1
0
mirror of https://gitee.com/coder-xiaomo/leetcode-problemset synced 2025-09-10 01:41:41 +08:00
Code Issues Projects Releases Wiki Activity GitHub Gitee
Files
leetcode-problemset/leetcode-cn/problem (Chinese)/统计特殊三元组 [count-special-triplets].html
2025-06-18 01:10:28 +08:00

91 lines
2.7 KiB
HTML
Raw Permalink Blame History

This file contains ambiguous Unicode characters

This file contains Unicode characters that might be confused with other characters. If you think that this is intentional, you can safely ignore this warning. Use the Escape button to reveal them.

<p>给你一个整数数组 <code>nums</code></p>
<p><strong>特殊三元组 </strong>定义为满足以下条件的下标三元组 <code>(i, j, k)</code></p>
<ul>
<li><code>0 &lt;= i &lt; j &lt; k &lt; n</code>,其中 <code>n = nums.length</code></li>
<li><code>nums[i] == nums[j] * 2</code></li>
<li><code>nums[k] == nums[j] * 2</code></li>
</ul>
<p>返回数组中&nbsp;<strong>特殊三元组&nbsp;</strong>的总数。</p>
<p>由于答案可能非常大,请返回结果对 <code>10<sup>9</sup> + 7</code> 取余数后的值。</p>
<p>&nbsp;</p>
<p><strong class="example">示例 1</strong></p>
<div class="example-block">
<p><strong>输入:</strong> <span class="example-io">nums = [6,3,6]</span></p>
<p><strong>输出:</strong> <span class="example-io">1</span></p>
<p><strong>解释:</strong></p>
<p>唯一的特殊三元组是 <code>(i, j, k) = (0, 1, 2)</code>,其中:</p>
<ul>
<li><code>nums[0] = 6</code>, <code>nums[1] = 3</code>, <code>nums[2] = 6</code></li>
<li><code>nums[0] = nums[1] * 2 = 3 * 2 = 6</code></li>
<li><code>nums[2] = nums[1] * 2 = 3 * 2 = 6</code></li>
</ul>
</div>
<p><strong class="example">示例 2</strong></p>
<div class="example-block">
<p><strong>输入:</strong> <span class="example-io">nums = [0,1,0,0]</span></p>
<p><strong>输出:</strong> <span class="example-io">1</span></p>
<p><strong>解释:</strong></p>
<p>唯一的特殊三元组是 <code>(i, j, k) = (0, 2, 3)</code>,其中:</p>
<ul>
<li><code>nums[0] = 0</code>, <code>nums[2] = 0</code>, <code>nums[3] = 0</code></li>
<li><code>nums[0] = nums[2] * 2 = 0 * 2 = 0</code></li>
<li><code>nums[3] = nums[2] * 2 = 0 * 2 = 0</code></li>
</ul>
</div>
<p><strong class="example">示例 3</strong></p>
<div class="example-block">
<p><strong>输入:</strong> <span class="example-io">nums = [8,4,2,8,4]</span></p>
<p><strong>输出:</strong> <span class="example-io">2</span></p>
<p><strong>解释:</strong></p>
<p>共有两个特殊三元组:</p>
<ul>
<li><code>(i, j, k) = (0, 1, 3)</code>
<ul>
<li><code>nums[0] = 8</code>, <code>nums[1] = 4</code>, <code>nums[3] = 8</code></li>
<li><code>nums[0] = nums[1] * 2 = 4 * 2 = 8</code></li>
<li><code>nums[3] = nums[1] * 2 = 4 * 2 = 8</code></li>
</ul>
</li>
<li><code>(i, j, k) = (1, 2, 4)</code>
<ul>
<li><code>nums[1] = 4</code>, <code>nums[2] = 2</code>, <code>nums[4] = 4</code></li>
<li><code>nums[1] = nums[2] * 2 = 2 * 2 = 4</code></li>
<li><code>nums[4] = nums[2] * 2 = 2 * 2 = 4</code></li>
</ul>
</li>
</ul>
</div>
<p>&nbsp;</p>
<p><strong>提示:</strong></p>
<ul>
<li><code>3 &lt;= n == nums.length &lt;= 10<sup>5</sup></code></li>
<li><code>0 &lt;= nums[i] &lt;= 10<sup>5</sup></code></li>
</ul>