leetcode-problemset/leetcode-cn/originData/construct-string-with-minimum-cost.json

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        "question": {
            "questionId": "3482",
            "questionFrontendId": "3213",
            "categoryTitle": "Algorithms",
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            "title": "Construct String with Minimum Cost",
            "titleSlug": "construct-string-with-minimum-cost",
            "content": "<p>You are given a string <code>target</code>, an array of strings <code>words</code>, and an integer array <code>costs</code>, both arrays of the same length.</p>\n\n<p>Imagine an empty string <code>s</code>.</p>\n\n<p>You can perform the following operation any number of times (including <strong>zero</strong>):</p>\n\n<ul>\n\t<li>Choose an index <code>i</code> in the range <code>[0, words.length - 1]</code>.</li>\n\t<li>Append <code>words[i]</code> to <code>s</code>.</li>\n\t<li>The cost of operation is <code>costs[i]</code>.</li>\n</ul>\n\n<p>Return the <strong>minimum</strong> cost to make <code>s</code> equal to <code>target</code>. If it&#39;s not possible, return <code>-1</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">target = &quot;abcdef&quot;, words = [&quot;abdef&quot;,&quot;abc&quot;,&quot;d&quot;,&quot;def&quot;,&quot;ef&quot;], costs = [100,1,1,10,5]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">7</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>The minimum cost can be achieved by performing the following operations:</p>\n\n<ul>\n\t<li>Select index 1 and append <code>&quot;abc&quot;</code> to <code>s</code> at a cost of 1, resulting in <code>s = &quot;abc&quot;</code>.</li>\n\t<li>Select index 2 and append <code>&quot;d&quot;</code> to <code>s</code> at a cost of 1, resulting in <code>s = &quot;abcd&quot;</code>.</li>\n\t<li>Select index 4 and append <code>&quot;ef&quot;</code> to <code>s</code> at a cost of 5, resulting in <code>s = &quot;abcdef&quot;</code>.</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">target = &quot;aaaa&quot;, words = [&quot;z&quot;,&quot;zz&quot;,&quot;zzz&quot;], costs = [1,10,100]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">-1</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>It is impossible to make <code>s</code> equal to <code>target</code>, so we return -1.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= target.length &lt;= 5 * 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= words.length == costs.length &lt;= 5 * 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= words[i].length &lt;= target.length</code></li>\n\t<li>The total sum of <code>words[i].length</code> is less than or equal to <code>5 * 10<sup>4</sup></code>.</li>\n\t<li><code>target</code> and <code>words[i]</code> consist only of lowercase English letters.</li>\n\t<li><code>1 &lt;= costs[i] &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
            "translatedTitle": "最小代价构造字符串",
            "translatedContent": "<p>给你一个字符串 <code>target</code>、一个字符串数组 <code>words</code> 以及一个整数数组 <code>costs</code>，这两个数组长度相同。</p>\n\n<p>设想一个空字符串 <code>s</code>。</p>\n\n<p>你可以执行以下操作任意次数（包括<strong>零</strong>次）：</p>\n\n<ul>\n\t<li>选择一个在范围&nbsp; <code>[0, words.length - 1]</code> 的索引 <code>i</code>。</li>\n\t<li>将 <code>words[i]</code> 追加到 <code>s</code>。</li>\n\t<li>该操作的成本是 <code>costs[i]</code>。</li>\n</ul>\n\n<p>返回使 <code>s</code> 等于 <code>target</code> 的 <strong>最小</strong> 成本。如果不可能，返回 <code>-1</code>。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">target = \"abcdef\", words = [\"abdef\",\"abc\",\"d\",\"def\",\"ef\"], costs = [100,1,1,10,5]</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">7</span></p>\n\n<p><strong>解释：</strong></p>\n\n<ul>\n\t<li>选择索引 1 并以成本 1 将 <code>\"abc\"</code> 追加到 <code>s</code>，得到 <code>s = \"abc\"</code>。</li>\n\t<li>选择索引 2 并以成本 1 将 <code>\"d\"</code> 追加到 <code>s</code>，得到 <code>s = \"abcd\"</code>。</li>\n\t<li>选择索引 4 并以成本 5 将 <code>\"ef\"</code> 追加到 <code>s</code>，得到 <code>s = \"abcdef\"</code>。</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">target = \"aaaa\", words = [\"z\",\"zz\",\"zzz\"], costs = [1,10,100]</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">-1</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>无法使 <code>s</code> 等于 <code>target</code>，因此返回 -1。</p>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= target.length &lt;= 5 * 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= words.length == costs.length &lt;= 5 * 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= words[i].length &lt;= target.length</code></li>\n\t<li>所有 <code>words[i].length</code> 的总和小于或等于 <code>5 * 10<sup>4</sup></code></li>\n\t<li><code>target</code> 和 <code>words[i]</code> 仅由小写英文字母组成。</li>\n\t<li><code>1 &lt;= costs[i] &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
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