You are given two arrays of strings wordsContainer and wordsQuery.
For each wordsQuery[i], you need to find a string from wordsContainer that has the longest common suffix with wordsQuery[i]. If there are two or more strings in wordsContainer that share the longest common suffix, find the string that is the smallest in length. If there are two or more such strings that have the same smallest length, find the one that occurred earlier in wordsContainer.
Return an array of integers ans, where ans[i] is the index of the string in wordsContainer that has the longest common suffix with wordsQuery[i].
\n
Example 1:
\n\nInput: wordsContainer = ["abcd","bcd","xbcd"], wordsQuery = ["cd","bcd","xyz"]
\n\nOutput: [1,1,1]
\n\nExplanation:
\n\nLet's look at each wordsQuery[i] separately:
wordsQuery[0] = "cd", strings from wordsContainer that share the longest common suffix "cd" are at indices 0, 1, and 2. Among these, the answer is the string at index 1 because it has the shortest length of 3.wordsQuery[1] = "bcd", strings from wordsContainer that share the longest common suffix "bcd" are at indices 0, 1, and 2. Among these, the answer is the string at index 1 because it has the shortest length of 3.wordsQuery[2] = "xyz", there is no string from wordsContainer that shares a common suffix. Hence the longest common suffix is "", that is shared with strings at index 0, 1, and 2. Among these, the answer is the string at index 1 because it has the shortest length of 3.Example 2:
\n\nInput: wordsContainer = ["abcdefgh","poiuygh","ghghgh"], wordsQuery = ["gh","acbfgh","acbfegh"]
\n\nOutput: [2,0,2]
\n\nExplanation:
\n\nLet's look at each wordsQuery[i] separately:
wordsQuery[0] = "gh", strings from wordsContainer that share the longest common suffix "gh" are at indices 0, 1, and 2. Among these, the answer is the string at index 2 because it has the shortest length of 6.wordsQuery[1] = "acbfgh", only the string at index 0 shares the longest common suffix "fgh". Hence it is the answer, even though the string at index 2 is shorter.wordsQuery[2] = "acbfegh", strings from wordsContainer that share the longest common suffix "gh" are at indices 0, 1, and 2. Among these, the answer is the string at index 2 because it has the shortest length of 6.\n
Constraints:
\n\n1 <= wordsContainer.length, wordsQuery.length <= 1041 <= wordsContainer[i].length <= 5 * 1031 <= wordsQuery[i].length <= 5 * 103wordsContainer[i] consists only of lowercase English letters.wordsQuery[i] consists only of lowercase English letters.wordsContainer[i].length is at most 5 * 105.wordsQuery[i].length is at most 5 * 105.给你两个字符串数组 wordsContainer 和 wordsQuery 。
对于每个 wordsQuery[i] ，你需要从 wordsContainer 中找到一个与 wordsQuery[i] 有 最长公共后缀 的字符串。如果 wordsContainer 中有两个或者更多字符串有最长公共后缀，那么答案为长度 最短 的。如果有超过两个字符串有 相同 最短长度，那么答案为它们在 wordsContainer 中出现 更早 的一个。
请你返回一个整数数组 ans ，其中 ans[i]是 wordsContainer中与 wordsQuery[i] 有 最长公共后缀 字符串的下标。
\n\n
示例 1：
\n\n输入：wordsContainer = [\"abcd\",\"bcd\",\"xbcd\"], wordsQuery = [\"cd\",\"bcd\",\"xyz\"]
\n\n输出：[1,1,1]
\n\n解释：
\n\n我们分别来看每一个 wordsQuery[i] ：
wordsQuery[0] = \"cd\" ，wordsContainer 中有最长公共后缀 \"cd\" 的字符串下标分别为 0 ，1 和 2 。这些字符串中，答案是下标为 1 的字符串，因为它的长度为 3 ，是最短的字符串。wordsQuery[1] = \"bcd\" ，wordsContainer 中有最长公共后缀 \"bcd\" 的字符串下标分别为 0 ，1 和 2 。这些字符串中，答案是下标为 1 的字符串，因为它的长度为 3 ，是最短的字符串。wordsQuery[2] = \"xyz\" ，wordsContainer 中没有字符串跟它有公共后缀，所以最长公共后缀为 \"\" ，下标为 0 ，1 和 2 的字符串都得到这一公共后缀。这些字符串中， 答案是下标为 1 的字符串，因为它的长度为 3 ，是最短的字符串。示例 2：
\n\n输入：wordsContainer = [\"abcdefgh\",\"poiuygh\",\"ghghgh\"], wordsQuery = [\"gh\",\"acbfgh\",\"acbfegh\"]
\n\n输出：[2,0,2]
\n\n解释：
\n\n我们分别来看每一个 wordsQuery[i] ：
wordsQuery[0] = \"gh\" ，wordsContainer 中有最长公共后缀 \"gh\" 的字符串下标分别为 0 ，1 和 2 。这些字符串中，答案是下标为 2 的字符串，因为它的长度为 6 ，是最短的字符串。wordsQuery[1] = \"acbfgh\" ，只有下标为 0 的字符串有最长公共后缀 \"fgh\" 。所以尽管下标为 2 的字符串是最短的字符串，但答案是 0 。wordsQuery[2] = \"acbfegh\" ，wordsContainer 中有最长公共后缀 \"gh\" 的字符串下标分别为 0 ，1 和 2 。这些字符串中，答案是下标为 2 的字符串，因为它的长度为 6 ，是最短的字符串。\n\n
提示：
\n\n1 <= wordsContainer.length, wordsQuery.length <= 1041 <= wordsContainer[i].length <= 5 * 1031 <= wordsQuery[i].length <= 5 * 103wordsContainer[i] 只包含小写英文字母。wordsQuery[i] 只包含小写英文字母。wordsContainer[i].length 的和至多为 5 * 105 。wordsQuery[i].length 的和至多为 5 * 105 。\\u7248\\u672c\\uff1a \\u7f16\\u8bd1\\u65f6\\uff0c\\u5c06\\u4f1a\\u91c7\\u7528 \\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\"],\"java\":[\"Java\",\" \\u7248\\u672c\\uff1a \\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u88ab\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u5305\\u542b Pair \\u7c7b: https:\\/\\/docs.oracle.com\\/javase\\/8\\/javafx\\/api\\/javafx\\/util\\/Pair.html <\\/p>\"],\"python\":[\"Python\",\" \\u7248\\u672c\\uff1a 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