Given an integer array nums, return the sum of floor(nums[i] / nums[j]) for all pairs of indices 0 <= i, j < nums.length in the array. Since the answer may be too large, return it modulo 109 + 7.
The floor() function returns the integer part of the division.
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Example 1:
\n\n\nInput: nums = [2,5,9]\nOutput: 10\nExplanation:\nfloor(2 / 5) = floor(2 / 9) = floor(5 / 9) = 0\nfloor(2 / 2) = floor(5 / 5) = floor(9 / 9) = 1\nfloor(5 / 2) = 2\nfloor(9 / 2) = 4\nfloor(9 / 5) = 1\nWe calculate the floor of the division for every pair of indices in the array then sum them up.\n\n\n
Example 2:
\n\n\nInput: nums = [7,7,7,7,7,7,7]\nOutput: 49\n\n\n
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Constraints:
\n\n1 <= nums.length <= 1051 <= nums[i] <= 105给你一个整数数组 nums ，请你返回所有下标对 0 <= i, j < nums.length 的 floor(nums[i] / nums[j]) 结果之和。由于答案可能会很大，请你返回答案对109 + 7 取余 的结果。
函数 floor() 返回输入数字的整数部分。
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示例 1：
\n\n输入：nums = [2,5,9]\n输出：10\n解释：\nfloor(2 / 5) = floor(2 / 9) = floor(5 / 9) = 0\nfloor(2 / 2) = floor(5 / 5) = floor(9 / 9) = 1\nfloor(5 / 2) = 2\nfloor(9 / 2) = 4\nfloor(9 / 5) = 1\n我们计算每一个数对商向下取整的结果并求和得到 10 。\n\n\n
示例 2：
\n\n输入：nums = [7,7,7,7,7,7,7]\n输出：49\n\n\n
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提示：
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