leetcode-problemset/leetcode-cn/originData/longest-common-suffix-queries.json

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        "question": {
            "questionId": "3376",
            "questionFrontendId": "3093",
            "categoryTitle": "Algorithms",
            "boundTopicId": 2701673,
            "title": "Longest Common Suffix Queries",
            "titleSlug": "longest-common-suffix-queries",
            "content": "<p>You are given two arrays of strings <code>wordsContainer</code> and <code>wordsQuery</code>.</p>\n\n<p>For each <code>wordsQuery[i]</code>, you need to find a string from <code>wordsContainer</code> that has the <strong>longest common suffix</strong> with <code>wordsQuery[i]</code>. If there are two or more strings in <code>wordsContainer</code> that share the longest common suffix, find the string that is the <strong>smallest</strong> in length. If there are two or more such strings that have the <strong>same</strong> smallest length, find the one that occurred <strong>earlier</strong> in <code>wordsContainer</code>.</p>\n\n<p>Return <em>an array of integers </em><code>ans</code><em>, where </em><code>ans[i]</code><em> is the index of the string in </em><code>wordsContainer</code><em> that has the <strong>longest common suffix</strong> with </em><code>wordsQuery[i]</code><em>.</em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">wordsContainer = [&quot;abcd&quot;,&quot;bcd&quot;,&quot;xbcd&quot;], wordsQuery = [&quot;cd&quot;,&quot;bcd&quot;,&quot;xyz&quot;]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[1,1,1]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>Let&#39;s look at each <code>wordsQuery[i]</code> separately:</p>\n\n<ul>\n\t<li>For <code>wordsQuery[0] = &quot;cd&quot;</code>, strings from <code>wordsContainer</code> that share the longest common suffix <code>&quot;cd&quot;</code> are at indices 0, 1, and 2. Among these, the answer is the string at index 1 because it has the shortest length of 3.</li>\n\t<li>For <code>wordsQuery[1] = &quot;bcd&quot;</code>, strings from <code>wordsContainer</code> that share the longest common suffix <code>&quot;bcd&quot;</code> are at indices 0, 1, and 2. Among these, the answer is the string at index 1 because it has the shortest length of 3.</li>\n\t<li>For <code>wordsQuery[2] = &quot;xyz&quot;</code>, there is no string from <code>wordsContainer</code> that shares a common suffix. Hence the longest common suffix is <code>&quot;&quot;</code>, that is shared with strings at index 0, 1, and 2. Among these, the answer is the string at index 1 because it has the shortest length of 3.</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">wordsContainer = [&quot;abcdefgh&quot;,&quot;poiuygh&quot;,&quot;ghghgh&quot;], wordsQuery = [&quot;gh&quot;,&quot;acbfgh&quot;,&quot;acbfegh&quot;]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[2,0,2]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>Let&#39;s look at each <code>wordsQuery[i]</code> separately:</p>\n\n<ul>\n\t<li>For <code>wordsQuery[0] = &quot;gh&quot;</code>, strings from <code>wordsContainer</code> that share the longest common suffix <code>&quot;gh&quot;</code> are at indices 0, 1, and 2. Among these, the answer is the string at index 2 because it has the shortest length of 6.</li>\n\t<li>For <code>wordsQuery[1] = &quot;acbfgh&quot;</code>, only the string at index 0 shares the longest common suffix <code>&quot;fgh&quot;</code>. Hence it is the answer, even though the string at index 2 is shorter.</li>\n\t<li>For <code>wordsQuery[2] = &quot;acbfegh&quot;</code>, strings from <code>wordsContainer</code> that share the longest common suffix <code>&quot;gh&quot;</code> are at indices 0, 1, and 2. Among these, the answer is the string at index 2 because it has the shortest length of 6.</li>\n</ul>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= wordsContainer.length, wordsQuery.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= wordsContainer[i].length &lt;= 5 * 10<sup>3</sup></code></li>\n\t<li><code>1 &lt;= wordsQuery[i].length &lt;= 5 * 10<sup>3</sup></code></li>\n\t<li><code>wordsContainer[i]</code> consists only of lowercase English letters.</li>\n\t<li><code>wordsQuery[i]</code> consists only of lowercase English letters.</li>\n\t<li>Sum of <code>wordsContainer[i].length</code> is at most <code>5 * 10<sup>5</sup></code>.</li>\n\t<li>Sum of <code>wordsQuery[i].length</code> is at most <code>5 * 10<sup>5</sup></code>.</li>\n</ul>\n",
            "translatedTitle": "最长公共后缀查询",
            "translatedContent": "<p>给你两个字符串数组&nbsp;<code>wordsContainer</code> 和&nbsp;<code>wordsQuery</code>&nbsp;。</p>\n\n<p>对于每个&nbsp;<code>wordsQuery[i]</code>&nbsp;，你需要从&nbsp;<code>wordsContainer</code>&nbsp;中找到一个与&nbsp;<code>wordsQuery[i]</code>&nbsp;有&nbsp;<strong>最长公共后缀</strong>&nbsp;的字符串。如果 <code>wordsContainer</code>&nbsp;中有两个或者更多字符串有最长公共后缀，那么答案为长度<strong>&nbsp;最短</strong>&nbsp;的。如果有超过两个字符串有&nbsp;<strong>相同</strong>&nbsp;最短长度，那么答案为它们在&nbsp;<code>wordsContainer</code>&nbsp;中出现&nbsp;<strong>更早</strong>&nbsp;的一个。</p>\n\n<p>请你返回一个整数数组<em>&nbsp;</em><code>ans</code>&nbsp;，其中<em>&nbsp;</em><code>ans[i]</code>是<em>&nbsp;</em><code>wordsContainer</code>中与&nbsp;<code>wordsQuery[i]</code>&nbsp;有&nbsp;<strong>最长公共后缀</strong>&nbsp;字符串的下标。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入：</b>wordsContainer = [\"abcd\",\"bcd\",\"xbcd\"], wordsQuery = [\"cd\",\"bcd\",\"xyz\"]</span></p>\n\n<p><span class=\"example-io\"><b>输出：</b>[1,1,1]</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>我们分别来看每一个&nbsp;<code>wordsQuery[i]</code>&nbsp;：</p>\n\n<ul>\n\t<li>对于&nbsp;<code>wordsQuery[0] = \"cd\"</code>&nbsp;，<code>wordsContainer</code>&nbsp;中有最长公共后缀&nbsp;<code>\"cd\"</code>&nbsp;的字符串下标分别为&nbsp;0 ，1 和&nbsp;2 。这些字符串中，答案是下标为 1 的字符串，因为它的长度为 3 ，是最短的字符串。</li>\n\t<li>对于&nbsp;<code>wordsQuery[1] = \"bcd\"</code>&nbsp;，<code>wordsContainer</code>&nbsp;中有最长公共后缀&nbsp;<code>\"bcd\"</code>&nbsp;的字符串下标分别为 0 ，1 和 2 。这些字符串中，答案是下标为 1 的字符串，因为它的长度为 3 ，是最短的字符串。</li>\n\t<li>对于&nbsp;<code>wordsQuery[2] = \"xyz\"</code>&nbsp;，<code>wordsContainer</code>&nbsp;中没有字符串跟它有公共后缀，所以最长公共后缀为&nbsp;<code>\"\"</code>&nbsp;，下标为&nbsp;0 ，1 和 2 的字符串都得到这一公共后缀。这些字符串中，&nbsp;答案是下标为 1 的字符串，因为它的长度为 3 ，是最短的字符串。</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入：</b>wordsContainer = [\"abcdefgh\",\"poiuygh\",\"ghghgh\"], wordsQuery = [\"gh\",\"acbfgh\",\"acbfegh\"]</span></p>\n\n<p><span class=\"example-io\"><b>输出：</b>[2,0,2]</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>我们分别来看每一个&nbsp;<code>wordsQuery[i]</code>&nbsp;：</p>\n\n<ul>\n\t<li>对于&nbsp;<code>wordsQuery[0] = \"gh\"</code>&nbsp;，<code>wordsContainer</code>&nbsp;中有最长公共后缀&nbsp;<code>\"gh\"</code>&nbsp;的字符串下标分别为 0 ，1 和 2 。这些字符串中，答案是下标为 2 的字符串，因为它的长度为 6 ，是最短的字符串。</li>\n\t<li>对于&nbsp;<code>wordsQuery[1] = \"acbfgh\"</code>&nbsp;，只有下标为 0 的字符串有最长公共后缀&nbsp;<code>\"fgh\"</code>&nbsp;。所以尽管下标为 2 的字符串是最短的字符串，但答案是 0 。</li>\n\t<li>对于&nbsp;<code>wordsQuery[2] = \"acbfegh\"</code>&nbsp;，<code>wordsContainer</code>&nbsp;中有最长公共后缀&nbsp;<code>\"gh\"</code>&nbsp;的字符串下标分别为 0 ，1 和 2 。这些字符串中，答案是下标为 2 的字符串，因为它的长度为 6 ，是最短的字符串。</li>\n</ul>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= wordsContainer.length, wordsQuery.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= wordsContainer[i].length &lt;= 5 * 10<sup>3</sup></code></li>\n\t<li><code>1 &lt;= wordsQuery[i].length &lt;= 5 * 10<sup>3</sup></code></li>\n\t<li><code>wordsContainer[i]</code>&nbsp;只包含小写英文字母。</li>\n\t<li><code>wordsQuery[i]</code>&nbsp;只包含小写英文字母。</li>\n\t<li><code>wordsContainer[i].length</code>&nbsp;的和至多为&nbsp;<code>5 * 10<sup>5</sup></code>&nbsp;。</li>\n\t<li><code>wordsQuery[i].length</code>&nbsp;的和至多为&nbsp;<code>5 * 10<sup>5</sup></code>&nbsp;。</li>\n</ul>\n",
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