leetcode-problemset/leetcode-cn/originData/string-rotation-lcci.json

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        "question": {
            "questionId": "100162",
            "questionFrontendId": "面试题 01.09",
            "categoryTitle": "LCCI",
            "boundTopicId": 45559,
            "title": "String Rotation LCCI",
            "titleSlug": "string-rotation-lcci",
            "content": "<p>Given two strings, <code>s1</code>&nbsp;and <code>s2</code>, write code to check if <code>s2</code> is a rotation of <code>s1</code> (e.g.,&quot;waterbottle&quot; is a rotation of&quot;erbottlewat&quot;).&nbsp;Can you use&nbsp;only one call to the method that&nbsp;checks if one word is a substring of another?</p>\r\n\r\n<p><strong>Example 1:</strong></p>\r\n\r\n<pre>\r\n<strong>Input: </strong>s1 = <span id=\"example-input-1-1\">&quot;waterbottle&quot;</span>, s2 = <span id=\"example-input-1-2\">&quot;</span>erbottlewat<span>&quot;</span>\r\n<strong>Output: </strong><span id=\"example-output-1\">True</span>\r\n</pre>\r\n\r\n<p><strong>Example 2:</strong></p>\r\n\r\n<pre>\r\n<strong>Input: </strong>s1 = &quot;aa&quot;, s2 = &quot;aba&quot;\r\n<strong>Output: </strong>False\r\n</pre>\r\n\r\n<p>&nbsp;</p>\r\n\r\n<p><strong>Note:</strong></p>\r\n\r\n<ol>\r\n\t<li><code><font face=\"monospace\">0 &lt;= s1.length, s2.length &lt;=&nbsp;</font>100000</code></li>\r\n</ol>\r\n",
            "translatedTitle": "字符串轮转",
            "translatedContent": "<p>字符串轮转。给定两个字符串<code>s1</code>和<code>s2</code>，请编写代码检查<code>s2</code>是否为<code>s1</code>旋转而成（比如，<code>waterbottle</code>是<code>erbottlewat</code>旋转后的字符串）。</p>\n\n<p><strong>示例1:</strong></p>\n\n<pre><strong> 输入</strong>：s1 = &quot;waterbottle&quot;, s2 = &quot;erbottlewat&quot;\n<strong> 输出</strong>：True\n</pre>\n\n<p><strong>示例2:</strong></p>\n\n<pre><strong> 输入</strong>：s1 = &quot;aa&quot;, s2 = &quot;aba&quot;\n<strong> 输出</strong>：False\n</pre>\n\n<ol>\n</ol>\n\n<p><strong>提示：</strong></p>\n\n<ol>\n\t<li>字符串长度在[0, 100000]范围内。</li>\n</ol>\n\n<p><strong>说明:</strong></p>\n\n<ol>\n\t<li>你能只调用一次检查子串的方法吗？</li>\n</ol>\n",
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                    "name": "String",
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            "hints": [
                "如果一个字符串是另一个字符串的旋转，那么它就是在某个特定点上的旋转。例如，字符串waterbottle在3处的旋转意味着在第三个字符处切割waterbottle，并在左半部分（wat）之前放置右半部分（erbottle）。",
                "本质上，我们是在寻找是否有一种方式可以把第一个字符串分成两部分，即x和y，如此一来，第一个字符串就是xy，第二个字符串就是yx。例如，x = wat，y = erbottle。那么，第一个字符串xy = waterbottle，第二个字符串yx = erbottlewat。",
                "想想前面的提示。再想想当你将erbottlewat与它本身连接会发生什么。你得到了erbottlewaterbottlewat。"
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