mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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186 lines
23 KiB
JSON
186 lines
23 KiB
JSON
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"title": "Most Stones Removed with Same Row or Column",
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"content": "<p>On a 2D plane, we place <code>n</code> stones at some integer coordinate points. Each coordinate point may have at most one stone.</p>\n\n<p>A stone can be removed if it shares either <strong>the same row or the same column</strong> as another stone that has not been removed.</p>\n\n<p>Given an array <code>stones</code> of length <code>n</code> where <code>stones[i] = [x<sub>i</sub>, y<sub>i</sub>]</code> represents the location of the <code>i<sup>th</sup></code> stone, return <em>the largest possible number of stones that can be removed</em>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> stones = [[0,0],[0,1],[1,0],[1,2],[2,1],[2,2]]\n<strong>Output:</strong> 5\n<strong>Explanation:</strong> One way to remove 5 stones is as follows:\n1. Remove stone [2,2] because it shares the same row as [2,1].\n2. Remove stone [2,1] because it shares the same column as [0,1].\n3. Remove stone [1,2] because it shares the same row as [1,0].\n4. Remove stone [1,0] because it shares the same column as [0,0].\n5. Remove stone [0,1] because it shares the same row as [0,0].\nStone [0,0] cannot be removed since it does not share a row/column with another stone still on the plane.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> stones = [[0,0],[0,2],[1,1],[2,0],[2,2]]\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> One way to make 3 moves is as follows:\n1. Remove stone [2,2] because it shares the same row as [2,0].\n2. Remove stone [2,0] because it shares the same column as [0,0].\n3. Remove stone [0,2] because it shares the same row as [0,0].\nStones [0,0] and [1,1] cannot be removed since they do not share a row/column with another stone still on the plane.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> stones = [[0,0]]\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> [0,0] is the only stone on the plane, so you cannot remove it.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= stones.length <= 1000</code></li>\n\t<li><code>0 <= x<sub>i</sub>, y<sub>i</sub> <= 10<sup>4</sup></code></li>\n\t<li>No two stones are at the same coordinate point.</li>\n</ul>\n",
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"translatedTitle": "移除最多的同行或同列石头",
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"translatedContent": "<p><code>n</code> 块石头放置在二维平面中的一些整数坐标点上。每个坐标点上最多只能有一块石头。</p>\n\n<p>如果一块石头的 <strong>同行或者同列</strong> 上有其他石头存在，那么就可以移除这块石头。</p>\n\n<p>给你一个长度为 <code>n</code> 的数组 <code>stones</code> ，其中 <code>stones[i] = [x<sub>i</sub>, y<sub>i</sub>]</code> 表示第 <code>i</code> 块石头的位置，返回 <strong>可以移除的石子</strong> 的最大数量。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>stones = [[0,0],[0,1],[1,0],[1,2],[2,1],[2,2]]\n<strong>输出：</strong>5\n<strong>解释：</strong>一种移除 5 块石头的方法如下所示：\n1. 移除石头 [2,2] ，因为它和 [2,1] 同行。\n2. 移除石头 [2,1] ，因为它和 [0,1] 同列。\n3. 移除石头 [1,2] ，因为它和 [1,0] 同行。\n4. 移除石头 [1,0] ，因为它和 [0,0] 同列。\n5. 移除石头 [0,1] ，因为它和 [0,0] 同行。\n石头 [0,0] 不能移除，因为它没有与另一块石头同行/列。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>stones = [[0,0],[0,2],[1,1],[2,0],[2,2]]\n<strong>输出：</strong>3\n<strong>解释：</strong>一种移除 3 块石头的方法如下所示：\n1. 移除石头 [2,2] ，因为它和 [2,0] 同行。\n2. 移除石头 [2,0] ，因为它和 [0,0] 同列。\n3. 移除石头 [0,2] ，因为它和 [0,0] 同行。\n石头 [0,0] 和 [1,1] 不能移除，因为它们没有与另一块石头同行/列。</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>stones = [[0,0]]\n<strong>输出：</strong>0\n<strong>解释：</strong>[0,0] 是平面上唯一一块石头，所以不可以移除它。</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= stones.length <= 1000</code></li>\n\t<li><code>0 <= x<sub>i</sub>, y<sub>i</sub> <= 10<sup>4</sup></code></li>\n\t<li>不会有两块石头放在同一个坐标点上</li>\n</ul>\n",
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