You are given a 0-indexed integer array buses of length n, where buses[i] represents the departure time of the ith bus. You are also given a 0-indexed integer array passengers of length m, where passengers[j] represents the arrival time of the jth passenger. All bus departure times are unique. All passenger arrival times are unique.
You are given an integer capacity, which represents the maximum number of passengers that can get on each bus.
When a passenger arrives, they will wait in line for the next available bus. You can get on a bus that departs at x minutes if you arrive at y minutes where y <= x, and the bus is not full. Passengers with the earliest arrival times get on the bus first.
More formally when a bus arrives, either:
\n\ncapacity or fewer passengers are waiting for a bus, they will all get on the bus, orcapacity passengers with the earliest arrival times will get on the bus.Return the latest time you may arrive at the bus station to catch a bus. You cannot arrive at the same time as another passenger.
\n\nNote: The arrays buses and passengers are not necessarily sorted.
\n
Example 1:
\n\n\nInput: buses = [10,20], passengers = [2,17,18,19], capacity = 2\nOutput: 16\nExplanation: Suppose you arrive at time 16.\nAt time 10, the first bus departs with the 0th passenger. \nAt time 20, the second bus departs with you and the 1st passenger.\nNote that you may not arrive at the same time as another passenger, which is why you must arrive before the 1st passenger to catch the bus.\n\n
Example 2:
\n\n\nInput: buses = [20,30,10], passengers = [19,13,26,4,25,11,21], capacity = 2\nOutput: 20\nExplanation: Suppose you arrive at time 20.\nAt time 10, the first bus departs with the 3rd passenger. \nAt time 20, the second bus departs with the 5th and 1st passengers.\nAt time 30, the third bus departs with the 0th passenger and you.\nNotice if you had arrived any later, then the 6th passenger would have taken your seat on the third bus.\n\n
\n
Constraints:
\n\nn == buses.lengthm == passengers.length1 <= n, m, capacity <= 1052 <= buses[i], passengers[i] <= 109buses is unique.passengers is unique.给你一个下标从 0 开始长度为 n 的整数数组 buses ，其中 buses[i] 表示第 i 辆公交车的出发时间。同时给你一个下标从 0 开始长度为 m 的整数数组 passengers ，其中 passengers[j] 表示第 j 位乘客的到达时间。所有公交车出发的时间互不相同，所有乘客到达的时间也互不相同。
给你一个整数 capacity ，表示每辆公交车 最多 能容纳的乘客数目。
每位乘客都会搭乘下一辆有座位的公交车。如果你在 y 时刻到达，公交在 x 时刻出发，满足 y <= x 且公交没有满，那么你可以搭乘这一辆公交。最早 到达的乘客优先上车。
返回你可以搭乘公交车的最晚到达公交站时间。你 不能 跟别的乘客同时刻到达。
\n\n注意：数组 buses 和 passengers 不一定是有序的。
\n\n
示例 1：
\n\n输入：buses = [10,20], passengers = [2,17,18,19], capacity = 2\n输出：16\n解释：\n第 1 辆公交车载着第 1 位乘客。\n第 2 辆公交车载着你和第 2 位乘客。\n注意你不能跟其他乘客同一时间到达，所以你必须在第二位乘客之前到达。\n\n
示例 2：
\n\n输入：buses = [20,30,10], passengers = [19,13,26,4,25,11,21], capacity = 2\n输出：20\n解释：\n第 1 辆公交车载着第 4 位乘客。\n第 2 辆公交车载着第 6 位和第 2 位乘客。\n第 3 辆公交车载着第 1 位乘客和你。\n\n\n
\n\n
提示：
\n\nn == buses.lengthm == passengers.length1 <= n, m, capacity <= 1052 <= buses[i], passengers[i] <= 109buses 中的元素 互不相同 。passengers 中的元素 互不相同 。\\u7248\\u672c\\uff1a \\u7f16\\u8bd1\\u65f6\\uff0c\\u5c06\\u4f1a\\u91c7\\u7528 \\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\"],\"java\":[\"Java\",\" \\u7248\\u672c\\uff1a \\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u88ab\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u5305\\u542b Pair \\u7c7b: https:\\/\\/docs.oracle.com\\/javase\\/8\\/javafx\\/api\\/javafx\\/util\\/Pair.html <\\/p>\"],\"python\":[\"Python\",\" \\u7248\\u672c\\uff1a \\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982\\uff1aarray<\\/a>, bisect<\\/a>, 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