Given two squares on a two-dimensional plane, find a line that would cut these two squares in half. Assume that the top and the bottom sides of the square run parallel to the x-axis.
\r\n\r\nEach square consists of three values, the coordinate of bottom left corner [X,Y] = [square[0],square[1]], and the side length of the square square[2]. The line will intersect to the two squares in four points. Return the coordinates of two intersection points [X1,Y1] and [X2,Y2] that the forming segment covers the other two intersection points in format of {X1,Y1,X2,Y2}. If X1 != X2, there should be X1 < X2, otherwise there should be Y1 <= Y2.
If there are more than one line that can cut these two squares in half, return the one that has biggest slope (slope of a line parallel to the y-axis is considered as infinity).
\r\n\r\nExample:
\r\n\r\n\r\nInput: \r\nsquare1 = {-1, -1, 2}\r\nsquare2 = {0, -1, 2}\r\nOutput: {-1,0,2,0}\r\nExplanation: y = 0 is the line that can cut these two squares in half.\r\n\r\n\r\nNote:
\r\n\r\nsquare.length == 3square[2] > 0给定两个正方形及一个二维平面。请找出将这两个正方形分割成两半的一条直线。假设正方形顶边和底边与 x 轴平行。
\n\n每个正方形的数据square包含3个数值，正方形的左下顶点坐标[X,Y] = [square[0],square[1]]，以及正方形的边长square[2]。所求直线穿过两个正方形会形成4个交点，请返回4个交点形成线段的两端点坐标（两个端点即为4个交点中距离最远的2个点，这2个点所连成的线段一定会穿过另外2个交点）。2个端点坐标[X1,Y1]和[X2,Y2]的返回格式为{X1,Y1,X2,Y2}，要求若X1 != X2，需保证X1 < X2，否则需保证Y1 <= Y2。
若同时有多条直线满足要求，则选择斜率最大的一条计算并返回（与Y轴平行的直线视为斜率无穷大）。
\n\n示例：
\n\n输入：\nsquare1 = {-1, -1, 2}\nsquare2 = {0, -1, 2}\n输出： {-1,0,2,0}\n解释： 直线 y = 0 能将两个正方形同时分为等面积的两部分，返回的两线段端点为[-1,0]和[2,0]\n\n\n提示：
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