{ "data": { "question": { "questionId": "984", "questionFrontendId": "947", "categoryTitle": "Algorithms", "boundTopicId": 2422, "title": "Most Stones Removed with Same Row or Column", "titleSlug": "most-stones-removed-with-same-row-or-column", "content": "

On a 2D plane, we place n stones at some integer coordinate points. Each coordinate point may have at most one stone.

\n\n

A stone can be removed if it shares either the same row or the same column as another stone that has not been removed.

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Given an array stones of length n where stones[i] = [xi, yi] represents the location of the ith stone, return the largest possible number of stones that can be removed.

\n\n

 

\n

Example 1:

\n\n
\nInput: stones = [[0,0],[0,1],[1,0],[1,2],[2,1],[2,2]]\nOutput: 5\nExplanation: One way to remove 5 stones is as follows:\n1. Remove stone [2,2] because it shares the same row as [2,1].\n2. Remove stone [2,1] because it shares the same column as [0,1].\n3. Remove stone [1,2] because it shares the same row as [1,0].\n4. Remove stone [1,0] because it shares the same column as [0,0].\n5. Remove stone [0,1] because it shares the same row as [0,0].\nStone [0,0] cannot be removed since it does not share a row/column with another stone still on the plane.\n
\n\n

Example 2:

\n\n
\nInput: stones = [[0,0],[0,2],[1,1],[2,0],[2,2]]\nOutput: 3\nExplanation: One way to make 3 moves is as follows:\n1. Remove stone [2,2] because it shares the same row as [2,0].\n2. Remove stone [2,0] because it shares the same column as [0,0].\n3. Remove stone [0,2] because it shares the same row as [0,0].\nStones [0,0] and [1,1] cannot be removed since they do not share a row/column with another stone still on the plane.\n
\n\n

Example 3:

\n\n
\nInput: stones = [[0,0]]\nOutput: 0\nExplanation: [0,0] is the only stone on the plane, so you cannot remove it.\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "移除最多的同行或同列石头", "translatedContent": "

n 块石头放置在二维平面中的一些整数坐标点上。每个坐标点上最多只能有一块石头。

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如果一块石头的 同行或者同列 上有其他石头存在,那么就可以移除这块石头。

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给你一个长度为 n 的数组 stones ,其中 stones[i] = [xi, yi] 表示第 i 块石头的位置,返回 可以移除的石子 的最大数量。

\n\n

 

\n\n

示例 1:

\n\n
\n输入:stones = [[0,0],[0,1],[1,0],[1,2],[2,1],[2,2]]\n输出:5\n解释:一种移除 5 块石头的方法如下所示:\n1. 移除石头 [2,2] ,因为它和 [2,1] 同行。\n2. 移除石头 [2,1] ,因为它和 [0,1] 同列。\n3. 移除石头 [1,2] ,因为它和 [1,0] 同行。\n4. 移除石头 [1,0] ,因为它和 [0,0] 同列。\n5. 移除石头 [0,1] ,因为它和 [0,0] 同行。\n石头 [0,0] 不能移除,因为它没有与另一块石头同行/列。
\n\n

示例 2:

\n\n
\n输入:stones = [[0,0],[0,2],[1,1],[2,0],[2,2]]\n输出:3\n解释:一种移除 3 块石头的方法如下所示:\n1. 移除石头 [2,2] ,因为它和 [2,0] 同行。\n2. 移除石头 [2,0] ,因为它和 [0,0] 同列。\n3. 移除石头 [0,2] ,因为它和 [0,0] 同行。\n石头 [0,0] 和 [1,1] 不能移除,因为它们没有与另一块石头同行/列。
\n\n

示例 3:

\n\n
\n输入:stones = [[0,0]]\n输出:0\n解释:[0,0] 是平面上唯一一块石头,所以不可以移除它。
\n\n

 

\n\n

提示:

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