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leetcode-problemset/leetcode/originData/find-all-k-distant-indices-in-an-array.json
2022-05-02 23:44:12 +08:00

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{
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"title": "Find All K-Distant Indices in an Array",
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"content": "<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code> and two integers <code>key</code> and <code>k</code>. A <strong>k-distant index</strong> is an index <code>i</code> of <code>nums</code> for which there exists at least one index <code>j</code> such that <code>|i - j| &lt;= k</code> and <code>nums[j] == key</code>.</p>\n\n<p>Return <em>a list of all k-distant indices sorted in <strong>increasing order</strong></em>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [3,4,9,1,3,9,5], key = 9, k = 1\n<strong>Output:</strong> [1,2,3,4,5,6]\n<strong>Explanation:</strong> Here, <code>nums[2] == key</code> and <code>nums[5] == key.\n- For index 0, |0 - 2| &gt; k and |0 - 5| &gt; k, so there is no j</code> where <code>|0 - j| &lt;= k</code> and <code>nums[j] == key. Thus, 0 is not a k-distant index.\n- For index 1, |1 - 2| &lt;= k and nums[2] == key, so 1 is a k-distant index.\n- For index 2, |2 - 2| &lt;= k and nums[2] == key, so 2 is a k-distant index.\n- For index 3, |3 - 2| &lt;= k and nums[2] == key, so 3 is a k-distant index.\n- For index 4, |4 - 5| &lt;= k and nums[5] == key, so 4 is a k-distant index.\n- For index 5, |5 - 5| &lt;= k and nums[5] == key, so 5 is a k-distant index.\n- For index 6, |6 - 5| &lt;= k and nums[5] == key, so 6 is a k-distant index.\n</code>Thus, we return [1,2,3,4,5,6] which is sorted in increasing order. \n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [2,2,2,2,2], key = 2, k = 2\n<strong>Output:</strong> [0,1,2,3,4]\n<strong>Explanation:</strong> For all indices i in nums, there exists some index j such that |i - j| &lt;= k and nums[j] == key, so every index is a k-distant index. \nHence, we return [0,1,2,3,4].\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 1000</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 1000</code></li>\n\t<li><code>key</code> is an integer from the array <code>nums</code>.</li>\n\t<li><code>1 &lt;= k &lt;= nums.length</code></li>\n</ul>\n",
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"code": "class Solution(object):\n def findKDistantIndices(self, nums, key, k):\n \"\"\"\n :type nums: List[int]\n :type key: int\n :type k: int\n :rtype: List[int]\n \"\"\"\n ",
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"code": "public class Solution {\n public IList<int> FindKDistantIndices(int[] nums, int key, int k) {\n \n }\n}",
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"code": "# @param {Integer[]} nums\n# @param {Integer} key\n# @param {Integer} k\n# @return {Integer[]}\ndef find_k_distant_indices(nums, key, k)\n \nend",
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"code": "impl Solution {\n pub fn find_k_distant_indices(nums: Vec<i32>, key: i32, k: i32) -> Vec<i32> {\n \n }\n}",
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"lang": "Erlang",
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"code": "defmodule Solution do\n @spec find_k_distant_indices(nums :: [integer], key :: integer, k :: integer) :: [integer]\n def find_k_distant_indices(nums, key, k) do\n\n end\nend",
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"For every occurrence of key in nums, find all indices within distance k from it.",
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