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leetcode-problemset/leetcode-cn/originData/merge-strings-alternately.json
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{
"data": {
"question": {
"questionId": "1894",
"questionFrontendId": "1768",
"categoryTitle": "Algorithms",
"boundTopicId": 609223,
"title": "Merge Strings Alternately",
"titleSlug": "merge-strings-alternately",
"content": "<p>You are given two strings <code>word1</code> and <code>word2</code>. Merge the strings by adding letters in alternating order, starting with <code>word1</code>. If a string is longer than the other, append the additional letters onto the end of the merged string.</p>\r\n\r\n<p>Return <em>the merged string.</em></p>\r\n\r\n<p>&nbsp;</p>\r\n<p><strong class=\"example\">Example 1:</strong></p>\r\n\r\n<pre>\r\n<strong>Input:</strong> word1 = &quot;abc&quot;, word2 = &quot;pqr&quot;\r\n<strong>Output:</strong> &quot;apbqcr&quot;\r\n<strong>Explanation:</strong>&nbsp;The merged string will be merged as so:\r\nword1: a b c\r\nword2: p q r\r\nmerged: a p b q c r\r\n</pre>\r\n\r\n<p><strong class=\"example\">Example 2:</strong></p>\r\n\r\n<pre>\r\n<strong>Input:</strong> word1 = &quot;ab&quot;, word2 = &quot;pqrs&quot;\r\n<strong>Output:</strong> &quot;apbqrs&quot;\r\n<strong>Explanation:</strong>&nbsp;Notice that as word2 is longer, &quot;rs&quot; is appended to the end.\r\nword1: a b \r\nword2: p q r s\r\nmerged: a p b q r s\r\n</pre>\r\n\r\n<p><strong class=\"example\">Example 3:</strong></p>\r\n\r\n<pre>\r\n<strong>Input:</strong> word1 = &quot;abcd&quot;, word2 = &quot;pq&quot;\r\n<strong>Output:</strong> &quot;apbqcd&quot;\r\n<strong>Explanation:</strong>&nbsp;Notice that as word1 is longer, &quot;cd&quot; is appended to the end.\r\nword1: a b c d\r\nword2: p q \r\nmerged: a p b q c d\r\n</pre>\r\n\r\n<p>&nbsp;</p>\r\n<p><strong>Constraints:</strong></p>\r\n\r\n<ul>\r\n\t<li><code>1 &lt;= word1.length, word2.length &lt;= 100</code></li>\r\n\t<li><code>word1</code> and <code>word2</code> consist of lowercase English letters.</li>\r\n</ul>",
"translatedTitle": "交替合并字符串",
"translatedContent": "<p>给你两个字符串 <code>word1</code> 和 <code>word2</code> 。请你从 <code>word1</code> 开始,通过交替添加字母来合并字符串。如果一个字符串比另一个字符串长,就将多出来的字母追加到合并后字符串的末尾。</p>\n\n<p>返回 <strong>合并后的字符串</strong> 。</p>\n\n<p> </p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<strong>输入:</strong>word1 = \"abc\", word2 = \"pqr\"\n<strong>输出:</strong>\"apbqcr\"\n<strong>解释:</strong>字符串合并情况如下所示:\nword1 a b c\nword2 p q r\n合并后 a p b q c r\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>word1 = \"ab\", word2 = \"pqrs\"\n<strong>输出:</strong>\"apbqrs\"\n<strong>解释:</strong>注意word2 比 word1 长,\"rs\" 需要追加到合并后字符串的末尾。\nword1 a b \nword2 p q r s\n合并后 a p b q r s\n</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre>\n<strong>输入:</strong>word1 = \"abcd\", word2 = \"pq\"\n<strong>输出:</strong>\"apbqcd\"\n<strong>解释:</strong>注意word1 比 word2 长,\"cd\" 需要追加到合并后字符串的末尾。\nword1 a b c d\nword2 p q \n合并后 a p b q c d\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= word1.length, word2.length <= 100</code></li>\n\t<li><code>word1</code> 和 <code>word2</code> 由小写英文字母组成</li>\n</ul>\n",
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"code": "class Solution {\npublic:\n string mergeAlternately(string word1, string word2) {\n\n }\n};",
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"code": "class Solution(object):\n def mergeAlternately(self, word1, word2):\n \"\"\"\n :type word1: str\n :type word2: str\n :rtype: str\n \"\"\"",
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"code": "/**\n * @param {string} word1\n * @param {string} word2\n * @return {string}\n */\nvar mergeAlternately = function(word1, word2) {\n\n};",
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"code": "class Solution {\n\n /**\n * @param String $word1\n * @param String $word2\n * @return String\n */\n function mergeAlternately($word1, $word2) {\n\n }\n}",
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"lang": "Erlang",
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"code": "-spec merge_alternately(Word1 :: unicode:unicode_binary(), Word2 :: unicode:unicode_binary()) -> unicode:unicode_binary().\nmerge_alternately(Word1, Word2) ->\n .",
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"code": "defmodule Solution do\n @spec merge_alternately(word1 :: String.t, word2 :: String.t) :: String.t\n def merge_alternately(word1, word2) do\n\n end\nend",
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"hints": [
"Use two pointers, one pointer for each string. Alternately choose the character from each pointer, and move the pointer upwards."
],
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"sampleTestCase": "\"abc\"\n\"pqr\"",
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