leetcode-problemset/leetcode-cn/originData/defuse-the-bomb.json

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        "question": {
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            "title": "Defuse the Bomb",
            "titleSlug": "defuse-the-bomb",
            "content": "<p>You have a bomb to defuse, and your time is running out! Your informer will provide you with a <strong>circular</strong> array <code>code</code>&nbsp;of length of <code>n</code>&nbsp;and a key <code>k</code>.</p>\n\n<p>To decrypt the code, you must replace every number. All the numbers are replaced <strong>simultaneously</strong>.</p>\n\n<ul>\n\t<li>If <code>k &gt; 0</code>, replace the <code>i<sup>th</sup></code> number with the sum of the <strong>next</strong> <code>k</code> numbers.</li>\n\t<li>If <code>k &lt; 0</code>, replace the <code>i<sup>th</sup></code> number with the sum of the <strong>previous</strong> <code>k</code> numbers.</li>\n\t<li>If <code>k == 0</code>, replace the <code>i<sup>th</sup></code> number with <code>0</code>.</li>\n</ul>\n\n<p>As <code>code</code> is circular, the next element of <code>code[n-1]</code> is <code>code[0]</code>, and the previous element of <code>code[0]</code> is <code>code[n-1]</code>.</p>\n\n<p>Given the <strong>circular</strong> array <code>code</code> and an integer key <code>k</code>, return <em>the decrypted code to defuse the bomb</em>!</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> code = [5,7,1,4], k = 3\n<strong>Output:</strong> [12,10,16,13]\n<strong>Explanation:</strong> Each number is replaced by the sum of the next 3 numbers. The decrypted code is [7+1+4, 1+4+5, 4+5+7, 5+7+1]. Notice that the numbers wrap around.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> code = [1,2,3,4], k = 0\n<strong>Output:</strong> [0,0,0,0]\n<strong>Explanation:</strong> When k is zero, the numbers are replaced by 0. \n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> code = [2,4,9,3], k = -2\n<strong>Output:</strong> [12,5,6,13]\n<strong>Explanation:</strong> The decrypted code is [3+9, 2+3, 4+2, 9+4]. Notice that the numbers wrap around again. If k is negative, the sum is of the <strong>previous</strong> numbers.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == code.length</code></li>\n\t<li><code>1 &lt;= n&nbsp;&lt;= 100</code></li>\n\t<li><code>1 &lt;= code[i] &lt;= 100</code></li>\n\t<li><code>-(n - 1) &lt;= k &lt;= n - 1</code></li>\n</ul>\n",
            "translatedTitle": "拆炸弹",
            "translatedContent": "<p>你有一个炸弹需要拆除，时间紧迫！你的情报员会给你一个长度为 <code>n</code> 的 <strong>循环</strong> 数组 <code>code</code> 以及一个密钥 <code>k</code> 。</p>\n\n<p>为了获得正确的密码，你需要替换掉每一个数字。所有数字会 <strong>同时</strong> 被替换。</p>\n\n<ul>\n\t<li>如果 <code>k > 0</code> ，将第 <code>i</code> 个数字用 <strong>接下来</strong> <code>k</code> 个数字之和替换。</li>\n\t<li>如果 <code>k < 0</code> ，将第 <code>i</code> 个数字用 <strong>之前</strong> <code>k</code> 个数字之和替换。</li>\n\t<li>如果 <code>k == 0</code> ，将第 <code>i</code> 个数字用 <code>0</code> 替换。</li>\n</ul>\n\n<p>由于 <code>code</code> 是循环的， <code>code[n-1]</code> 下一个元素是 <code>code[0]</code> ，且 <code>code[0]</code> 前一个元素是 <code>code[n-1]</code> 。</p>\n\n<p>给你 <strong>循环</strong> 数组 <code>code</code> 和整数密钥 <code>k</code> ，请你返回解密后的结果来拆除炸弹！</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>code = [5,7,1,4], k = 3\n<b>输出：</b>[12,10,16,13]\n<b>解释：</b>每个数字都被接下来 3 个数字之和替换。解密后的密码为 [7+1+4, 1+4+5, 4+5+7, 5+7+1]。注意到数组是循环连接的。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>code = [1,2,3,4], k = 0\n<b>输出：</b>[0,0,0,0]\n<b>解释：</b>当 k 为 0 时，所有数字都被 0 替换。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<b>输入：</b>code = [2,4,9,3], k = -2\n<b>输出：</b>[12,5,6,13]\n<b>解释：</b>解密后的密码为 [3+9, 2+3, 4+2, 9+4] 。注意到数组是循环连接的。如果 k 是负数，那么和为 <strong>之前</strong> 的数字。\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == code.length</code></li>\n\t<li><code>1 <= n <= 100</code></li>\n\t<li><code>1 <= code[i] <= 100</code></li>\n\t<li><code>-(n - 1) <= k <= n - 1</code></li>\n</ul>\n",
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