leetcode-problemset/leetcode-cn/originData/queries-on-a-permutation-with-key.json

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            "title": "Queries on a Permutation With Key",
            "titleSlug": "queries-on-a-permutation-with-key",
            "content": "<p>Given the array <code>queries</code> of positive integers between <code>1</code> and <code>m</code>, you have to process all <code>queries[i]</code> (from <code>i=0</code> to <code>i=queries.length-1</code>) according to the following rules:</p>\n\n<ul>\n\t<li>In the beginning, you have the permutation <code>P=[1,2,3,...,m]</code>.</li>\n\t<li>For the current <code>i</code>, find the position of <code>queries[i]</code> in the permutation <code>P</code> (<strong>indexing from 0</strong>) and then move this at the beginning of the permutation <code>P</code>. Notice that the position of <code>queries[i]</code> in <code>P</code> is the result for <code>queries[i]</code>.</li>\n</ul>\n\n<p>Return an array containing the result for the given <code>queries</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> queries = [3,1,2,1], m = 5\n<strong>Output:</strong> [2,1,2,1] \n<strong>Explanation:</strong> The queries are processed as follow: \nFor i=0: queries[i]=3, P=[1,2,3,4,5], position of 3 in P is <strong>2</strong>, then we move 3 to the beginning of P resulting in P=[3,1,2,4,5]. \nFor i=1: queries[i]=1, P=[3,1,2,4,5], position of 1 in P is <strong>1</strong>, then we move 1 to the beginning of P resulting in P=[1,3,2,4,5]. \nFor i=2: queries[i]=2, P=[1,3,2,4,5], position of 2 in P is <strong>2</strong>, then we move 2 to the beginning of P resulting in P=[2,1,3,4,5]. \nFor i=3: queries[i]=1, P=[2,1,3,4,5], position of 1 in P is <strong>1</strong>, then we move 1 to the beginning of P resulting in P=[1,2,3,4,5]. \nTherefore, the array containing the result is [2,1,2,1].  \n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> queries = [4,1,2,2], m = 4\n<strong>Output:</strong> [3,1,2,0]\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> queries = [7,5,5,8,3], m = 8\n<strong>Output:</strong> [6,5,0,7,5]\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= m &lt;= 10^3</code></li>\n\t<li><code>1 &lt;= queries.length &lt;= m</code></li>\n\t<li><code>1 &lt;= queries[i] &lt;= m</code></li>\n</ul>\n",
            "translatedTitle": "查询带键的排列",
            "translatedContent": "<p>给定一个正整数数组&nbsp;<code>queries</code> ，其取值范围在&nbsp;<code>1</code> 到 <code>m</code> 之间。 请你根据以下规则按顺序处理所有&nbsp;<code>queries[i]</code>（从 <code>i=0</code> 到 <code>i=queries.length-1</code>）：</p>\n\n<ul>\n\t<li>首先，你有一个排列&nbsp;<code>P=[1,2,3,...,m]</code>。</li>\n\t<li>对于当前的 <code>i</code> ，找到&nbsp;<code>queries[i]</code> 在排列 <code>P</code> 中的位置（<b>从 0 开始索引</b>），然后将它移到排列&nbsp;<code>P</code> 的开头（即下标为 0 处）。注意， <code>queries[i]</code>&nbsp;的查询结果是 <code>queries[i]</code> 在 <code>P</code> 中移动前的位置。</li>\n</ul>\n\n<p>返回一个数组，包含从给定 &nbsp;<code>queries</code>&nbsp;中查询到的结果。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>queries = [3,1,2,1], m = 5\n<strong>输出：</strong>[2,1,2,1] \n<strong>解释：处理</strong> queries 的过程如下：\n对于 i=0: queries[i]=3, P=[1,2,3,4,5], 3 在 P 中的位置是 <strong>2</strong>，然后我们把 3 移动到 P 的开头，得到 P=[3,1,2,4,5] 。\n对于 i=1: queries[i]=1, P=[3,1,2,4,5], 1 在 P 中的位置是 <strong>1</strong>，然后我们把 1 移动到 P 的开头，得到 P=[1,3,2,4,5] 。 \n对于 i=2: queries[i]=2, P=[1,3,2,4,5], 2 在 P 中的位置是 <strong>2</strong>，然后我们把 2 移动到 P 的开头，得到 P=[2,1,3,4,5] 。\n对于 i=3: queries[i]=1, P=[2,1,3,4,5], 1 在 P 中的位置是 <strong>1</strong>，然后我们把 1 移动到 P 的开头，得到 P=[1,2,3,4,5] 。 \n因此，包含结果的数组为 [2,1,2,1] 。  \n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>queries = [4,1,2,2], m = 4\n<strong>输出：</strong>[3,1,2,0]\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>queries = [7,5,5,8,3], m = 8\n<strong>输出：</strong>[6,5,0,7,5]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= m &lt;= 10^3</code></li>\n\t<li><code>1 &lt;= queries.length &lt;= m</code></li>\n\t<li><code>1 &lt;= queries[i] &lt;= m</code></li>\n</ul>\n",
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