You are playing a game involving a circular array of non-zero integers nums. Each nums[i] denotes the number of indices forward/backward you must move if you are located at index i:
nums[i] is positive, move nums[i] steps forward, andnums[i] is negative, move nums[i] steps backward.Since the array is circular, you may assume that moving forward from the last element puts you on the first element, and moving backwards from the first element puts you on the last element.
\n\nA cycle in the array consists of a sequence of indices seq of length k where:
seq[0] -> seq[1] -> ... -> seq[k - 1] -> seq[0] -> ...nums[seq[j]] is either all positive or all negative.k > 1Return true if there is a cycle in nums, or false otherwise.
\n
Example 1:
\n\n\nInput: nums = [2,-1,1,2,2]\nOutput: true\nExplanation:\nThere is a cycle from index 0 -> 2 -> 3 -> 0 -> ...\nThe cycle's length is 3.\n\n\n
Example 2:
\n\n\nInput: nums = [-1,2]\nOutput: false\nExplanation:\nThe sequence from index 1 -> 1 -> 1 -> ... is not a cycle because the sequence's length is 1.\nBy definition the sequence's length must be strictly greater than 1 to be a cycle.\n\n\n
Example 3:
\n\n\nInput: nums = [-2,1,-1,-2,-2]\nOutput: false\nExplanation:\nThe sequence from index 1 -> 2 -> 1 -> ... is not a cycle because nums[1] is positive, but nums[2] is negative.\nEvery nums[seq[j]] must be either all positive or all negative.\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 5000-1000 <= nums[i] <= 1000nums[i] != 0\n
Follow up: Could you solve it in O(n) time complexity and O(1) extra space complexity?
存在一个不含 0 的 环形 数组 nums ，每个 nums[i] 都表示位于下标 i 的角色应该向前或向后移动的下标个数：
nums[i] 是正数，向前（下标递增方向）移动 |nums[i]| 步nums[i] 是负数，向后（下标递减方向）移动 |nums[i]| 步因为数组是 环形 的，所以可以假设从最后一个元素向前移动一步会到达第一个元素，而第一个元素向后移动一步会到达最后一个元素。
\n\n数组中的 循环 由长度为 k 的下标序列 seq 标识：
seq[0] -> seq[1] -> ... -> seq[k - 1] -> seq[0] -> ...nums[seq[j]] 应当不是 全正 就是 全负k > 1如果 nums 中存在循环，返回 true ；否则，返回 false 。
\n\n
示例 1：
\n\n\n输入：nums = [2,-1,1,2,2]\n输出：true\n解释：存在循环，按下标 0 -> 2 -> 3 -> 0 。循环长度为 3 。\n\n\n
示例 2：
\n\n\n输入：nums = [-1,2]\n输出：false\n解释：按下标 1 -> 1 -> 1 ... 的运动无法构成循环，因为循环的长度为 1 。根据定义，循环的长度必须大于 1 。\n\n\n
示例 3:
\n\n\n输入：nums = [-2,1,-1,-2,-2]\n输出：false\n解释：按下标 1 -> 2 -> 1 -> ... 的运动无法构成循环，因为 nums[1] 是正数，而 nums[2] 是负数。\n所有 nums[seq[j]] 应当不是全正就是全负。\n\n
\n\n
提示：
\n\n1 <= nums.length <= 5000-1000 <= nums[i] <= 1000nums[i] != 0\n\n
进阶：你能设计一个时间复杂度为 O(n) 且额外空间复杂度为 O(1) 的算法吗？
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