You are given two 0-indexed integer arrays nums and divisors.
The divisibility score of divisors[i] is the number of indices j such that nums[j] is divisible by divisors[i].
Return the integer divisors[i] with the maximum divisibility score. If there is more than one integer with the maximum score, return the minimum of them.
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Example 1:
\n\n\nInput: nums = [4,7,9,3,9], divisors = [5,2,3]\nOutput: 3\nExplanation: The divisibility score for every element in divisors is:\nThe divisibility score of divisors[0] is 0 since no number in nums is divisible by 5.\nThe divisibility score of divisors[1] is 1 since nums[0] is divisible by 2.\nThe divisibility score of divisors[2] is 3 since nums[2], nums[3], and nums[4] are divisible by 3.\nSince divisors[2] has the maximum divisibility score, we return it.\n\n\n
Example 2:
\n\n\nInput: nums = [20,14,21,10], divisors = [5,7,5]\nOutput: 5\nExplanation: The divisibility score for every element in divisors is:\nThe divisibility score of divisors[0] is 2 since nums[0] and nums[3] are divisible by 5.\nThe divisibility score of divisors[1] is 2 since nums[1] and nums[2] are divisible by 7.\nThe divisibility score of divisors[2] is 2 since nums[0] and nums[3] are divisible by 5.\nSince divisors[0], divisors[1], and divisors[2] all have the maximum divisibility score, we return the minimum of them (i.e., divisors[2]).\n\n\n
Example 3:
\n\n\nInput: nums = [12], divisors = [10,16]\nOutput: 10\nExplanation: The divisibility score for every element in divisors is:\nThe divisibility score of divisors[0] is 0 since no number in nums is divisible by 10.\nThe divisibility score of divisors[1] is 0 since no number in nums is divisible by 16.\nSince divisors[0] and divisors[1] both have the maximum divisibility score, we return the minimum of them (i.e., divisors[0]).\n\n\n
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Constraints:
\n\n1 <= nums.length, divisors.length <= 10001 <= nums[i], divisors[i] <= 109给你两个下标从 0 开始的整数数组 nums 和 divisors 。
divisors[i] 的 可整除性得分 等于满足 nums[j] 能被 divisors[i] 整除的下标 j 的数量。
返回 可整除性得分 最大的整数 divisors[i] 。如果有多个整数具有最大得分，则返回数值最小的一个。
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示例 1：
\n\n\n输入：nums = [4,7,9,3,9], divisors = [5,2,3]\n输出：3\n解释：divisors 中每个元素的可整除性得分为：\ndivisors[0] 的可整除性得分为 0 ，因为 nums 中没有任何数字能被 5 整除。\ndivisors[1] 的可整除性得分为 1 ，因为 nums[0] 能被 2 整除。 \ndivisors[2] 的可整除性得分为 3 ，因为 nums[2]、nums[3] 和 nums[4] 都能被 3 整除。 \n因此，返回 divisors[2] ，它的可整除性得分最大。\n\n\n
示例 2：
\n\n\n输入：nums = [20,14,21,10], divisors = [5,7,5]\n输出：5\n解释：divisors 中每个元素的可整除性得分为：\ndivisors[0] 的可整除性得分为 2 ，因为 nums[0] 和 nums[3] 都能被 5 整除。\ndivisors[1] 的可整除性得分为 2 ，因为 nums[1] 和 nums[2] 都能被 7 整除。\ndivisors[2] 的可整除性得分为 2 ，因为 nums[0] 和 nums[3] 都能被5整除。 \n由于 divisors[0]、divisors[1] 和 divisors[2] 的可整除性得分都是最大的，因此，我们返回数值最小的一个，即 divisors[2] 。\n\n\n
示例 3：
\n\n\n输入：nums = [12], divisors = [10,16]\n输出：10\n解释：divisors 中每个元素的可整除性得分为：\ndivisors[0] 的可整除性得分为 0 ，因为 nums 中没有任何数字能被 10 整除。\ndivisors[1] 的可整除性得分为 0 ，因为 nums 中没有任何数字能被 16 整除。 \n由于 divisors[0] 和 divisors[1] 的可整除性得分都是最大的，因此，我们返回数值最小的一个，即 divisors[0] 。\n\n\n
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提示：
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