{ "data": { "question": { "questionId": "2076", "questionFrontendId": "1945", "categoryTitle": "Algorithms", "boundTopicId": 888024, "title": "Sum of Digits of String After Convert", "titleSlug": "sum-of-digits-of-string-after-convert", "content": "
You are given a string s
consisting of lowercase English letters, and an integer k
.
First, convert s
into an integer by replacing each letter with its position in the alphabet (i.e., replace 'a'
with 1
, 'b'
with 2
, ..., 'z'
with 26
). Then, transform the integer by replacing it with the sum of its digits. Repeat the transform operation k
times in total.
For example, if s = "zbax"
and k = 2
, then the resulting integer would be 8
by the following operations:
"zbax" ➝ "(26)(2)(1)(24)" ➝ "262124" ➝ 262124
262124 ➝ 2 + 6 + 2 + 1 + 2 + 4 ➝ 17
17 ➝ 1 + 7 ➝ 8
Return the resulting integer after performing the operations described above.
\n\n\n
Example 1:
\n\n\nInput: s = "iiii", k = 1\nOutput: 36\nExplanation: The operations are as follows:\n- Convert: "iiii" ➝ "(9)(9)(9)(9)" ➝ "9999" ➝ 9999\n- Transform #1: 9999 ➝ 9 + 9 + 9 + 9 ➝ 36\nThus the resulting integer is 36.\n\n\n
Example 2:
\n\n\nInput: s = "leetcode", k = 2\nOutput: 6\nExplanation: The operations are as follows:\n- Convert: "leetcode" ➝ "(12)(5)(5)(20)(3)(15)(4)(5)" ➝ "12552031545" ➝ 12552031545\n- Transform #1: 12552031545 ➝ 1 + 2 + 5 + 5 + 2 + 0 + 3 + 1 + 5 + 4 + 5 ➝ 33\n- Transform #2: 33 ➝ 3 + 3 ➝ 6\nThus the resulting integer is 6.\n\n\n
Example 3:
\n\n\nInput: s = "zbax", k = 2\nOutput: 8\n\n\n
\n
Constraints:
\n\n1 <= s.length <= 100
1 <= k <= 10
s
consists of lowercase English letters.给你一个由小写字母组成的字符串 s
,以及一个整数 k
。
首先,用字母在字母表中的位置替换该字母,将 s
转化 为一个整数(也就是,'a'
用 1
替换,'b'
用 2
替换,... 'z'
用 26
替换)。接着,将整数 转换 为其 各位数字之和 。共重复 转换 操作 k
次 。
例如,如果 s = \"zbax\"
且 k = 2
,那么执行下述步骤后得到的结果是整数 8
:
\"zbax\" ➝ \"(26)(2)(1)(24)\" ➝ \"262124\" ➝ 262124
262124 ➝ 2 + 6 + 2 + 1 + 2 + 4 ➝ 17
17 ➝ 1 + 7 ➝ 8
返回执行上述操作后得到的结果整数。
\n\n\n\n
示例 1:
\n\n\n输入:s = \"iiii\", k = 1\n输出:36\n解释:操作如下:\n- 转化:\"iiii\" ➝ \"(9)(9)(9)(9)\" ➝ \"9999\" ➝ 9999\n- 转换 #1:9999 ➝ 9 + 9 + 9 + 9 ➝ 36\n因此,结果整数为 36 。\n\n\n
示例 2:
\n\n\n输入:s = \"leetcode\", k = 2\n输出:6\n解释:操作如下:\n- 转化:\"leetcode\" ➝ \"(12)(5)(5)(20)(3)(15)(4)(5)\" ➝ \"12552031545\" ➝ 12552031545\n- 转换 #1:12552031545 ➝ 1 + 2 + 5 + 5 + 2 + 0 + 3 + 1 + 5 + 4 + 5 ➝ 33\n- 转换 #2:33 ➝ 3 + 3 ➝ 6\n因此,结果整数为 6 。\n\n\n
\n\n
提示:
\n\n1 <= s.length <= 100
1 <= k <= 10
s
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out-of-bounds<\\/code>\\u548c
use-after-free<\\/code>\\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n
OpenJDK 17<\\/code>\\u3002\\u53ef\\u4ee5\\u4f7f\\u7528Java 8\\u7684\\u7279\\u6027\\u4f8b\\u5982\\uff0clambda expressions \\u548c stream API\\u3002<\\/p>\\r\\n\\r\\n
Python 2.7.12<\\/code><\\/p>\\r\\n\\r\\n
GCC 8.2<\\/code>\\uff0c\\u91c7\\u7528GNU99\\u6807\\u51c6\\u3002<\\/p>\\r\\n\\r\\n
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out-of-bounds<\\/code>\\u548c
use-after-free<\\/code>\\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n
\\r\\nstruct hash_entry {\\r\\n int id; \\/* we'll use this field as the key *\\/\\r\\n char name[10];\\r\\n UT_hash_handle hh; \\/* makes this structure hashable *\\/\\r\\n};\\r\\n\\r\\nstruct hash_entry *users = NULL;\\r\\n\\r\\nvoid add_user(struct hash_entry *s) {\\r\\n HASH_ADD_INT(users, id, s);\\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\\r\\n\\r\\n
\\r\\nstruct hash_entry *find_user(int user_id) {\\r\\n struct hash_entry *s;\\r\\n HASH_FIND_INT(users, &user_id, s);\\r\\n return s;\\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\\r\\n\\r\\n
\\r\\nvoid delete_user(struct hash_entry *user) {\\r\\n HASH_DEL(users, user); \\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\"],\"csharp\":[\"C#\",\"
\\/debug:pdbonly<\\/code>)\\u3002<\\/p>\"],\"javascript\":[\"JavaScript\",\"
Node.js 16.13.2<\\/code><\\/p>\\r\\n\\r\\n
--harmony<\\/code> \\u6807\\u8bb0\\u6765\\u5f00\\u542f \\u65b0\\u7248ES6\\u7279\\u6027<\\/a>\\u3002<\\/p>\\r\\n\\r\\n
Ruby 3.1<\\/code>\\u6267\\u884c<\\/p>\\r\\n\\r\\n
Swift 5.5.2<\\/code><\\/p>\\r\\n\\r\\n
Go 1.17<\\/code><\\/p>\\r\\n\\r\\n
Python 3.10<\\/code><\\/p>\\r\\n\\r\\n
Scala 2.13<\\/code><\\/p>\"],\"kotlin\":[\"Kotlin\",\"
Kotlin 1.3.10<\\/code><\\/p>\"],\"rust\":[\"Rust\",\"
rust 1.58.1<\\/code><\\/p>\\r\\n\\r\\n
PHP 8.1<\\/code>.<\\/p>\\r\\n\\r\\n