leetcode-problemset/leetcode-cn/originData/the-latest-time-to-catch-a-bus.json

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        "question": {
            "questionId": "2417",
            "questionFrontendId": "2332",
            "categoryTitle": "Algorithms",
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            "title": "The Latest Time to Catch a Bus",
            "titleSlug": "the-latest-time-to-catch-a-bus",
            "content": "<p>You are given a <strong>0-indexed</strong> integer array <code>buses</code> of length <code>n</code>, where <code>buses[i]</code> represents the departure time of the <code>i<sup>th</sup></code> bus. You are also given a <strong>0-indexed</strong> integer array <code>passengers</code> of length <code>m</code>, where <code>passengers[j]</code> represents the arrival time of the <code>j<sup>th</sup></code> passenger. All bus departure times are unique. All passenger arrival times are unique.</p>\n\n<p>You are given an integer <code>capacity</code>, which represents the <strong>maximum</strong> number of passengers that can get on each bus.</p>\n\n<p>When a passenger arrives, they will wait in line for the next available bus. You can get on a bus that departs at <code>x</code> minutes if you arrive at <code>y</code> minutes where <code>y &lt;= x</code>, and the bus is not full. Passengers with the <strong>earliest</strong> arrival times get on the bus first.</p>\n\n<p>More formally when a bus arrives, either:</p>\n\n<ul>\n\t<li>If <code>capacity</code> or fewer passengers are waiting for a bus, they will <strong>all</strong> get on the bus, or</li>\n\t<li>The <code>capacity</code> passengers with the <strong>earliest</strong> arrival times will get on the bus.</li>\n</ul>\n\n<p>Return <em>the latest time you may arrive at the bus station to catch a bus</em>. You <strong>cannot</strong> arrive at the same time as another passenger.</p>\n\n<p><strong>Note: </strong>The arrays <code>buses</code> and <code>passengers</code> are not necessarily sorted.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> buses = [10,20], passengers = [2,17,18,19], capacity = 2\n<strong>Output:</strong> 16\n<strong>Explanation:</strong> Suppose you arrive at time 16.\nAt time 10, the first bus departs with the 0<sup>th</sup> passenger. \nAt time 20, the second bus departs with you and the 1<sup>st</sup> passenger.\nNote that you may not arrive at the same time as another passenger, which is why you must arrive before the 1<sup>st</sup> passenger to catch the bus.</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> buses = [20,30,10], passengers = [19,13,26,4,25,11,21], capacity = 2\n<strong>Output:</strong> 20\n<strong>Explanation:</strong> Suppose you arrive at time 20.\nAt time 10, the first bus departs with the 3<sup>rd</sup> passenger. \nAt time 20, the second bus departs with the 5<sup>th</sup> and 1<sup>st</sup> passengers.\nAt time 30, the third bus departs with the 0<sup>th</sup> passenger and you.\nNotice if you had arrived any later, then the 6<sup>th</sup> passenger would have taken your seat on the third bus.</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == buses.length</code></li>\n\t<li><code>m == passengers.length</code></li>\n\t<li><code>1 &lt;= n, m, capacity &lt;= 10<sup>5</sup></code></li>\n\t<li><code>2 &lt;= buses[i], passengers[i] &lt;= 10<sup>9</sup></code></li>\n\t<li>Each element in <code>buses</code> is <strong>unique</strong>.</li>\n\t<li>Each element in <code>passengers</code> is <strong>unique</strong>.</li>\n</ul>\n",
            "translatedTitle": "坐上公交的最晚时间",
            "translatedContent": "<p>给你一个下标从 <strong>0</strong>&nbsp;开始长度为 <code>n</code>&nbsp;的整数数组&nbsp;<code>buses</code>&nbsp;，其中&nbsp;<code>buses[i]</code>&nbsp;表示第 <code>i</code>&nbsp;辆公交车的出发时间。同时给你一个下标从 <strong>0</strong>&nbsp;开始长度为 <code>m</code>&nbsp;的整数数组&nbsp;<code>passengers</code>&nbsp;，其中&nbsp;<code>passengers[j]</code>&nbsp;表示第&nbsp;<code>j</code>&nbsp;位乘客的到达时间。所有公交车出发的时间互不相同，所有乘客到达的时间也互不相同。</p>\n\n<p>给你一个整数&nbsp;<code>capacity</code>&nbsp;，表示每辆公交车&nbsp;<strong>最多</strong>&nbsp;能容纳的乘客数目。</p>\n\n<p>每位乘客都会搭乘下一辆有座位的公交车。如果你在 <code>y</code>&nbsp;时刻到达，公交在&nbsp;<code>x</code>&nbsp;时刻出发，满足&nbsp;<code>y &lt;= x</code>&nbsp;&nbsp;且公交没有满，那么你可以搭乘这一辆公交。<strong>最早</strong>&nbsp;到达的乘客优先上车。</p>\n\n<p>返回你可以搭乘公交车的最晚到达公交站时间。你 <strong>不能</strong>&nbsp;跟别的乘客同时刻到达。</p>\n\n<p><strong>注意：</strong>数组&nbsp;<code>buses</code> 和&nbsp;<code>passengers</code>&nbsp;不一定是有序的。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre><b>输入：</b>buses = [10,20], passengers = [2,17,18,19], capacity = 2\n<b>输出：</b>16\n<strong>解释：</strong>\n第 1 辆公交车载着第 1 位乘客。\n第 2 辆公交车载着你和第 2 位乘客。\n注意你不能跟其他乘客同一时间到达，所以你必须在第二位乘客之前到达。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre><b>输入：</b>buses = [20,30,10], passengers = [19,13,26,4,25,11,21], capacity = 2\n<b>输出：</b>20\n<b>解释：</b>\n第 1 辆公交车载着第 4 位乘客。\n第 2 辆公交车载着第 6 位和第 2 位乘客。\n第 3 辆公交车载着第 1 位乘客和你。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == buses.length</code></li>\n\t<li><code>m == passengers.length</code></li>\n\t<li><code>1 &lt;= n, m, capacity &lt;= 10<sup>5</sup></code></li>\n\t<li><code>2 &lt;= buses[i], passengers[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>buses</code>&nbsp;中的元素 <strong>互不相同&nbsp;</strong>。</li>\n\t<li><code>passengers</code>&nbsp;中的元素 <strong>互不相同</strong>&nbsp;。</li>\n</ul>\n",
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                    "code": "class Solution {\npublic:\n    int latestTimeCatchTheBus(vector<int>& buses, vector<int>& passengers, int capacity) {\n        \n    }\n};",
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                    "code": "class Solution(object):\n    def latestTimeCatchTheBus(self, buses, passengers, capacity):\n        \"\"\"\n        :type buses: List[int]\n        :type passengers: List[int]\n        :type capacity: int\n        :rtype: int\n        \"\"\"",
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                    "code": "public class Solution {\n    public int LatestTimeCatchTheBus(int[] buses, int[] passengers, int capacity) {\n\n    }\n}",
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                    "code": "/**\n * @param {number[]} buses\n * @param {number[]} passengers\n * @param {number} capacity\n * @return {number}\n */\nvar latestTimeCatchTheBus = function(buses, passengers, capacity) {\n\n};",
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                    "code": "class Solution {\n\n    /**\n     * @param Integer[] $buses\n     * @param Integer[] $passengers\n     * @param Integer $capacity\n     * @return Integer\n     */\n    function latestTimeCatchTheBus($buses, $passengers, $capacity) {\n\n    }\n}",
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                    "code": "class Solution {\n    func latestTimeCatchTheBus(_ buses: [Int], _ passengers: [Int], _ capacity: Int) -> Int {\n\n    }\n}",
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                    "code": "class Solution {\n    fun latestTimeCatchTheBus(buses: IntArray, passengers: IntArray, capacity: Int): Int {\n\n    }\n}",
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                "Sort the buses and passengers arrays.",
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