You are given a string target, an array of strings words, and an integer array costs, both arrays of the same length.
Imagine an empty string s.
You can perform the following operation any number of times (including zero):
\n\ni in the range [0, words.length - 1].words[i] to s.costs[i].Return the minimum cost to make s equal to target. If it's not possible, return -1.
\n
Example 1:
\n\nInput: target = "abcdef", words = ["abdef","abc","d","def","ef"], costs = [100,1,1,10,5]
\n\nOutput: 7
\n\nExplanation:
\n\nThe minimum cost can be achieved by performing the following operations:
\n\n"abc" to s at a cost of 1, resulting in s = "abc"."d" to s at a cost of 1, resulting in s = "abcd"."ef" to s at a cost of 5, resulting in s = "abcdef".Example 2:
\n\nInput: target = "aaaa", words = ["z","zz","zzz"], costs = [1,10,100]
\n\nOutput: -1
\n\nExplanation:
\n\nIt is impossible to make s equal to target, so we return -1.
\n
Constraints:
\n\n1 <= target.length <= 5 * 1041 <= words.length == costs.length <= 5 * 1041 <= words[i].length <= target.lengthwords[i].length is less than or equal to 5 * 104.target and words[i] consist only of lowercase English letters.1 <= costs[i] <= 104给你一个字符串 target、一个字符串数组 words 以及一个整数数组 costs，这两个数组长度相同。
设想一个空字符串 s。
你可以执行以下操作任意次数（包括零次）：
\n\n[0, words.length - 1] 的索引 i。words[i] 追加到 s。costs[i]。返回使 s 等于 target 的 最小 成本。如果不可能，返回 -1。
\n\n
示例 1：
\n\n输入： target = \"abcdef\", words = [\"abdef\",\"abc\",\"d\",\"def\",\"ef\"], costs = [100,1,1,10,5]
\n\n输出： 7
\n\n解释：
\n\n\"abc\" 追加到 s，得到 s = \"abc\"。\"d\" 追加到 s，得到 s = \"abcd\"。\"ef\" 追加到 s，得到 s = \"abcdef\"。示例 2：
\n\n输入： target = \"aaaa\", words = [\"z\",\"zz\",\"zzz\"], costs = [1,10,100]
\n\n输出： -1
\n\n解释：
\n\n无法使 s 等于 target，因此返回 -1。
\n\n
提示：
\n\n1 <= target.length <= 5 * 1041 <= words.length == costs.length <= 5 * 1041 <= words[i].length <= target.lengthwords[i].length 的总和小于或等于 5 * 104target 和 words[i] 仅由小写英文字母组成。1 <= costs[i] <= 104\\u7248\\u672c\\uff1a \\u7f16\\u8bd1\\u65f6\\uff0c\\u5c06\\u4f1a\\u91c7\\u7528 \\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\"],\"java\":[\"Java\",\" \\u7248\\u672c\\uff1a \\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u88ab\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u5305\\u542b Pair \\u7c7b: https:\\/\\/docs.oracle.com\\/javase\\/8\\/javafx\\/api\\/javafx\\/util\\/Pair.html <\\/p>\"],\"python\":[\"Python\",\" \\u7248\\u672c\\uff1a \\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982\\uff1aarray<\\/a>, bisect<\\/a>, collections<\\/a>\\u3002\\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u6ce8\\u610f Python 2.7 \\u5c06\\u57282020\\u5e74\\u540e\\u4e0d\\u518d\\u7ef4\\u62a4<\\/a>\\u3002 \\u5982\\u60f3\\u4f7f\\u7528\\u6700\\u65b0\\u7248\\u7684Python\\uff0c\\u8bf7\\u9009\\u62e9Python 3\\u3002<\\/p>\"],\"c\":[\"C\",\" \\u7248\\u672c\\uff1a \\u7f16\\u8bd1\\u65f6\\uff0c\\u5c06\\u4f1a\\u91c7\\u7528 \\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u5982\\u60f3\\u4f7f\\u7528\\u54c8\\u5e0c\\u8868\\u8fd0\\u7b97, \\u60a8\\u53ef\\u4ee5\\u4f7f\\u7528 uthash<\\/a>\\u3002 \\\"uthash.h\\\"\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5bfc\\u5165\\u3002\\u8bf7\\u770b\\u5982\\u4e0b\\u793a\\u4f8b:<\\/p>\\r\\n\\r\\n 1. 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