mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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174 lines
22 KiB
JSON
174 lines
22 KiB
JSON
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"title": "Circular Array Loop",
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"content": "<p>You are playing a game involving a <strong>circular</strong> array of non-zero integers <code>nums</code>. Each <code>nums[i]</code> denotes the number of indices forward/backward you must move if you are located at index <code>i</code>:</p>\n\n<ul>\n\t<li>If <code>nums[i]</code> is positive, move <code>nums[i]</code> steps <strong>forward</strong>, and</li>\n\t<li>If <code>nums[i]</code> is negative, move <code>nums[i]</code> steps <strong>backward</strong>.</li>\n</ul>\n\n<p>Since the array is <strong>circular</strong>, you may assume that moving forward from the last element puts you on the first element, and moving backwards from the first element puts you on the last element.</p>\n\n<p>A <strong>cycle</strong> in the array consists of a sequence of indices <code>seq</code> of length <code>k</code> where:</p>\n\n<ul>\n\t<li>Following the movement rules above results in the repeating index sequence <code>seq[0] -> seq[1] -> ... -> seq[k - 1] -> seq[0] -> ...</code></li>\n\t<li>Every <code>nums[seq[j]]</code> is either <strong>all positive</strong> or <strong>all negative</strong>.</li>\n\t<li><code>k > 1</code></li>\n</ul>\n\n<p>Return <code>true</code><em> if there is a <strong>cycle</strong> in </em><code>nums</code><em>, or </em><code>false</code><em> otherwise</em>.</p>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [2,-1,1,2,2]\n<strong>Output:</strong> true\n<strong>Explanation:</strong>\nThere is a cycle from index 0 -> 2 -> 3 -> 0 -> ...\nThe cycle's length is 3.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [-1,2]\n<strong>Output:</strong> false\n<strong>Explanation:</strong>\nThe sequence from index 1 -> 1 -> 1 -> ... is not a cycle because the sequence's length is 1.\nBy definition the sequence's length must be strictly greater than 1 to be a cycle.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [-2,1,-1,-2,-2]\n<strong>Output:</strong> false\n<strong>Explanation:</strong>\nThe sequence from index 1 -> 2 -> 1 -> ... is not a cycle because nums[1] is positive, but nums[2] is negative.\nEvery nums[seq[j]] must be either all positive or all negative.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 5000</code></li>\n\t<li><code>-1000 <= nums[i] <= 1000</code></li>\n\t<li><code>nums[i] != 0</code></li>\n</ul>\n\n<p> </p>\n<p><strong>Follow up:</strong> Could you solve it in <code>O(n)</code> time complexity and <code>O(1)</code> extra space complexity?</p>\n",
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"translatedTitle": "环形数组是否存在循环",
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"translatedContent": "<p>存在一个不含 <code>0</code> 的<strong> 环形 </strong>数组 <code>nums</code> ，每个 <code>nums[i]</code> 都表示位于下标 <code>i</code> 的角色应该向前或向后移动的下标个数：</p>\n\n<ul>\n\t<li>如果 <code>nums[i]</code> 是正数，<strong>向前</strong>（下标递增方向）移动 <code>|nums[i]|</code> 步</li>\n\t<li>如果 <code>nums[i]</code> 是负数，<strong>向后</strong>（下标递减方向）移动 <code>|nums[i]|</code> 步</li>\n</ul>\n\n<p>因为数组是 <strong>环形</strong> 的，所以可以假设从最后一个元素向前移动一步会到达第一个元素，而第一个元素向后移动一步会到达最后一个元素。</p>\n\n<p>数组中的 <strong>循环</strong> 由长度为 <code>k</code> 的下标序列 <code>seq</code> 标识：</p>\n\n<ul>\n\t<li>遵循上述移动规则将导致一组重复下标序列 <code>seq[0] -> seq[1] -> ... -> seq[k - 1] -> seq[0] -> ...</code></li>\n\t<li>所有 <code>nums[seq[j]]</code> 应当不是 <strong>全正</strong> 就是 <strong>全负</strong></li>\n\t<li><code>k > 1</code></li>\n</ul>\n\n<p>如果 <code>nums</code> 中存在循环，返回 <code>true</code> ；否则，返回<em> </em><code>false</code><em> </em>。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [2,-1,1,2,2]\n<strong>输出：</strong>true\n<strong>解释：</strong>存在循环，按下标 0 -> 2 -> 3 -> 0 。循环长度为 3 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [-1,2]\n<strong>输出：</strong>false\n<strong>解释：</strong>按下标 1 -> 1 -> 1 ... 的运动无法构成循环，因为循环的长度为 1 。根据定义，循环的长度必须大于 1 。\n</pre>\n\n<p><strong>示例 3:</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [-2,1,-1,-2,-2]\n<strong>输出：</strong>false\n<strong>解释：</strong>按下标 1 -> 2 -> 1 -> ... 的运动无法构成循环，因为 nums[1] 是正数，而 nums[2] 是负数。\n所有 nums[seq[j]] 应当不是全正就是全负。</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= nums.length <= 5000</code></li>\n\t<li><code>-1000 <= nums[i] <= 1000</code></li>\n\t<li><code>nums[i] != 0</code></li>\n</ul>\n\n<p> </p>\n\n<p><strong>进阶：</strong>你能设计一个时间复杂度为 <code>O(n)</code> 且额外空间复杂度为 <code>O(1)</code> 的算法吗？</p>\n",
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