{ "data": { "question": { "questionId": "1755", "questionFrontendId": "1652", "categoryTitle": "Algorithms", "boundTopicId": 480838, "title": "Defuse the Bomb", "titleSlug": "defuse-the-bomb", "content": "

You have a bomb to defuse, and your time is running out! Your informer will provide you with a circular array code of length of n and a key k.

\n\n

To decrypt the code, you must replace every number. All the numbers are replaced simultaneously.

\n\n\n\n

As code is circular, the next element of code[n-1] is code[0], and the previous element of code[0] is code[n-1].

\n\n

Given the circular array code and an integer key k, return the decrypted code to defuse the bomb!

\n\n

 

\n

Example 1:

\n\n
\nInput: code = [5,7,1,4], k = 3\nOutput: [12,10,16,13]\nExplanation: Each number is replaced by the sum of the next 3 numbers. The decrypted code is [7+1+4, 1+4+5, 4+5+7, 5+7+1]. Notice that the numbers wrap around.\n
\n\n

Example 2:

\n\n
\nInput: code = [1,2,3,4], k = 0\nOutput: [0,0,0,0]\nExplanation: When k is zero, the numbers are replaced by 0. \n
\n\n

Example 3:

\n\n
\nInput: code = [2,4,9,3], k = -2\nOutput: [12,5,6,13]\nExplanation: The decrypted code is [3+9, 2+3, 4+2, 9+4]. Notice that the numbers wrap around again. If k is negative, the sum is of the previous numbers.\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "拆炸弹", "translatedContent": "

你有一个炸弹需要拆除，时间紧迫！你的情报员会给你一个长度为 n 的 循环 数组 code 以及一个密钥 k 。

\n\n

为了获得正确的密码，你需要替换掉每一个数字。所有数字会 同时 被替换。

\n\n\n\n

由于 code 是循环的， code[n-1] 下一个元素是 code[0] ，且 code[0] 前一个元素是 code[n-1] 。

\n\n

给你 循环 数组 code 和整数密钥 k ，请你返回解密后的结果来拆除炸弹！

\n\n

 

\n\n

示例 1：

\n\n
\n输入：code = [5,7,1,4], k = 3\n输出：[12,10,16,13]\n解释：每个数字都被接下来 3 个数字之和替换。解密后的密码为 [7+1+4, 1+4+5, 4+5+7, 5+7+1]。注意到数组是循环连接的。\n
\n\n

示例 2：

\n\n
\n输入：code = [1,2,3,4], k = 0\n输出：[0,0,0,0]\n解释：当 k 为 0 时，所有数字都被 0 替换。\n
\n\n

示例 3：

\n\n
\n输入：code = [2,4,9,3], k = -2\n输出：[12,5,6,13]\n解释：解密后的密码为 [3+9, 2+3, 4+2, 9+4] 。注意到数组是循环连接的。如果 k 是负数，那么和为 之前 的数字。\n
\n\n

 

\n\n

提示：

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