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            "questionId": "1894",
            "questionFrontendId": "1768",
            "categoryTitle": "Algorithms",
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            "title": "Merge Strings Alternately",
            "titleSlug": "merge-strings-alternately",
            "content": "<p>You are given two strings <code>word1</code> and <code>word2</code>. Merge the strings by adding letters in alternating order, starting with <code>word1</code>. If a string is longer than the other, append the additional letters onto the end of the merged string.</p>\r\n\r\n<p>Return <em>the merged string.</em></p>\r\n\r\n<p>&nbsp;</p>\r\n<p><strong class=\"example\">Example 1:</strong></p>\r\n\r\n<pre>\r\n<strong>Input:</strong> word1 = &quot;abc&quot;, word2 = &quot;pqr&quot;\r\n<strong>Output:</strong> &quot;apbqcr&quot;\r\n<strong>Explanation:</strong>&nbsp;The merged string will be merged as so:\r\nword1:  a   b   c\r\nword2:    p   q   r\r\nmerged: a p b q c r\r\n</pre>\r\n\r\n<p><strong class=\"example\">Example 2:</strong></p>\r\n\r\n<pre>\r\n<strong>Input:</strong> word1 = &quot;ab&quot;, word2 = &quot;pqrs&quot;\r\n<strong>Output:</strong> &quot;apbqrs&quot;\r\n<strong>Explanation:</strong>&nbsp;Notice that as word2 is longer, &quot;rs&quot; is appended to the end.\r\nword1:  a   b \r\nword2:    p   q   r   s\r\nmerged: a p b q   r   s\r\n</pre>\r\n\r\n<p><strong class=\"example\">Example 3:</strong></p>\r\n\r\n<pre>\r\n<strong>Input:</strong> word1 = &quot;abcd&quot;, word2 = &quot;pq&quot;\r\n<strong>Output:</strong> &quot;apbqcd&quot;\r\n<strong>Explanation:</strong>&nbsp;Notice that as word1 is longer, &quot;cd&quot; is appended to the end.\r\nword1:  a   b   c   d\r\nword2:    p   q \r\nmerged: a p b q c   d\r\n</pre>\r\n\r\n<p>&nbsp;</p>\r\n<p><strong>Constraints:</strong></p>\r\n\r\n<ul>\r\n\t<li><code>1 &lt;= word1.length, word2.length &lt;= 100</code></li>\r\n\t<li><code>word1</code> and <code>word2</code> consist of lowercase English letters.</li>\r\n</ul>",
            "translatedTitle": "交替合并字符串",
            "translatedContent": "<p>给你两个字符串 <code>word1</code> 和 <code>word2</code> 。请你从 <code>word1</code> 开始，通过交替添加字母来合并字符串。如果一个字符串比另一个字符串长，就将多出来的字母追加到合并后字符串的末尾。</p>\n\n<p>返回 <strong>合并后的字符串</strong> 。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>word1 = \"abc\", word2 = \"pqr\"\n<strong>输出：</strong>\"apbqcr\"\n<strong>解释：</strong>字符串合并情况如下所示：\nword1：  a   b   c\nword2：    p   q   r\n合并后：  a p b q c r\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>word1 = \"ab\", word2 = \"pqrs\"\n<strong>输出：</strong>\"apbqrs\"\n<strong>解释：</strong>注意，word2 比 word1 长，\"rs\" 需要追加到合并后字符串的末尾。\nword1：  a   b \nword2：    p   q   r   s\n合并后：  a p b q   r   s\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>word1 = \"abcd\", word2 = \"pq\"\n<strong>输出：</strong>\"apbqcd\"\n<strong>解释：</strong>注意，word1 比 word2 长，\"cd\" 需要追加到合并后字符串的末尾。\nword1：  a   b   c   d\nword2：    p   q \n合并后：  a p b q c   d\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= word1.length, word2.length <= 100</code></li>\n\t<li><code>word1</code> 和 <code>word2</code> 由小写英文字母组成</li>\n</ul>\n",
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                    "lang": "C++",
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                    "code": "class Solution {\npublic:\n    string mergeAlternately(string word1, string word2) {\n\n    }\n};",
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                    "code": "class Solution {\n    public String mergeAlternately(String word1, String word2) {\n\n    }\n}",
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                    "code": "class Solution(object):\n    def mergeAlternately(self, word1, word2):\n        \"\"\"\n        :type word1: str\n        :type word2: str\n        :rtype: str\n        \"\"\"",
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                    "code": "/**\n * @param {string} word1\n * @param {string} word2\n * @return {string}\n */\nvar mergeAlternately = function(word1, word2) {\n\n};",
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                    "code": "class Solution {\n\n    /**\n     * @param String $word1\n     * @param String $word2\n     * @return String\n     */\n    function mergeAlternately($word1, $word2) {\n\n    }\n}",
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                    "code": "class Solution {\n    func mergeAlternately(_ word1: String, _ word2: String) -> String {\n\n    }\n}",
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                    "code": "class Solution {\n    fun mergeAlternately(word1: String, word2: String): String {\n\n    }\n}",
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                    "code": "# @param {String} word1\n# @param {String} word2\n# @return {String}\ndef merge_alternately(word1, word2)\n\nend",
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                    "code": "-spec merge_alternately(Word1 :: unicode:unicode_binary(), Word2 :: unicode:unicode_binary()) -> unicode:unicode_binary().\nmerge_alternately(Word1, Word2) ->\n  .",
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                    "code": "defmodule Solution do\n  @spec merge_alternately(word1 :: String.t, word2 :: String.t) :: String.t\n  def merge_alternately(word1, word2) do\n\n  end\nend",
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                "Use two pointers, one pointer for each string. Alternately choose the character from each pointer, and move the pointer upwards."
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