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leetcode-problemset/leetcode-cn/originData/sum-of-digits-of-string-after-convert.json
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"question": {
"questionId": "2076",
"questionFrontendId": "1945",
"categoryTitle": "Algorithms",
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"title": "Sum of Digits of String After Convert",
"titleSlug": "sum-of-digits-of-string-after-convert",
"content": "<p>You are given a string <code>s</code> consisting of lowercase English letters, and an integer <code>k</code>.</p>\n\n<p>First, <strong>convert</strong> <code>s</code> into an integer by replacing each letter with its position in the alphabet (i.e., replace <code>&#39;a&#39;</code> with <code>1</code>, <code>&#39;b&#39;</code> with <code>2</code>, ..., <code>&#39;z&#39;</code> with <code>26</code>). Then, <strong>transform</strong> the integer by replacing it with the <strong>sum of its digits</strong>. Repeat the <strong>transform</strong> operation <code>k</code><strong> times</strong> in total.</p>\n\n<p>For example, if <code>s = &quot;zbax&quot;</code> and <code>k = 2</code>, then the resulting integer would be <code>8</code> by the following operations:</p>\n\n<ul>\n\t<li><strong>Convert</strong>: <code>&quot;zbax&quot; ➝ &quot;(26)(2)(1)(24)&quot; ➝ &quot;262124&quot; ➝ 262124</code></li>\n\t<li><strong>Transform #1</strong>: <code>262124 ➝ 2 + 6 + 2 + 1 + 2 + 4&nbsp;➝ 17</code></li>\n\t<li><strong>Transform #2</strong>: <code>17 ➝ 1 + 7 ➝ 8</code></li>\n</ul>\n\n<p>Return <em>the resulting integer after performing the operations described above</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;iiii&quot;, k = 1\n<strong>Output:</strong> 36\n<strong>Explanation:</strong> The operations are as follows:\n- Convert: &quot;iiii&quot; ➝ &quot;(9)(9)(9)(9)&quot; ➝ &quot;9999&quot; ➝ 9999\n- Transform #1: 9999 ➝ 9 + 9 + 9 + 9 ➝ 36\nThus the resulting integer is 36.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;leetcode&quot;, k = 2\n<strong>Output:</strong> 6\n<strong>Explanation:</strong> The operations are as follows:\n- Convert: &quot;leetcode&quot; ➝ &quot;(12)(5)(5)(20)(3)(15)(4)(5)&quot; ➝ &quot;12552031545&quot; ➝ 12552031545\n- Transform #1: 12552031545 ➝ 1 + 2 + 5 + 5 + 2 + 0 + 3 + 1 + 5 + 4 + 5 ➝ 33\n- Transform #2: 33 ➝ 3 + 3 ➝ 6\nThus the resulting integer is 6.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;zbax&quot;, k = 2\n<strong>Output:</strong> 8\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 100</code></li>\n\t<li><code>1 &lt;= k &lt;= 10</code></li>\n\t<li><code>s</code> consists of lowercase English letters.</li>\n</ul>\n",
"translatedTitle": "字符串转化后的各位数字之和",
"translatedContent": "<p>给你一个由小写字母组成的字符串 <code>s</code> ,以及一个整数 <code>k</code> 。</p>\n\n<p>首先,用字母在字母表中的位置替换该字母,将 <code>s</code> <strong>转化</strong> 为一个整数(也就是,<code>'a'</code> 用 <code>1</code> 替换,<code>'b'</code> 用 <code>2</code> 替换,... <code>'z'</code> 用 <code>26</code> 替换)。接着,将整数 <strong>转换</strong> 为其 <strong>各位数字之和</strong> 。共重复 <strong>转换</strong> 操作 <strong><code>k</code> 次</strong> 。</p>\n\n<p>例如,如果 <code>s = \"zbax\"</code> 且 <code>k = 2</code> ,那么执行下述步骤后得到的结果是整数 <code>8</code> </p>\n\n<ul>\n\t<li><strong>转化:</strong><code>\"zbax\" ➝ \"(26)(2)(1)(24)\" ➝ \"262124\" ➝ 262124</code></li>\n\t<li><strong>转换 #1</strong><code>262124&nbsp;➝ 2 + 6 + 2 + 1 + 2 + 4&nbsp;➝ 17</code></li>\n\t<li><strong>转换 #2</strong><code>17 ➝ 1 + 7 ➝ 8</code></li>\n</ul>\n\n<p>返回执行上述操作后得到的结果整数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>s = \"iiii\", k = 1\n<strong>输出:</strong>36\n<strong>解释:</strong>操作如下:\n- 转化:\"iiii\" ➝ \"(9)(9)(9)(9)\" ➝ \"9999\" ➝ 9999\n- 转换 #19999 ➝ 9 + 9 + 9 + 9 ➝ 36\n因此结果整数为 36 。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>s = \"leetcode\", k = 2\n<strong>输出:</strong>6\n<strong>解释:</strong>操作如下:\n- 转化:\"leetcode\" ➝ \"(12)(5)(5)(20)(3)(15)(4)(5)\" ➝ \"12552031545\" ➝ 12552031545\n- 转换 #112552031545 ➝ 1 + 2 + 5 + 5 + 2 + 0 + 3 + 1 + 5 + 4 + 5 ➝ 33\n- 转换 #233 ➝ 3 + 3 ➝ 6\n因此结果整数为 6 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 100</code></li>\n\t<li><code>1 &lt;= k &lt;= 10</code></li>\n\t<li><code>s</code> 由小写英文字母组成</li>\n</ul>\n",
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"First, let's note that after the first transform the value will be at most 100 * 9 which is not much",
"After The first transform, we can just do the rest of the transforms by brute force"
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