leetcode-problemset/leetcode-cn/originData/minimum-adjacent-swaps-to-alternate-parity.json

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            "title": "Minimum Adjacent Swaps to Alternate Parity",
            "titleSlug": "minimum-adjacent-swaps-to-alternate-parity",
            "content": "<p>You are given an array <code>nums</code> of <strong>distinct</strong> integers.</p>\n\n<p>In one operation, you can swap any two <strong>adjacent</strong> elements in the array.</p>\n\n<p>An arrangement of the array is considered <strong>valid</strong> if the parity of adjacent elements <strong>alternates</strong>, meaning every pair of neighboring elements consists of one even and one odd number.</p>\n\n<p>Return the <strong>minimum</strong> number of adjacent swaps required to transform <code>nums</code> into any valid arrangement.</p>\n\n<p>If it is impossible to rearrange <code>nums</code> such that no two adjacent elements have the same parity, return <code>-1</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [2,4,6,5,7]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">3</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>Swapping 5 and 6, the array becomes <code>[2,4,5,6,7]</code></p>\n\n<p>Swapping 5 and 4, the array becomes <code>[2,5,4,6,7]</code></p>\n\n<p>Swapping 6 and 7, the array becomes <code>[2,5,4,7,6]</code>. The array is now a valid arrangement. Thus, the answer is 3.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [2,4,5,7]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">1</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>By swapping 4 and 5, the array becomes <code>[2,5,4,7]</code>, which is a valid arrangement. Thus, the answer is 1.</p>\n</div>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [1,2,3]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">0</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>The array is already a valid arrangement. Thus, no operations are needed.</p>\n</div>\n\n<p><strong class=\"example\">Example 4:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [4,5,6,8]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">-1</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>No valid arrangement is possible. Thus, the answer is -1.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n\t<li>All elements in <code>nums</code> are <strong>distinct</strong>.</li>\n</ul>\n",
            "translatedTitle": "最小相邻交换至奇偶交替",
            "translatedContent": "<p>给你一个由互不相同的整数组成的数组 <code>nums</code>&nbsp;。</p>\n\n<p>在一次操作中，你可以交换任意两个&nbsp;<strong>相邻&nbsp;</strong>元素。</p>\n\n<p>在一个排列中，当所有相邻元素的奇偶性交替出现，我们认为该排列是 <strong>有效排列</strong>。这意味着每对相邻元素中一个是偶数，一个是奇数。</p>\n\n<p>请返回将 <code>nums</code> 变成任意一种&nbsp;<strong>有效排列</strong>&nbsp;所需的最小相邻交换次数。</p>\n\n<p>如果无法重排 <code>nums</code> 来获得有效排列，则返回 <code>-1</code>。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">nums = [2,4,6,5,7]</span></p>\n\n<p><span class=\"example-io\"><b>输出：</b>3</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>将 5 和 6 交换，数组变成&nbsp; <code>[2,4,5,6,7]</code></p>\n\n<p>将 5 和 4&nbsp;交换，数组变成&nbsp; <code>[2,5,4,6,7]</code></p>\n\n<p>将 6&nbsp;和 7&nbsp;交换，数组变成&nbsp;&nbsp;<code>[2,5,4,7,6]</code>。此时是一个有效排列。因此答案是 3。</p>\n</div>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">nums = [2,4,5,7]</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">1</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>将 4&nbsp;和 5&nbsp;交换，数组变成 <code>[2,5,4,7]</code>。此时是一个有效排列。因此答案是 1。</p>\n</div>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">nums = [1,2,3]</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">0</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>数组已经是有效排列，因此不需要任何操作。</p>\n</div>\n\n<p><strong class=\"example\">示例 4：</strong></p>\n\n<div class=\"example-block\">\n<p><b>输入：</b>&nbsp;<span class=\"example-io\">nums = [4,5,6,8]</span></p>\n\n<p><span class=\"example-io\"><b>输出：</b>-1</span></p>\n\n<p><b>解释：</b></p>\n\n<p>没有任何一种排列可以满足奇偶交替的要求，因此返回 -1。</p>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>nums</code>&nbsp;中的所有元素都是 <strong>唯一</strong> 的</li>\n</ul>\n",
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                "Compute <code>evenCnt</code> and <code>oddCnt</code> in <code>nums</code>. If abs(evenCnt - oddCnt) > 1, return -1 immediately.",
                "Let <code>n</code> = len(nums). You’ll try at most two target parity‐patterns: one starting with even at index 0, one with odd at index 0.",
                "If <code>n</code> is odd, only the pattern whose starting parity matches the larger of <code>evenCnt</code> or <code>oddCnt</code> is feasible. If <code>n</code> is even, both starting‐even and starting‐odd patterns are possible—compute both and take the minimum.",
                "For a given target pattern, collect the indices of all even elements in <code>nums</code> (or odd elements) and the indices where an even (or odd) should go in the pattern.",
                "The minimum adjacent‐swap cost to align those elements is the sum of absolute differences between each element’s current index and its target index.",
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