{ "data": { "question": { "questionId": "100162", "questionFrontendId": "面试题 01.09", "categoryTitle": "LCCI", "boundTopicId": 45559, "title": "String Rotation LCCI", "titleSlug": "string-rotation-lcci", "content": "

Given two strings, s1 and s2, write code to check if s2 is a rotation of s1 (e.g.,"waterbottle" is a rotation of"erbottlewat"). Can you use only one call to the method that checks if one word is a substring of another?

\r\n\r\n

Example 1:

\r\n\r\n
\r\nInput: s1 = "waterbottle", s2 = "erbottlewat"\r\nOutput: True\r\n
\r\n\r\n

Example 2:

\r\n\r\n
\r\nInput: s1 = "aa", s2 = "aba"\r\nOutput: False\r\n
\r\n\r\n

 

\r\n\r\n

Note:

\r\n\r\n
    \r\n\t
  1. 0 <= s1.length, s2.length <= 100000
    2. \r\n
\r\n", "translatedTitle": "字符串轮转", "translatedContent": "

字符串轮转。给定两个字符串s1和s2，请编写代码检查s2是否为s1旋转而成（比如，waterbottle是erbottlewat旋转后的字符串）。

\n\n

示例1:

\n\n
 输入：s1 = "waterbottle", s2 = "erbottlewat"\n 输出：True\n
\n\n

示例2:

\n\n
 输入：s1 = "aa", s2 = "aba"\n 输出：False\n
\n\n
    \n
\n\n

提示：

\n\n
    \n\t
  1. 字符串长度在[0, 100000]范围内。
    2. \n
\n\n

说明:

\n\n
    \n\t
  1. 你能只调用一次检查子串的方法吗？
    2. \n
\n", "isPaidOnly": false, "difficulty": "Easy", "likes": 116, "dislikes": 0, "isLiked": null, "similarQuestions": "[]", "contributors": [], "langToValidPlayground": "{\"cpp\": true, \"java\": true, \"python\": true, \"python3\": true, \"mysql\": false, \"mssql\": false, \"oraclesql\": false, \"c\": false, \"csharp\": false, \"javascript\": false, \"ruby\": false, \"bash\": false, \"swift\": false, \"golang\": false, \"scala\": false, \"html\": false, \"pythonml\": false, \"kotlin\": false, \"rust\": false, \"php\": false, \"typescript\": false, \"racket\": false, \"erlang\": false, \"elixir\": false}", "topicTags": [ { "name": "String", "slug": "string", "translatedName": "字符串", "__typename": "TopicTagNode" }, { "name": "String Matching", "slug": "string-matching", "translatedName": "字符串匹配", "__typename": "TopicTagNode" } ], "companyTagStats": null, "codeSnippets": [ { "lang": "C++", "langSlug": "cpp", "code": "class Solution {\npublic:\n bool isFlipedString(string s1, string s2) {\n\n }\n};", "__typename": "CodeSnippetNode" }, { "lang": "Java", "langSlug": "java", "code": "class Solution {\n public boolean isFlipedString(String s1, String s2) {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Python", "langSlug": "python", "code": "class Solution(object):\n def isFlipedString(self, s1, s2):\n \"\"\"\n :type s1: str\n :type s2: str\n :rtype: bool\n \"\"\"", "__typename": "CodeSnippetNode" }, { "lang": "Python3", "langSlug": "python3", "code": "class Solution:\n def isFlipedString(self, s1: str, s2: str) -> bool:", "__typename": "CodeSnippetNode" }, { "lang": "C", "langSlug": "c", "code": "\n\nbool isFlipedString(char* s1, char* s2){\n\n}\n", "__typename": "CodeSnippetNode" }, { "lang": "C#", "langSlug": "csharp", "code": "public class Solution {\n public bool IsFlipedString(string s1, string s2) {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "JavaScript", "langSlug": "javascript", "code": "/**\n * @param {string} s1\n * @param {string} s2\n * @return {boolean}\n */\nvar isFlipedString = function(s1, s2) {\n\n};", "__typename": "CodeSnippetNode" }, { "lang": "Ruby", "langSlug": "ruby", "code": "# @param {String} s1\n# @param {String} s2\n# @return {Boolean}\ndef is_fliped_string(s1, s2)\n\nend", "__typename": "CodeSnippetNode" }, { "lang": "Swift", "langSlug": "swift", "code": "class Solution {\n func isFlipedString(_ s1: String, _ s2: String) -> Bool {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Go", "langSlug": "golang", "code": "func isFlipedString(s1 string, s2 string) bool {\n\n}", "__typename": "CodeSnippetNode" }, { "lang": "Scala", "langSlug": "scala", "code": "object Solution {\n def isFlipedString(s1: String, s2: String): Boolean = {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Kotlin", "langSlug": "kotlin", "code": "class Solution {\n fun isFlipedString(s1: String, s2: String): Boolean {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Rust", "langSlug": "rust", "code": "impl Solution {\n pub fn is_fliped_string(s1: String, s2: String) -> bool {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "PHP", "langSlug": "php", "code": "class Solution {\n\n /**\n * @param String $s1\n * @param String $s2\n * @return Boolean\n */\n function isFlipedString($s1, $s2) {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "TypeScript", "langSlug": "typescript", "code": "function isFlipedString(s1: string, s2: string): boolean {\n\n};", "__typename": "CodeSnippetNode" }, { "lang": "Racket", "langSlug": "racket", "code": "(define/contract (is-fliped-string s1 s2)\n (-> string? string? boolean?)\n\n )", "__typename": "CodeSnippetNode" }, { "lang": "Erlang", "langSlug": "erlang", "code": "-spec is_fliped_string(S1 :: unicode:unicode_binary(), S2 :: unicode:unicode_binary()) -> boolean().\nis_fliped_string(S1, S2) ->\n .", "__typename": "CodeSnippetNode" }, { "lang": "Elixir", "langSlug": "elixir", "code": "defmodule Solution do\n @spec is_fliped_string(s1 :: String.t, s2 :: String.t) :: boolean\n def is_fliped_string(s1, s2) do\n\n end\nend", "__typename": "CodeSnippetNode" } ], "stats": "{\"totalAccepted\": \"42.7K\", \"totalSubmission\": \"77.9K\", \"totalAcceptedRaw\": 42676, \"totalSubmissionRaw\": 77883, \"acRate\": \"54.8%\"}", "hints": [ "如果一个字符串是另一个字符串的旋转，那么它就是在某个特定点上的旋转。例如，字符串waterbottle在3处的旋转意味着在第三个字符处切割waterbottle，并在左半部分（wat）之前放置右半部分（erbottle）。", "本质上，我们是在寻找是否有一种方式可以把第一个字符串分成两部分，即x和y，如此一来，第一个字符串就是xy，第二个字符串就是yx。例如，x = wat，y = erbottle。那么，第一个字符串xy = waterbottle，第二个字符串yx = erbottlewat。", "想想前面的提示。再想想当你将erbottlewat与它本身连接会发生什么。你得到了erbottlewaterbottlewat。" ], "solution": null, "status": null, "sampleTestCase": "\"waterbottle\"\n\"erbottlewat\"", "metaData": "{\"name\": \"isFlipedString\", \"params\": [{\"name\": \"s1\", \"type\": \"string\"}, {\"name\": \"s2\", \"type\": \"string\"}], \"return\": {\"type\": \"boolean\"}}", "judgerAvailable": true, "judgeType": "large", "mysqlSchemas": [], "enableRunCode": true, "envInfo": "{\"cpp\":[\"C++\",\"

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