mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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171 lines
23 KiB
JSON
171 lines
23 KiB
JSON
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"title": "Find the Maximum Divisibility Score",
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"content": "<p>You are given two <strong>0-indexed</strong> integer arrays <code>nums</code> and <code>divisors</code>.</p>\n\n<p>The <strong>divisibility score</strong> of <code>divisors[i]</code> is the number of indices <code>j</code> such that <code>nums[j]</code> is divisible by <code>divisors[i]</code>.</p>\n\n<p>Return <em>the integer</em> <code>divisors[i]</code> <em>with the maximum divisibility score</em>. If there is more than one integer with the maximum score, return the minimum of them.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [4,7,9,3,9], divisors = [5,2,3]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> The divisibility score for every element in divisors is:\nThe divisibility score of divisors[0] is 0 since no number in nums is divisible by 5.\nThe divisibility score of divisors[1] is 1 since nums[0] is divisible by 2.\nThe divisibility score of divisors[2] is 3 since nums[2], nums[3], and nums[4] are divisible by 3.\nSince divisors[2] has the maximum divisibility score, we return it.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [20,14,21,10], divisors = [5,7,5]\n<strong>Output:</strong> 5\n<strong>Explanation:</strong> The divisibility score for every element in divisors is:\nThe divisibility score of divisors[0] is 2 since nums[0] and nums[3] are divisible by 5.\nThe divisibility score of divisors[1] is 2 since nums[1] and nums[2] are divisible by 7.\nThe divisibility score of divisors[2] is 2 since nums[0] and nums[3] are divisible by 5.\nSince divisors[0], divisors[1], and divisors[2] all have the maximum divisibility score, we return the minimum of them (i.e., divisors[2]).\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [12], divisors = [10,16]\n<strong>Output:</strong> 10\n<strong>Explanation:</strong> The divisibility score for every element in divisors is:\nThe divisibility score of divisors[0] is 0 since no number in nums is divisible by 10.\nThe divisibility score of divisors[1] is 0 since no number in nums is divisible by 16.\nSince divisors[0] and divisors[1] both have the maximum divisibility score, we return the minimum of them (i.e., divisors[0]).\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length, divisors.length <= 1000</code></li>\n\t<li><code>1 <= nums[i], divisors[i] <= 10<sup>9</sup></code></li>\n</ul>\n",
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"translatedTitle": "找出可整除性得分最大的整数",
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"translatedContent": "<p>给你两个下标从 <strong>0</strong> 开始的整数数组 <code>nums</code> 和 <code>divisors</code> 。</p>\n\n<p><code>divisors[i]</code> 的 <strong>可整除性得分</strong> 等于满足 <code>nums[j]</code> 能被 <code>divisors[i]</code> 整除的下标 <code>j</code> 的数量。</p>\n\n<p>返回 <strong>可整除性得分</strong> 最大的整数 <code>divisors[i]</code> 。如果有多个整数具有最大得分,则返回数值最小的一个。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [4,7,9,3,9], divisors = [5,2,3]\n<strong>输出:</strong>3\n<strong>解释:</strong>divisors 中每个元素的可整除性得分为:\ndivisors[0] 的可整除性得分为 0 ,因为 nums 中没有任何数字能被 5 整除。\ndivisors[1] 的可整除性得分为 1 ,因为 nums[0] 能被 2 整除。 \ndivisors[2] 的可整除性得分为 3 ,因为 nums[2]、nums[3] 和 nums[4] 都能被 3 整除。 \n因此,返回 divisors[2] ,它的可整除性得分最大。\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [20,14,21,10], divisors = [5,7,5]\n<strong>输出:</strong>5\n<strong>解释:</strong>divisors 中每个元素的可整除性得分为:\ndivisors[0] 的可整除性得分为 2 ,因为 nums[0] 和 nums[3] 都能被 5 整除。\ndivisors[1] 的可整除性得分为 2 ,因为 nums[1] 和 nums[2] 都能被 7 整除。\ndivisors[2] 的可整除性得分为 2 ,因为 nums[0] 和 nums[3] 都能被5整除。 \n由于 divisors[0]、divisors[1] 和 divisors[2] 的可整除性得分都是最大的,因此,我们返回数值最小的一个,即 divisors[2] 。\n</pre>\n\n<p><strong>示例 3:</strong></p>\n\n<pre>\n<strong>输入:</strong>nums = [12], divisors = [10,16]\n<strong>输出:</strong>10\n<strong>解释:</strong>divisors 中每个元素的可整除性得分为:\ndivisors[0] 的可整除性得分为 0 ,因为 nums 中没有任何数字能被 10 整除。\ndivisors[1] 的可整除性得分为 0 ,因为 nums 中没有任何数字能被 16 整除。 \n由于 divisors[0] 和 divisors[1] 的可整除性得分都是最大的,因此,我们返回数值最小的一个,即 divisors[0] 。\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length, divisors.length <= 1000</code></li>\n\t<li><code>1 <= nums[i], divisors[i] <= 10<sup>9</sup></code></li>\n</ul>\n",
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