mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-11 02:58:13 +08:00
180 lines
29 KiB
JSON
180 lines
29 KiB
JSON
{
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"data": {
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"question": {
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"questionId": "382",
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"questionFrontendId": "382",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1161,
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"title": "Linked List Random Node",
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"titleSlug": "linked-list-random-node",
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"content": "<p>Given a singly linked list, return a random node's value from the linked list. Each node must have the <strong>same probability</strong> of being chosen.</p>\n\n<p>Implement the <code>Solution</code> class:</p>\n\n<ul>\n\t<li><code>Solution(ListNode head)</code> Initializes the object with the head of the singly-linked list <code>head</code>.</li>\n\t<li><code>int getRandom()</code> Chooses a node randomly from the list and returns its value. All the nodes of the list should be equally likely to be chosen.</li>\n</ul>\n\n<p> </p>\n<p><strong>Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/03/16/getrand-linked-list.jpg\" style=\"width: 302px; height: 62px;\" />\n<pre>\n<strong>Input</strong>\n["Solution", "getRandom", "getRandom", "getRandom", "getRandom", "getRandom"]\n[[[1, 2, 3]], [], [], [], [], []]\n<strong>Output</strong>\n[null, 1, 3, 2, 2, 3]\n\n<strong>Explanation</strong>\nSolution solution = new Solution([1, 2, 3]);\nsolution.getRandom(); // return 1\nsolution.getRandom(); // return 3\nsolution.getRandom(); // return 2\nsolution.getRandom(); // return 2\nsolution.getRandom(); // return 3\n// getRandom() should return either 1, 2, or 3 randomly. Each element should have equal probability of returning.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the linked list will be in the range <code>[1, 10<sup>4</sup>]</code>.</li>\n\t<li><code>-10<sup>4</sup> <= Node.val <= 10<sup>4</sup></code></li>\n\t<li>At most <code>10<sup>4</sup></code> calls will be made to <code>getRandom</code>.</li>\n</ul>\n\n<p> </p>\n<p><strong>Follow up:</strong></p>\n\n<ul>\n\t<li>What if the linked list is extremely large and its length is unknown to you?</li>\n\t<li>Could you solve this efficiently without using extra space?</li>\n</ul>\n",
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"translatedTitle": "链表随机节点",
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"translatedContent": "<p>给你一个单链表，随机选择链表的一个节点，并返回相应的节点值。每个节点<strong> 被选中的概率一样</strong> 。</p>\n\n<p>实现 <code>Solution</code> 类：</p>\n\n<ul>\n\t<li><code>Solution(ListNode head)</code> 使用整数数组初始化对象。</li>\n\t<li><code>int getRandom()</code> 从链表中随机选择一个节点并返回该节点的值。链表中所有节点被选中的概率相等。</li>\n</ul>\n\n<p> </p>\n\n<p><strong>示例：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/03/16/getrand-linked-list.jpg\" style=\"width: 302px; height: 62px;\" />\n<pre>\n<strong>输入</strong>\n[\"Solution\", \"getRandom\", \"getRandom\", \"getRandom\", \"getRandom\", \"getRandom\"]\n[[[1, 2, 3]], [], [], [], [], []]\n<strong>输出</strong>\n[null, 1, 3, 2, 2, 3]\n\n<strong>解释</strong>\nSolution solution = new Solution([1, 2, 3]);\nsolution.getRandom(); // 返回 1\nsolution.getRandom(); // 返回 3\nsolution.getRandom(); // 返回 2\nsolution.getRandom(); // 返回 2\nsolution.getRandom(); // 返回 3\n// getRandom() 方法应随机返回 1、2、3中的一个，每个元素被返回的概率相等。</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>链表中的节点数在范围 <code>[1, 10<sup>4</sup>]</code> 内</li>\n\t<li><code>-10<sup>4</sup> <= Node.val <= 10<sup>4</sup></code></li>\n\t<li>至多调用 <code>getRandom</code> 方法 <code>10<sup>4</sup></code> 次</li>\n</ul>\n\n<p> </p>\n\n<p><strong>进阶：</strong></p>\n\n<ul>\n\t<li>如果链表非常大且长度未知，该怎么处理？</li>\n\t<li>你能否在不使用额外空间的情况下解决此问题？</li>\n</ul>\n",
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"code": "# Definition for singly-linked list.\n# class ListNode:\n# def __init__(self, val=0, next=None):\n# self.val = val\n# self.next = next\nclass Solution:\n\n def __init__(self, head: Optional[ListNode]):\n\n\n def getRandom(self) -> int:\n\n\n\n# Your Solution object will be instantiated and called as such:\n# obj = Solution(head)\n# param_1 = obj.getRandom()",
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"code": "// Definition for singly-linked list.\n// #[derive(PartialEq, Eq, Clone, Debug)]\n// pub struct ListNode {\n// pub val: i32,\n// pub next: Option<Box<ListNode>>\n// }\n//\n// impl ListNode {\n// #[inline]\n// fn new(val: i32) -> Self {\n// ListNode {\n// next: None,\n// val\n// }\n// }\n// }\nstruct Solution {\n\n}\n\n\n/**\n * `&self` means the method takes an immutable reference.\n * If you need a mutable reference, change it to `&mut self` instead.\n */\nimpl Solution {\n\n fn new(head: Option<Box<ListNode>>) -> Self {\n\n }\n \n fn get_random(&self) -> i32 {\n\n }\n}\n\n/**\n * Your Solution object will be instantiated and called as such:\n * let obj = Solution::new(head);\n * let ret_1: i32 = obj.get_random();\n */",
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"code": "/**\n * Definition for a singly-linked list.\n * class ListNode {\n * public $val = 0;\n * public $next = null;\n * function __construct($val = 0, $next = null) {\n * $this->val = $val;\n * $this->next = $next;\n * }\n * }\n */\nclass Solution {\n /**\n * @param ListNode $head\n */\n function __construct($head) {\n\n }\n\n /**\n * @return Integer\n */\n function getRandom() {\n\n }\n}\n\n/**\n * Your Solution object will be instantiated and called as such:\n * $obj = Solution($head);\n * $ret_1 = $obj->getRandom();\n */",
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