical to the original unless it takes longer than <code>t</code> milliseconds to fullfill. In that case, it will reject with <code>"Time Limit Exceeded"</code>. Note that it should reject with a string, not an <code>Error</code>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> \nfn = async (n) => { \n await new Promise(res => setTimeout(res, 100)); \n return n * n; \n}\ninputs = [5]\nt = 50\n<strong>Output:</strong> {"rejected":"Time Limit Exceeded","time":50}\n<strong>Explanation:</strong>\nThe provided function is set to resolve after 100ms. However, the time limit is set to 50ms. It rejects at t=50ms because the time limit was reached.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> \nfn = async (n) => { \n await new Promise(res => setTimeout(res, 100)); \n return n * n; \n}\ninputs = [5]\nt = 150\n<strong>Output:</strong> {"resolved":25,"time":100}\n<strong>Explanation:</strong>\nThe function resolved 5 * 5 = 25 at t=100ms. The time limit is never reached.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> \nfn = async (a, b) => { \n await new Promise(res => setTimeout(res, 120)); \n return a + b; \n}\ninputs = [5,10]\nt = 150\n<strong>Output:</strong> {"resolved":15,"time":120}\n<strong>Explanation:</strong>\nThe function resolved 5 + 10 = 15 at t=120ms. The time limit is never reached.\n</pre>\n\n<p><strong class=\"example\">Example 4:</strong></p>\n\n<pre>\n<strong>Input:</strong> \nfn = async () => { \n throw "Error";\n}\ninputs = []\nt = 1000\n<strong>Output:</strong> {"rejected":"Error","time":0}\n<strong>Explanation:</strong>\nThe function immediately throws an error.</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>0 <= inputs.length <= 10</code></li>\n\t<li><code>0 <= t <= 1000</code></li>\n\t<li><code>fn returns a promise</code></li>\n</ul>\n",
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"translatedTitle": "有时间限制的 Promise 对象",
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"translatedContent": "<p>请你编写一个函数，它接收一个异步函数 <code>fn</code> 和一个以毫秒为单位的时间 <code>t</code>。它应根据限时函数返回一个有 <strong>限时</strong> 效果的函数。</p>\n\n<p>限时函数是与原函数相同的函数，除非它需要 <code>t</code> 毫秒以上的时间来完成。如果出现了这种情况，请你返回 <code>\"Time Limit Exceeded\"</code> 拒绝这次函数的调用。注意，它应该返回一个字符串拒绝，而不是一个 <code>Error</code> 。</p>\n\n<p> </p>\n\n<p><b>示例 1：</b></p>\n\n<pre>\n<b>输入：</b>\nfn = async (n) => { \n await new Promise(res => setTimeout(res, 100)); \n return n * n; \n}\ninputs = [5]\nt = 50\n<b>输出：</b>{\"rejected\":\"Time Limit Exceeded\",\"time\":50}\n<b>解释：\n</b>提供的函数设置在 100ms 后执行完成，但是设置的超时时间为 50ms，所以在 t=50ms 时拒绝因为达到了超时时间。\n</pre>\n\n<p><b>示例 2：</b></p>\n\n<pre>\n<b>输入：</b>\nfn = async (n) => { \n await new Promise(res => setTimeout(res, 100)); \n return n * n; \n}\ninputs = [5]\nt = 150\n<b>输出：</b>{\"resolved\":25,\"time\":100}\n<b>解释：</b>\n在 t=100ms 时执行 5*5=25 ，没有达到超时时间。\n</pre>\n\n<p><b>示例 3：</b></p>\n\n<pre>\n<b>输入：</b>\nfn = async (a, b) => { \n await new Promise(res => setTimeout(res, 120)); \n return a + b; \n}\ninputs = [5,10]\nt = 150\n<b>输出：</b>{\"resolved\":15,\"time\":120}\n<b>解释：\n</b>在 t=120ms 时执行 5+10=15，没有达到超时时间。\n</pre>\n\n<p><b>示例 4：</b></p>\n\n<pre>\n<b>输入：</b>\nfn = async () => { \n throw \"Error\";\n}\ninputs = []\nt = 1000\n<b>输出：</b>{\"rejected\":\"Error\",\"time\":0}\n<b>解释：</b>\n此函数始终丢出 Error</pre>\n\n<p> </p>\n\n<p><b>提示：</b></p>\n\n<ul>\n\t<li><code>0 <= inputs.length <= 10</code></li>\n\t<li><code>0 <= t <= 1000</code></li>\n\t<li><code>fn 返回一个 Promise 对象</code></li>\n</ul>\n",
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"difficulty": "Easy",
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"lang": "JavaScript",
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"code": "/**\n * @param {Function} fn\n * @param {number} t\n * @return {Function}\n */\nvar timeLimit = function(fn, t) {\n\treturn async function(...args) {\n \n }\n};\n\n/**\n * const limited = timeLimit((t) => new Promise(res => setTimeout(res, t)), 100);\n * limited(150).catch(console.log) // \"Time Limit Exceeded\" at t=100ms\n */",
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"langSlug": "typescript",
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"code": "type Fn = (...params: any[]) => Promise<any>;\n\nfunction timeLimit(fn: Fn, t: number): Fn {\n\treturn async function(...args) {\n \n }\n};\n\n/**\n * const limited = timeLimit((t) => new Promise(res => setTimeout(res, t)), 100);\n * limited(150).catch(console.log) // \"Time Limit Exceeded\" at t=100ms\n */",
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"hints": [
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"You can return a copy of a function with: \r\n\r\nfunction outerFunction(fn) { \r\n return function innerFunction(...params) {\r\n return fn(...params);\r\n };\r\n}",
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"Inside the inner function, you will need to return a new Promise.",
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"You can create a new promise like: new Promise((resolve, reject) => {}).",
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"You can execute code with a delay with \"setTimeout(fn, delay)\"",
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"To reject a promise after a delay, \"setTimeout(() => reject('err'), delay)\"",
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"You can resolve and reject when the passed promise resolves or rejects with: \"fn(...params).then(resolve).catch(reject)\""
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],
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"sampleTestCase": "async (n) => { await new Promise(res => setTimeout(res, 100)); return n * n; }\n[5]\n50",
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"exampleTestcases": "async (n) => { await new Promise(res => setTimeout(res, 100)); return n * n; }\n[5]\n50\nasync (n) => { await new Promise(res => setTimeout(res, 100)); return n * n; }\n[5]\n150\nasync (a, b) => { await new Promise(res => setTimeout(res, 120)); return a + b; }\n[5,10]\n150\nasync () => { throw \"Error\"; }\n[]\n1000",
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