mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
183 lines
19 KiB
JSON
183 lines
19 KiB
JSON
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"questionId": "1326",
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"questionFrontendId": "1862",
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"categoryTitle": "Algorithms",
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"boundTopicId": 772200,
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"title": "Sum of Floored Pairs",
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"content": "<p>Given an integer array <code>nums</code>, return the sum of <code>floor(nums[i] / nums[j])</code> for all pairs of indices <code>0 <= i, j < nums.length</code> in the array. Since the answer may be too large, return it <strong>modulo</strong> <code>10<sup>9</sup> + 7</code>.</p>\n\n<p>The <code>floor()</code> function returns the integer part of the division.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [2,5,9]\n<strong>Output:</strong> 10\n<strong>Explanation:</strong>\nfloor(2 / 5) = floor(2 / 9) = floor(5 / 9) = 0\nfloor(2 / 2) = floor(5 / 5) = floor(9 / 9) = 1\nfloor(5 / 2) = 2\nfloor(9 / 2) = 4\nfloor(9 / 5) = 1\nWe calculate the floor of the division for every pair of indices in the array then sum them up.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [7,7,7,7,7,7,7]\n<strong>Output:</strong> 49\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= nums[i] <= 10<sup>5</sup></code></li>\n</ul>\n",
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"translatedTitle": "向下取整数对和",
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"translatedContent": "<p>给你一个整数数组 <code>nums</code> ，请你返回所有下标对 <code>0 <= i, j < nums.length</code> 的 <code>floor(nums[i] / nums[j])</code> 结果之和。由于答案可能会很大，请你返回答案对<code>10<sup>9</sup> + 7</code> <strong>取余</strong> 的结果。</p>\n\n<p>函数 <code>floor()</code> 返回输入数字的整数部分。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><b>输入：</b>nums = [2,5,9]\n<b>输出：</b>10\n<strong>解释：</strong>\nfloor(2 / 5) = floor(2 / 9) = floor(5 / 9) = 0\nfloor(2 / 2) = floor(5 / 5) = floor(9 / 9) = 1\nfloor(5 / 2) = 2\nfloor(9 / 2) = 4\nfloor(9 / 5) = 1\n我们计算每一个数对商向下取整的结果并求和得到 10 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><b>输入：</b>nums = [7,7,7,7,7,7,7]\n<b>输出：</b>49\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= nums[i] <= 10<sup>5</sup></code></li>\n</ul>\n",
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"Find the frequency (number of occurrences) of all elements in the array.",
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