mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
190 lines
23 KiB
JSON
190 lines
23 KiB
JSON
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"questionId": "100353",
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"questionFrontendId": "面试题 16.13",
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"categoryTitle": "LCCI",
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"boundTopicId": 91327,
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"title": "Bisect Squares LCCI",
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"titleSlug": "bisect-squares-lcci",
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"content": "<p>Given two squares on a two-dimensional plane, find a line that would cut these two squares in half. Assume that the top and the bottom sides of the square run parallel to the x-axis.</p>\r\n\r\n<p>Each square consists of three values, the coordinate of bottom left corner <code>[X,Y] = [square[0],square[1]]</code>, and the side length of the square <code>square[2]</code>. The line will intersect to the two squares in four points. Return the coordinates of two intersection points <code>[X<sub>1</sub>,Y<sub>1</sub>]</code> and <code>[X<sub>2</sub>,Y<sub>2</sub>]</code> that the forming segment covers the other two intersection points in format of <code>{X<sub>1</sub>,Y<sub>1</sub>,X<sub>2</sub>,Y<sub>2</sub>}</code>. If <code>X<sub>1</sub> != X<sub>2</sub></code>, there should be <code>X<sub>1</sub> < X<sub>2</sub></code>, otherwise there should be <code>Y<sub>1</sub> <= Y<sub>2</sub></code>.</p>\r\n\r\n<p>If there are more than one line that can cut these two squares in half, return the one that has biggest slope (slope of a line parallel to the y-axis is considered as infinity).</p>\r\n\r\n<p><strong>Example: </strong></p>\r\n\r\n<pre>\r\n<strong>Input: </strong>\r\nsquare1 = {-1, -1, 2}\r\nsquare2 = {0, -1, 2}\r\n<strong>Output:</strong> {-1,0,2,0}\r\n<strong>Explanation:</strong> y = 0 is the line that can cut these two squares in half.\r\n</pre>\r\n\r\n<p><strong>Note: </strong></p>\r\n\r\n<ul>\r\n\t<li><code>square.length == 3</code></li>\r\n\t<li><code>square[2] > 0</code></li>\r\n</ul>\r\n",
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"translatedTitle": "平分正方形",
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"translatedContent": "<p>给定两个正方形及一个二维平面。请找出将这两个正方形分割成两半的一条直线。假设正方形顶边和底边与 x 轴平行。</p>\n\n<p>每个正方形的数据<code>square</code>包含3个数值,正方形的左下顶点坐标<code>[X,Y] = [square[0],square[1]]</code>,以及正方形的边长<code>square[2]</code>。所求直线穿过两个正方形会形成4个交点,请返回4个交点形成线段的两端点坐标(两个端点即为4个交点中距离最远的2个点,这2个点所连成的线段一定会穿过另外2个交点)。2个端点坐标<code>[X<sub>1</sub>,Y<sub>1</sub>]</code>和<code>[X<sub>2</sub>,Y<sub>2</sub>]</code>的返回格式为<code>{X<sub>1</sub>,Y<sub>1</sub>,X<sub>2</sub>,Y<sub>2</sub>}</code>,要求若<code>X<sub>1</sub> != X<sub>2</sub></code>,需保证<code>X<sub>1</sub> < X<sub>2</sub></code>,否则需保证<code>Y<sub>1</sub> <= Y<sub>2</sub></code>。</p>\n\n<p>若同时有多条直线满足要求,则选择斜率最大的一条计算并返回(与Y轴平行的直线视为斜率无穷大)。</p>\n\n<p><strong>示例:</strong></p>\n\n<pre><strong>输入:</strong>\nsquare1 = {-1, -1, 2}\nsquare2 = {0, -1, 2}\n<strong>输出:</strong> {-1,0,2,0}\n<strong>解释:</strong> 直线 y = 0 能将两个正方形同时分为等面积的两部分,返回的两线段端点为[-1,0]和[2,0]\n</pre>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>square.length == 3</code></li>\n\t<li><code>square[2] > 0</code></li>\n</ul>\n",
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"code": "class Solution {\npublic:\n vector<double> cutSquares(vector<int>& square1, vector<int>& square2) {\n\n }\n};",
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"code": "class Solution {\n\n /**\n * @param Integer[] $square1\n * @param Integer[] $square2\n * @return Float[]\n */\n function cutSquares($square1, $square2) {\n\n }\n}",
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"code": "# @param {Integer[]} square1\n# @param {Integer[]} square2\n# @return {Float[]}\ndef cut_squares(square1, square2)\n\nend",
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"画一个正方形和一些把它切成两半的线。这些线位于哪里?",
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"任何把正方形切成两半的直线都穿过正方形的中心。那你怎么才能找到一条把两个正方形切成两半的线呢?",
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"要将两个正方形切成两半,这条线必须穿过这两个正方形的中心。",
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"给定一条直线(斜率和y轴截距),你能找到它与另一条直线的交点吗?"
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